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Tambaya 1 Rahoto
Consider the reaction represented by the following equation: N2(g) + 3H2(g) ⇌ 2NH3(g); ∆Hϴ = -xkJ mol-1. Which of the following conditions would increase the yield of NH3?
Tambaya 2 Rahoto
Which of the following transition metals is not attracted to external magnetic field?
Tambaya 3 Rahoto
NH4- is formed from NH3 and H- by
Tambaya 4 Rahoto
Which of the following factors would affect the equilibrium constant?
Bayanin Amsa
The equilibrium constant (K) is a value that indicates the extent of a chemical reaction at equilibrium. It is determined by the concentrations of the reactants and products at equilibrium, and is unaffected by any external factors such as the initial concentrations or the rate of the reaction. However, the equilibrium constant is affected by changes in temperature. When the temperature of a system at equilibrium is changed, the equilibrium constant will also change. This is because the forward and reverse reactions of a chemical reaction are affected differently by changes in temperature, which alters the equilibrium position. Similarly, changes in pressure or volume of a system at equilibrium can also affect the equilibrium constant. For example, an increase in pressure will cause the equilibrium to shift towards the side with fewer moles of gas, while a decrease in volume will have the same effect. These changes in the equilibrium position will alter the concentrations of the reactants and products, and hence change the equilibrium constant. Overall, concentration alone cannot affect the equilibrium constant as it is determined by the concentrations of the reactants and products at equilibrium, and is not dependent on the initial concentrations. However, changes in temperature, pressure, or volume can affect the equilibrium constant by altering the equilibrium position of the chemical reaction.
Tambaya 5 Rahoto
The enzyme that catalyses the conversion of glucose te ethanol and carbon (IV) oxide is
Bayanin Amsa
The enzyme that catalyzes the conversion of glucose to ethanol and carbon dioxide is called zymase. Zymase is a complex of enzymes that are found in yeast cells and are involved in the fermentation of glucose into ethanol and carbon dioxide. The process of fermentation involves the breakdown of glucose into pyruvate, which is then converted into ethanol and carbon dioxide by the action of zymase. During the fermentation process, zymase catalyzes two important reactions: the conversion of glucose to pyruvate by the action of the enzyme hexokinase, and the conversion of pyruvate to ethanol and carbon dioxide by the action of the enzymes pyruvate decarboxylase and alcohol dehydrogenase. Therefore, the correct option is "zymase" because it is the enzyme complex that is responsible for the conversion of glucose to ethanol and carbon dioxide. The other options are incorrect because diastase and maltase are enzymes involved in the breakdown of carbohydrates into simpler sugars, while ptyalin is an enzyme found in saliva that helps to break down starch into maltose.
Tambaya 6 Rahoto
The purity of a solid sample can best be determined by its?
Bayanin Amsa
The purity of a solid sample can best be determined by its melting point. Melting point is defined as the temperature at which a solid substance melts to become a liquid. Pure substances have a fixed melting point, which means that they melt at a specific temperature under a given pressure. Impurities in a solid sample can lower the melting point and cause it to melt over a range of temperatures instead of at a fixed temperature. Therefore, by measuring the melting point of a solid sample, we can determine its purity. If the sample has a narrow melting point range, it is likely to be pure. If the sample has a wide melting point range or melts over a range of temperatures, it is likely to be impure. In summary, the purity of a solid sample can be best determined by its melting point because pure substances have a fixed melting point, whereas impurities lower the melting point and cause the sample to melt over a range of temperatures.
Tambaya 7 Rahoto
Consider the reaction represented by the following equation: C2H4(g)
+ 302(g) → 2CO2(g) + 2H2O(g)How many moles of ethene would be burnt to produce 0.1 mole of water?
Tambaya 8 Rahoto
The shape of CH4 is
Bayanin Amsa
The shape of CH4 is tetrahedral. This is because the carbon atom is surrounded by four hydrogen atoms, and the molecule has a symmetrical arrangement, with the hydrogen atoms forming the corners of a tetrahedron around the carbon atom. The bond angles between the hydrogen atoms in the CH4 molecule are 109.5 degrees, which is characteristic of a tetrahedral shape.
Tambaya 9 Rahoto
If 0.20 mol dm-3 NaOH(aq) was evaporated to yield 5.0g of solid NaOH, calculate the volume of NaOH (aq) used. (Na = 23.0,O = 16:0; H = 1.00)
Bayanin Amsa
To calculate the volume of NaOH (aq) used, we need to use the formula: moles of solute = mass of solute / molar mass of solute First, we need to find the number of moles of NaOH used to produce the 5.0 g of solid NaOH. Molar mass of NaOH = 23.0 + 16.0 + 1.0 = 40.0 g/mol Number of moles of NaOH = mass of NaOH / molar mass of NaOH = 5.0 g / 40.0 g/mol = 0.125 mol Now, we can use the formula for concentration to find the volume of NaOH (aq) used. Concentration of NaOH (aq) = 0.20 mol/dm³ Number of moles of NaOH (aq) = concentration × volume 0.125 mol = 0.20 mol/dm³ × volume Rearranging the equation to isolate the volume: volume = number of moles / concentration volume = 0.125 mol / 0.20 mol/dm³ volume = 0.625 dm³ Converting dm³ to cm³ by multiplying by 1000: volume = 0.625 dm³ × 1000 cm³/dm³ volume = 625 cm³ Therefore, the volume of NaOH (aq) used is 625 cm³. The correct option is (B).
Tambaya 11 Rahoto
Which of the following arrangements is in decreasing order of atomic radius?
Tambaya 12 Rahoto
Which of the following compounds determines the octane rating of petrol?
Bayanin Amsa
The compound that determines the octane rating of petrol is 2,2,4-trimethylpentane, also known as iso-octane. Octane rating is a measure of a fuel's ability to resist "knocking" or detonation that can occur inside an engine, causing damage and reducing efficiency. Iso-octane has a high resistance to knocking, which makes it an ideal reference standard for determining the octane rating of petrol. A fuel with a higher percentage of iso-octane will have a higher octane rating and will be less likely to cause knocking in an engine.
Tambaya 13 Rahoto
Ethene molecules can be added to one another to form a long chain compound called a
Bayanin Amsa
Ethene is a molecule that consists of two carbon atoms and four hydrogen atoms. The carbon atoms in ethene each have one unpaired electron, which they can use to form a covalent bond with another carbon atom. When many ethene molecules are added together, the carbon atoms can bond with each other to form a long chain of carbon atoms, with hydrogen atoms attached to each carbon atom. This chain of repeating units is called a polymer. The process of adding ethene molecules to each other to form a polymer is called polymerization. In this process, the double bond between the carbon atoms in ethene is broken, and the carbon atoms can bond with each other and with other molecules to form a long chain. Therefore, the correct answer is polymer, as ethene molecules can be added to each other to form a long chain polymer.
Tambaya 14 Rahoto
The two elements 11X and 19Y are in the same group because they have the same
Bayanin Amsa
The two elements 11X and 19Y are in the same group because they have the same number of valence electrons. The elements in the same group of the periodic table have similar chemical and physical properties, and this is largely due to the fact that they have the same number of valence electrons in their outermost energy level. Valence electrons are the electrons in the outermost energy level of an atom that are involved in chemical bonding with other atoms. Elements in the same group have the same number of valence electrons, which gives them similar reactivity and bonding patterns. In this case, both 11X and 19Y have the same number of valence electrons, which means that they belong to the same group of the periodic table.
Tambaya 15 Rahoto
A gaseous mixture contains 0,256 g of hydrogen and 2.00 g of oxygen. The mole ration of hydrogen to oxygen in the mixture is (H=1.00; O=16,0)
Tambaya 16 Rahoto
Zinc oxide is said to be amphoteric because it
Bayanin Amsa
Zinc oxide (ZnO) is called amphoteric because it can react as both an acid and a base. When it reacts with a strong acid, it behaves like a base and neutralizes the acid to form a salt and water. On the other hand, when it reacts with a strong base, it behaves like an acid and neutralizes the base to form a salt and water. This property of zinc oxide makes it useful in a variety of industrial and chemical processes.
Tambaya 17 Rahoto
A colourless hydrocarbon with a sweet smell undergoes substitution reaction. The hydrocarbon is likely to be
Tambaya 18 Rahoto
The gases produced when Cu(NO3)2(s) was heated are
Tambaya 19 Rahoto
An atom W has 17 electrons and 18 neutrons. Which of the following representations of the atom is correct?
Bayanin Amsa
The atomic number of an element is the number of protons in the nucleus of an atom of that element. Since the atom W has 17 electrons, it must also have 17 protons to balance the electrical charge. Therefore, its atomic number is 17. The atomic mass number of an atom is the sum of the number of protons and neutrons in its nucleus. We are told that atom W has 18 neutrons, so its atomic mass number is 17 + 18 = 35. Therefore, the correct representation of the atom W is 3517W, where the superscript indicates the atomic mass number and the subscript indicates the atomic number.
Tambaya 20 Rahoto
The oxide from electric power station is
Tambaya 21 Rahoto
Which of the following statements about volatile liquids is correct? They have
Bayanin Amsa
Volatile liquids are substances that have a tendency to evaporate easily at room temperature. This is because the molecules of volatile liquids have weak intermolecular forces, which allow them to escape easily from the surface of the liquid and form a gas. The vapour pressure of a liquid is a measure of the tendency of its molecules to escape into the gas phase. Volatile liquids have a high vapour pressure because a large number of their molecules can escape from the surface of the liquid and enter the gas phase, even at relatively low temperatures. The boiling point of a liquid is the temperature at which its vapour pressure becomes equal to the external pressure on the liquid. At this temperature, the molecules of the liquid have enough energy to overcome the intermolecular forces holding them together and escape into the gas phase. Therefore, the correct statement about volatile liquids is that they have a high vapour pressure and a low boiling point. This is because they can easily form a gas at room temperature due to their weak intermolecular forces, and their vapour pressure is high because a large number of their molecules can escape from the surface of the liquid. In addition, their low boiling point indicates that they can boil at a relatively low temperature, as their vapour pressure is already high at lower temperatures. The other options are not correct because they describe properties that are not characteristic of volatile liquids. Volatile liquids do not have a low vapour pressure or a high boiling point, as they can easily form a gas at low temperatures and boil at relatively low temperatures.
Tambaya 22 Rahoto
Which of the following substances with the corresponding pH value is an alkali?
Substance pH
Bayanin Amsa
Milk of magnesia with a pH value of 10.5 is an alkali. Alkalis are substances that have pH values greater than 7.0. The higher the pH value, the more alkaline the substance is. In this case, the substance with the highest pH value among the given options is Milk of magnesia, with a pH of 10.5. Therefore, it is the alkali among the given substances.
Tambaya 23 Rahoto
The mass of 800cm3 of gas Q at s.t.p. is 1.0g. What is the molar mass of Q? [Avogadros constant = 22.4dm3 mol-1`]
Tambaya 24 Rahoto
How many lone pair (s) of electrons is present in HF?
Tambaya 25 Rahoto
The liquid hydrocarbon likely to be found in the fraction of crude oil used for domestic cooking is
Bayanin Amsa
The liquid hydrocarbon likely to be found in the fraction of crude oil used for domestic cooking is C5H12, which is also known as Pentane. Crude oil is a complex mixture of hydrocarbons of varying lengths and structures. These hydrocarbons are separated into different fractions based on their boiling points, using a process called fractional distillation. The fraction of crude oil used for domestic cooking is commonly known as cooking gas or liquefied petroleum gas (LPG). Pentane is a colorless and odorless liquid hydrocarbon that is commonly found in the LPG fraction of crude oil. It has a boiling point of approximately 36°C and is highly volatile, which makes it suitable for use as a fuel for domestic cooking. Pentane is often mixed with other hydrocarbons such as butane and propane to create a more stable and efficient fuel for cooking. In summary, the liquid hydrocarbon likely to be found in the fraction of crude oil used for domestic cooking is C5H12, which is pentane.
Tambaya 26 Rahoto
The reaction that occurs all the anode when CuSO4(aq) is electrolyzed using carbon electrode is
Bayanin Amsa
Tambaya 27 Rahoto
The vapour pressure of a given volume of liquid increase when the
Bayanin Amsa
The vapour pressure of a given volume of liquid increases when the temperature of the liquid rises. Vapor pressure is the pressure exerted by the gas molecules that are in equilibrium with the liquid phase of a substance. In simple terms, it is the pressure created by the gas molecules that escape from the surface of a liquid. The amount of vapor pressure that a liquid can exert is directly related to its temperature. As the temperature of a liquid increases, the average kinetic energy of the molecules in the liquid also increases. This increase in kinetic energy allows more molecules to escape from the surface of the liquid, leading to an increase in the number of gas molecules in the vapor phase. Consequently, the vapor pressure of the liquid increases. On the other hand, when the temperature of the liquid falls, the average kinetic energy of the molecules in the liquid decreases. As a result, fewer molecules escape from the surface of the liquid, leading to a decrease in the number of gas molecules in the vapor phase. This results in a decrease in the vapor pressure of the liquid. Therefore, the correct option is "temperature of the liquid rises" since it results in an increase in the vapor pressure of the liquid. The other options are incorrect because the volume of the liquid and its saturation with a salt have no significant effect on the vapor pressure of the liquid, while a decrease in temperature would lead to a decrease in the vapor pressure of the liquid.
Tambaya 29 Rahoto
Consider the reaction represented by the following equation: Na2CO3(aq) + 2HCl(aq) \(\longrightarrow\) 2NaCl(aq) + H2O(l) + CO2(g) . What volume of 0.02 mol dm-3 Na2CO3(aq) would be required to completely neutralize 40 cm3 of 0.10 mol dm-3 HCl(aq)?
Bayanin Amsa
The balanced chemical equation for the reaction between Na2CO3(aq) and HCl(aq) is: Na2CO3(aq) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g) From the equation, we can see that 1 mole of Na2CO3(aq) reacts with 2 moles of HCl(aq) to produce 2 moles of NaCl(aq), 1 mole of H2O(l), and 1 mole of CO2(g). Therefore, the number of moles of HCl(aq) that reacted can be calculated as: number of moles = concentration x volume number of moles = 0.10 mol dm-3 x 0.040 dm3 number of moles = 0.004 mol From the balanced equation, we know that 1 mole of Na2CO3(aq) reacts with 2 moles of HCl(aq). Therefore, the number of moles of Na2CO3(aq) required to completely neutralize the HCl(aq) can be calculated as: number of moles = 0.5 x number of moles of HCl(aq) number of moles = 0.5 x 0.004 number of moles = 0.002 Finally, we can use the concentration and number of moles to calculate the required volume of Na2CO3(aq) as: volume = number of moles / concentration volume = 0.002 mol / 0.02 mol dm-3 volume = 0.1 dm3 = 100 cm3 Therefore, the correct answer is 100 cm3.
Tambaya 30 Rahoto
Which of the following statements about a chemical system in equilibrium is correct/ The
Bayanin Amsa
The correct statement about a chemical system in equilibrium is that "equilibrium is re-established when a stress is applied." Chemical equilibrium is a state where the forward and backward reactions occur at equal rates, resulting in no net change in the concentration of reactants or products. It is a dynamic state where the system appears to be static because the rates of forward and backward reactions are equal. However, a system in equilibrium is not unchangeable and can be disturbed by changes in concentration, pressure, or temperature. Such changes are referred to as "stresses." When a stress is applied to an equilibrium system, the system responds by shifting the equilibrium position in a direction that reduces the stress. This means that the concentration of the reactants and products will change until a new equilibrium is established. Therefore, the only correct option is that "equilibrium is re-established when a stress is applied." The other options are incorrect because a system in equilibrium is reversible, and the reaction may not go to completion. Additionally, the equilibrium position is not affected by a catalyst because it only speeds up the rate of the reaction without affecting the position of equilibrium.
Tambaya 32 Rahoto
Which type of reaction is illustrated by the following equation? C12H26 → 5C 2H4 + C 2H6
Bayanin Amsa
The type of reaction illustrated by the given equation is "cracking". In cracking, a large hydrocarbon molecule is broken down into smaller molecules by heating it at high temperatures or using a catalyst. In this reaction, C12H26 (a large hydrocarbon molecule) is broken down into smaller molecules of C 2H4 and C 2H6 by heating. Therefore, the correct answer is "Cracking".
Tambaya 33 Rahoto
Which of the following processes is used in food preservation in an industry?
Bayanin Amsa
The process used in food preservation in an industry is the irradiation of gamma rays. Gamma irradiation is a process that exposes food to a controlled amount of ionizing radiation to eliminate bacteria, fungi, and other microorganisms that cause food spoilage and foodborne illness. The gamma rays penetrate the food, disrupting the genetic material of microorganisms and rendering them unable to reproduce. This process does not make the food radioactive and does not significantly change the taste, texture, or nutritional value of the food. Therefore, the correct option is "Irradiation of gamma rays".
Tambaya 34 Rahoto
The most common process in the extraction of metals from their ore is
Bayanin Amsa
The most common process in the extraction of metals from their ore is **reduction**. In this process, the metal oxide in the ore is reduced by carbon or another reducing agent to obtain the metal. Reduction involves the removal of oxygen or addition of electrons to the metal ion, resulting in the formation of the metal. This process is used for extracting metals such as iron, copper, and zinc from their ores. Electrolysis is also used in the extraction of certain metals, but it is not as common as reduction.
Tambaya 35 Rahoto
Which of the following gases is used to retard the vaporization of the filament in a light bulb?
Bayanin Amsa
Argon is used to retard the vaporization of the filament in a light bulb. When a light bulb is turned on, the filament heats up and vaporizes, leading to a loss of material and eventual failure of the bulb. However, if the bulb is filled with an inert gas like argon, the gas helps to slow down the rate of vaporization by reducing the rate of evaporation of the filament. This prolongs the life of the filament and the bulb. Helium and hydrogen are not commonly used because they are too light and can escape through small leaks in the bulb. Oxygen is not used because it can react with the hot filament, leading to oxidation and failure of the bulb.
Tambaya 36 Rahoto
The oxidation number of sulphur in Fe2(SO4)3 is
Bayanin Amsa
In Fe2(SO4)3, there are two iron (Fe) atoms and three sulfate (SO4) ions. Each sulfate ion has a charge of -2, and the total negative charge of the three sulfate ions is -6. Since the compound as a whole is neutral, the total positive charge must be +6. To find the oxidation number of sulfur (S) in sulfate (SO4) ion, we need to apply the following rule: the sum of the oxidation numbers of all atoms in a compound must be equal to the overall charge of the compound. In sulfate ion, oxygen (O) always has an oxidation number of -2, so the total oxidation number contributed by four oxygen atoms in SO4 is -8. Therefore, the oxidation number of S in SO4 can be calculated as follows: (-2 × 4) + (oxidation number of S) = -2 Simplifying the above equation, we get: -8 + (oxidation number of S) = -2 (oxidation number of S) = +6 So, the oxidation number of sulfur in Fe2(SO4)3 is +6. Therefore, the correct option is +6.
Tambaya 37 Rahoto
The production of biogas from the fermentation of waste materials is an example of
Bayanin Amsa
The production of biogas from the fermentation of waste materials is an example of recycling. This is because biogas is produced by the breakdown of organic waste materials, such as food scraps and animal manure, in the absence of oxygen. The waste materials are recycled and converted into a useful energy source, biogas, which can be used for heating, electricity generation, or as a fuel for vehicles. Recycling is the process of converting waste materials into new products or energy sources, rather than disposing of them as garbage. In the case of biogas production, organic waste materials that would otherwise be discarded are recycled into a valuable resource.
Tambaya 38 Rahoto
Hydrogen bonds are formed between molecules containing a hydrogen atom bonded to a
Bayanin Amsa
Hydrogen bonds are a type of intermolecular force that forms between molecules containing a hydrogen atom bonded to a strongly electronegative atom such as oxygen, nitrogen or fluorine. These atoms have a partial negative charge due to their high electronegativity, which attracts the partially positive hydrogen atom of another molecule, forming a weak bond between them. This type of bonding is important in many biological processes, such as the structure of DNA and the folding of proteins, and also plays a role in the physical properties of substances such as water. Hydrogen bonds do not form with non-polar species, diatomic elements, or complex ions because they lack the necessary partial charges for the interaction to occur.
Tambaya 39 Rahoto
The relative atomic mass of chlorine is not a whole number because
Tambaya 40 Rahoto
Which of the following salts on hydrolysis would give an alkaline solution?
Bayanin Amsa
The salt that would give an alkaline solution upon hydrolysis is CH3COONa. When CH3COONa is hydrolyzed, it reacts with water to form acetic acid (CH3COOH) and sodium hydroxide (NaOH). Sodium hydroxide is a strong base and will dissociate in water to produce hydroxide ions (OH-), which will increase the pH of the solution and make it alkaline. Acetic acid is a weak acid and will only slightly lower the pH of the solution. On the other hand, NH4CI, AICI3, and NH4NO3 are all salts that would give an acidic solution upon hydrolysis. When NH4CI is hydrolyzed, it forms ammonium hydroxide (NH4OH) and hydrochloric acid (HCI), which is an acidic solution. AICI3 and NH4NO3 would also give acidic solutions upon hydrolysis.
Tambaya 41 Rahoto
An aqueous solution of Na2CO3 is
Bayanin Amsa
An aqueous solution of Na2CO3 (sodium carbonate) is alkaline. When sodium carbonate is dissolved in water, it dissociates into sodium ions (Na+) and carbonate ions (CO32-). The carbonate ions react with water molecules to form bicarbonate ions (HCO3-) and hydroxide ions (OH-). The presence of hydroxide ions makes the solution alkaline, with a pH greater than 7. Therefore, an aqueous solution of Na2CO3 is an alkaline solution.
Tambaya 42 Rahoto
The type of energy changes that accompany the mixing of a strong acid to a strong base is
Bayanin Amsa
When a strong acid and a strong base are mixed, they undergo a chemical reaction called neutralization. During this reaction, the hydrogen ions (H+) from the acid combine with the hydroxide ions (OH-) from the base to form water (H2O). The mixing of a strong acid to a strong base results in an exothermic reaction, which means that heat is released. This is because the breaking of the strong acid and base bonds releases energy, and the formation of the new water bonds also releases energy. The heat released can be felt if you touch the container in which the acid and base are mixed. There is no electrical, light, or sound energy released during the mixing of a strong acid to a strong base. Therefore, the correct answer is heat.
Tambaya 43 Rahoto
The crystal layers in graphite are held together by
Bayanin Amsa
The crystal layers in graphite are held together by van der Waal's forces. These forces are relatively weak and are caused by the attraction between temporary dipoles in adjacent atoms or molecules. In graphite, each layer is made up of carbon atoms arranged in a hexagonal lattice, with each carbon atom bonded to three neighboring carbon atoms through strong covalent bonds. However, the layers themselves are held together by van der Waal's forces, which allows them to slide past each other easily. This is why graphite is a soft, slippery material, and is commonly used as a lubricant.
Tambaya 44 Rahoto
Which of the following relationships correctly expresses the Boyle's law?
Bayanin Amsa
The correct relationship that expresses Boyle's law is "P \(\alpha\) \(\frac{1}{V}\) at constant T." This means that at a constant temperature, the pressure of a gas is inversely proportional to its volume. In other words, as the volume of a gas decreases, its pressure will increase, and vice versa, as long as the temperature remains constant. This relationship is often written as PV = constant, where P is the pressure, V is the volume, and the product of the two is constant as long as the temperature remains constant.
Tambaya 46 Rahoto
TEST OF PRACTICAL KNOWLEDGE QUESTION
Credit will be given for strict adherence to the instructions, for observations, precisely recorded, and for accurate inferences. All tests, observations, and inferences must be clearly entered in your answer book, in ink, at the time they are made.
C contains two cations and two anions. Perform the following exercises on C. Record your observations and identify any gas (es) evolved. State the conclusion you draw from the result of each test.
(a) Dissolve all of C in about 10 cm\(^3\) of distilled water. Stir the resulting solution thoroughly.
(i) To about 2 cm\(^3\) of the solution, add few drops of AgNO\(_3\) solution, followed by HNO\(_{3(aq)}\). To the mixture, add excess NH\(_{3(aq)}\)
(ii) To another 2 cm\(^3\) portion of the solution, add dil. HCl followed by BaCl\(_2\) solution.
(iii) To another 2 cm\(^3\) portion of the solution, add NaOH\(_{3(aq)}\) dropwise and then in excess. Warm the mixture.
(iv) To another 2 cm\(^3\) portion of the solution, add NH\(_{3(aq)}\) dropwise and then in excess.
None
Bayanin Amsa
None
Tambaya 47 Rahoto
TEST OF PRACTICAL KNOWLEDGE QUESTION
Burette readings (initial and final) must be given to two decimal places. Volume of pipette used must also be recorded but no account of experimental procedure is required. All calculations must be done in your answer book.
A is a solution of hydrochloric acid. B is a solution containing 2.45g of anhydrous sodium trioxocarbonate (IV) in 250g of solution.
(a) Put A into the burette and titrate it against 20.0 cm\(^3\) or 25.0 cm\(^3\) portion of B using methyl orange as an indicator. Repeat the exercise to obtain consistent titres. Tabulate your burette reading and calculate the average volume of A used. The equation for the reaction involved in the titration is Na\(_2\)CO\(_{3(aq)}\) + 2HCI\(_{(aq)}\) + H\(_2\)O\(_{(l)}\)
(b) From your results and the information provided, calculate the:
(i) concentration of B in moldm\(^{-3}\)
(ii) concentration of A in moldm\(^{-3}\)
(iii) concentration of A in gdm\(^{-3}\)
(iv) volume of the gas evolved in the reaction at s.t.p.
[H = 1.00; C: 12.0; O = 16.0; Na = 23.0; Na = 23.0; Cl = 35.5; Molar Volume = 22.4 dm\(^3\)mol\(^{-3}\)]
Tambaya 48 Rahoto
(a)(i) Outline the steps involved in the purification of water for town supply.
(ii) Give two cations that can cause hardness in water.
(iii) State two disadvantages of hardness of water.
(iv) List two sources of water pollution.
(b)(i) Explain briefly why water is a good solvent for sodium chloride but not for oil.
(ii) State the function of H\(_2\)SO\(_4\) in each of the following reaction equations:
(i) C\(_2\)H\(_5\)OH\(_{(l)}\) \(\to\) C\(_2\)H\(_{4(g)}\)
(ii) MgO\(_{(s)}\) + H\(_2\)SO\(_4\)\(_{(aq)}\) —> MgSO\(_{4(aq)}\) + H\(_2\)O\(_{(l)}\)
(iii) C\(_{(s)}\) + conc. H\(_2\)SO\(_4\) --> CO\(_{(g)}\) + SO\(_{2(g)}\) + H\(_2\)O\(_{(l)}\)
(c) (i) Give the two products formed when chlorine water is exposed to sunlight.
(ii) I. Which of the compounds is suitable for the preparation of standard alkaline solution?
II. Give a reason for your answer in (c)(ii)I
Bayanin Amsa
None
Tambaya 49 Rahoto
(a)(i) Define ionic bond.
(ii) What type of bond (s) exist (s) in: I. magnesium oxide; II. ammonium ion?
(b) Determine the oxidation number of sulphur in Na\(_2\)S\(_2\)O\(_2\).
(c) State Faraday's first law.
(d) Give one example each of: (i) acid salt; (ii) base salt.
(e) Name the type of energy change that occurs in each of the following processes
(i) I\(_{2(s)}\) \(\to\) I\(_{2(g)}\)
(ii) Cl\(_{(g)}\) + e\(^{-}\) \(\to\) Cl\(^{-_(g)}\)
(f) State the effect of each of the following aqueous solutions on litmus paper: (i) Na\(_2\)SO\(_{4(aq)}\) (ii) AlCl\(_{3(aq)}\)
(g) Define the term efflorescence.
(h) Give two uses of activated charcoal.
(i) State one use of each of the following processes in the chemical industry: (i) hydrogenation of vegetable oil; (ii) cracking; (iii) esterification.
(j) Calculate the amount of silver deposited in moles when 10920 coulombs of electricity is passed through a solution of a silver salt. [ Faraday constant-- 96500 C mol\(^{-1}\)]
Bayanin Amsa
None
Tambaya 50 Rahoto
TEST OF PRACTICAL KNOWLEDGE QUESTION
Consider the following experimental set-up.
(i) Identify by name: P; Q; R; S and T.
(ii) State the method of collection of gas, S.
(iii) What is the function of R in the experimental set-up?
(iv) Write the balanced equation of the reaction for the preparation of gas S.
Tambaya 51 Rahoto
(a) Define each of the following terms:
(i) ion; (ii) isotopes.
(b)(i) Consider the:element \(_{12}\)Mg and \(_{3}\)Al
I. Write the electron configuration of each element. II. Explain briefly why the first ionization energy of \(_{12}\)Mg is greater than that of \(_{13}\)Al.
(ii) Write the formulae of three different oxides of period 3 elements that react with water.
(c)(i) What are allotropes?
(ii) Name the two crystalline allotropes of carbon.
(iii) Give one industrial use of each allotrope named in (c)(ii).
(d) On warming crystals of sodium chloride with concentrated tetraoxosulphate (VI) acid, a gas was evolved.
(i) List two physical properties of the gas produced.
(ii) Write a balanced equation for the reaction.
(e) A certain chip W used in a circuit of a microcomputer has a mass of 5.68mg. Calculate the amount of W in the microcomputer. [ W = 28 gmol\(^{-1}\) ].
None
Bayanin Amsa
None
Tambaya 52 Rahoto
(a)(i) Explain briefly each of the following terms: I. anode; II. cathode.
(ii) Sodium and aluminium are extracted by the electrolysis of molten sodium chloride and alumina respectively. Write balanced equations for the reactions at the anode and cathode during the extraction of: I. sodium; II. aluminium.
(iii) Explain briefly why extraction of aluminium is considered environmentally friendly while that of sodium is not.
(b) Consider the reaction represented by the following equation:
K\(_2\)Cr\(_2\)O\(_7\) + HC1--> KCI + CrCl\(_3\) + H\(_2\)O + Cl\(_2\)
(i) Explain briefly why this reaction is redox.
(ii) Write balanced half equations for the reaction.
(iii) Write the over-all balanced reaction equation.
(c) During the electrolysis of molten Al\(_2\)O\(_3\), a current of 6A was passed through the electrolyte for 1 hr. 30 mins. Calculate the mass of aluminium deposited at the cathode.
Tambaya 53 Rahoto
(a)(i) Define the term functional group.
(ii) Name the functional groups present in the following compound:
(b) Consider the following structure of an organic compound, Q.
(1) Name compound Q.
(ii) Write the balanced equation for the complete combustion of compound Q.
(iii) What type of reaction will compound Q undergo with chlorine?
(vi) Draw the structure of-the alkene that is an isomer of compound Q.
(c) A chemistry student was provided with four samples of organic compounds, A, B, C, and D. Samples A and B each decolourized bromine in tetrachloromethane but only sample B reacted with a solution of ammoniacal silver trioxonitrate (V) to give a white precipitate. Sample D reacted with sodium trioxocarbonate (IV) to liberate carbon (IV) oxide. When heat was applied to the mixture of samples C and D in a test tube and drops of concentrated tetraoxosulphate (VI) acid added, a product with a fruity odour was formed.
(i) Name the family of organic compounds to which samples A, B, C, and D belong.
(ii) State why samples A and B reacted with bromine in tetrachloromethane.
(iii) State the reason why sample B gave a white precipitate with the solution of ammoniacal silver trioxocarbonate (V).
(iv) Give the name o f the reactions between' samples C and D.
(v) State the two roles of the concentrated tetraoxosulphate (VI) acid in the reaction in (a)(iv).
(d) (i) Describe briefly the production of biogas using a biogas generator.
(ii) State two uses of biogas.
None
Bayanin Amsa
None
Za ka so ka ci gaba da wannan aikin?