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JAMB UTME - Chemistry - 1985

Question 1 Report

A certain volume of gas at 298k is heated such that its volume and pressure are now four times the original values. What is the new temperature?
Answer Details
P 1 V 1 T 1 = 4 P 1 × 4 V 1 T 2

i.e  P 1 V 1 298 = 4 P 1 × 4 V 1 T 2

T2 =  298 × 4 P 1 × 4 V 1 P 1 V 1

= 298 + 16 = 4768.0k