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Vraag 1 Verslag
In how many ways can a team of 3 girls be selected from 7 girls?
Antwoorddetails
A team of 2 girls can be selected from 7 girls in 7C3
=7!(7?3)!3!
=7!4!3!ways
Vraag 3 Verslag
In the figure above, KL//NM, LN bisects < KNM. If angles KLN is 54?
and angle MKN is 35?
, calculate the size of angle KMN.
Antwoorddetails
In the diagram above, α = 54∘ (alternate angles; KL||MN) < KNM = 2α (LN is bisector of < KNM) = 108∘
35∘ + < KMN + 108∘ = 180∘ (sum of angles of △ )
< KMN + 143∘ = 180∘
< KMN = 180∘ - 143∘
= 37∘
Vraag 4 Verslag
If y = 4x3 - 2x2 + x, find δyδx
Antwoorddetails
If y = 4x3 - 2x2 + x, then;
δyδx
= 3(4x2) - 2(2x) + 1
= 12x2 - 4x + 1
Vraag 5 Verslag
Find the equation of the straight line through (-2, 3) and perpendicular to 4x + 3y - 5 = 0
Antwoorddetails
4x + 3y - 5 = 0 (given)
The equation of the line perpendicular to the given line takes the form 3x - 4y = k
Thus, substitution x = -2 and y = 3 in 3x - 4y = k gives;
3(-2) - 4(3) = k
-6 - 12 = k
k = -18
Hence the required equation is 3x - 4y = -18
3x - 4y + 18 = 0
Vraag 6 Verslag
Simplify 2√2−√3√2+√3
Antwoorddetails
=2√2−√3√2+√3×√2−√3√2+√3
=2√2(√2)+(2√2)(−√3)−√3(√2)−√3(−√3)(√2)2−(√3)2
=2×2−2√6−√6+32−3
=4−3√6+3−1
=7−3√6−1
=7−1−3√6−1
=−7+3√6
=3√6−7
Vraag 8 Verslag
The locus of a dog tethered to a pole with a rope of 4m is a
Antwoorddetails
The locus of a dog tethered to a pole with a rope of 4m is a circle with radius 4m. When a dog is tethered to a pole with a rope, it can move around the pole within the radius of the rope. Therefore, the dog's possible positions form a circle centered at the pole, with the radius equal to the length of the rope, which in this case is 4 meters. Since the circle has a fixed radius of 4m, it is not a semi-circle, but a full circle. Therefore, the correct answer is "circle with radius 4m."
Vraag 9 Verslag
A man donates 10% of his monthly net earnings to his church. If it amounts to ₦4,500, what is his net monthly income?
Antwoorddetails
We can begin by setting up an equation to represent the given situation. Let x be the man's net monthly income. Then, we know that he donates 10% of his net monthly income to his church, which amounts to ₦4,500. Mathematically, we can express this as: 10% of x = ₦4,500 To solve for x, we need to isolate the variable on one side of the equation. We can do this by dividing both sides of the equation by 10%, which is equivalent to multiplying both sides by 10/100 or 0.1: 10% of x ÷ 10% = ₦4,500 ÷ 10% x = ₦4,500 ÷ 0.1 x = ₦45,000 Therefore, the man's net monthly income is ₦45,000. Answer: ₦45,000
Vraag 10 Verslag
Solve for x in 8x-2 = 2/25
Antwoorddetails
8x-2 = 2/25
x-2 = 2/25 x 1/8
x-2 = 2/200
x-2 = 1/100
1/x2 = 1/100
x2 = 100
x = 10
Vraag 11 Verslag
Values01234Frequency12219
Find the mode of the distribution above
Antwoorddetails
To find the mode of the distribution, we look for the value that appears most frequently in the dataset. From the given frequency table, we can see that the value "4" appears 9 times, which is more than any other value. Therefore, the mode of this distribution is "4". In other words, the mode is the value that occurs most frequently in the data set. It is a measure of central tendency that can be useful in describing a dataset.
Vraag 12 Verslag
Find the mid point of S(-5, 4) and T(-3, -2)
Antwoorddetails
To find the midpoint of the line segment between two points, we need to average the x-coordinates and the y-coordinates of the two points separately. So, to find the midpoint of S(-5, 4) and T(-3, -2), we take the average of their x-coordinates and the average of their y-coordinates: Midpoint x-coordinate = (S x-coordinate + T x-coordinate) / 2 = (-5 + (-3)) / 2 = -4 Midpoint y-coordinate = (S y-coordinate + T y-coordinate) / 2 = (4 + (-2)) / 2 = 1 Therefore, the midpoint of S(-5, 4) and T(-3, -2) is (-4, 1).
Vraag 13 Verslag
If cos(x + 40)o = 0.0872, what is the value of x?
Antwoorddetails
We are given that cos(x + 40) = 0.0872. To find the value of x, we need to use the inverse cosine function, also known as arccosine or cos^-1. Taking the inverse cosine of both sides, we get: arccos(cos(x + 40)) = arccos(0.0872) The inverse cosine and cosine functions are inverses of each other, so they "cancel out" on the left-hand side, leaving us with: x + 40 = arccos(0.0872) Using a calculator or a table of trigonometric values, we can find that arccos(0.0872) is approximately 84.74 degrees. Subtracting 40 from both sides, we get: x = 84.74 - 40 x = 44.74 So the value of x is approximately 44.74 degrees. None of the given options is an exact match, but the closest one is 45 degrees.
Vraag 14 Verslag
Find the value of x in the figure above.
Antwoorddetails
The figure above is a right triangle with sides x, 3 cm, and x√3 cm. Since it is a right triangle, we can use the Pythagorean theorem to find the value of x. The theorem states that the sum of the squares of the two shorter sides of a right triangle is equal to the square of the longest side, which is the hypotenuse. So, we have: x^2 + (3)^2 = (x√3)^2 Expanding the square on the right side: x^2 + 9 = x^2 * 3 Simplifying the equation: x^2 + 9 = 3x^2 Solving for x: 2x^2 = 9 x^2 = 4.5 Taking the square root of both sides: x = ±√(4.5) Since x has to be positive, we choose the positive square root: x = √(4.5) = 2√3 Finally, multiplying by 10: x = 10√3 So, the value of x in the figure is 10√3 cm.
Vraag 15 Verslag
If ∣∣∣−x12−14∣∣∣=−12, find x
Antwoorddetails
Vraag 16 Verslag
The gradient of a line joining (x,4) and (1,2) is 12 . Find the value of x
Antwoorddetails
Vraag 17 Verslag
A cylindrical tank has a capacity of 6160m3. What is the depth of the tank if the radius of its base is 28cm?
Antwoorddetails
Using V=πr2h
6160 = 22/7 x 28 x 28 x h
h=616022×4×28
h=2.5m
Vraag 18 Verslag
Calculate the mid point of the line segment y - 4x + 3 = 0, which lies between the x-axis and y-axis.
Antwoorddetails
y - 4x + 3 = 0
When y = 0, 0 - 4x + 3 = 0
Then -4x = -3
x = 3/4
So the line cuts the x-axis at point (3/4, 0).
When x = 0, y - 4(0) + 3 = 0
Then y + 3 = 0
y = -3
So the line cuts the y-axis at the point (0, 3)
Hence the midpoint of the line y - 4x + 3 = 0, which lies between the x-axis and the y-axis is;
[12(x1+x2),12(y1+y2)]
[12(34+0),12(0+−3)]
[12(34),12(−3)]
[38,−32]
Vraag 19 Verslag
Express the product of 0.00043 and 2000 in standard form.
Antwoorddetails
0.00043 x 2000
= 43 x 10-5 x 2 x 103
= 43 x 2 x 10-5+3
= 86 x 10-2
= 8.6 x 101 x 10-2
= 8.6 x 10-1
Vraag 20 Verslag
A number is chosen at random from 10 to 30 both inclusive. What is the probability that the number is divisible by 3?
Antwoorddetails
Sample space S = {10, 11, 12, ... 30}
Let E denote the event of choosing a number divisible by 3
Then E = {12, 15, 18, 21, 24, 27, 30} and n(E) = 7
Prob (E) = n(E)n(E)
Prob (E) = 721
Prob (E) = 13
Vraag 21 Verslag
Evaluate the inequality x2+34≤5x6−712
Antwoorddetails
x2+34≤5x6−712
12x2+1234≤125x6−12712
6x + 9 ≤
10x - 7
6x - 10x ≤
- 7 - 9
-4x ≤
-16
-4x/-4 ≥
-16/-4
x ≥
4
Vraag 22 Verslag
The pie chart above shows the monthly distribution of a man's salary on food items. If he spent ₦8,000 on rice, how much did he spent on yam?
Antwoorddetails
The man's salary was divided into four food items: Rice, Yam, Beans, and Others. The chart shows that rice takes up 20% of his salary, and yam takes up 40% of his salary. Since rice takes up 20% of his salary, and he spent ₦8,000 on it, we can calculate the total salary of the man by dividing his spend on rice by 20%. ₦8,000 / 20% = ₦40,000 Since the total salary is ₦40,000 and yam takes up 40% of the salary, we can calculate how much he spent on yam by multiplying the total salary by 40%. ₦40,000 * 40% = ₦16,000 Therefore, the man spent ₦16,000 on yam.
Vraag 23 Verslag
If gt2 - k - w = 0, make g the subject of the formula
Antwoorddetails
We can solve for g by manipulating the given equation, gt² - k - w = 0, to isolate g on one side of the equation. First, we can add k and w to both sides of the equation to obtain: gt² = k + w Next, we can divide both sides of the equation by t² to solve for g: g = (k + w)/t² Therefore, the solution is: g = (k + w)/t² Hence, the answer is: (k + w)/t²
Vraag 24 Verslag
The 4th term of an A.P is 13 while the 10th term is 31. Find the 21st term
Antwoorddetails
Let's begin by recalling the formula for the nth term of an arithmetic progression (A.P): a_n = a_1 + (n - 1)d where a_n is the nth term of the A.P, a_1 is the first term, n is the number of the term, and d is the common difference between consecutive terms. We are given that the 4th term of the A.P is 13, so we can substitute these values into the formula to get: a_4 = a_1 + (4 - 1)d = 13 Simplifying this equation, we get: a_1 + 3d = 13 ---(1) We are also given that the 10th term of the A.P is 31, so we can use the formula again to get: a_10 = a_1 + (10 - 1)d = 31 Simplifying this equation, we get: a_1 + 9d = 31 ---(2) Now we need to solve for a_1 and d. We can do this by subtracting equation (1) from equation (2) to eliminate a_1: 6d = 18 d = 3 Substituting this value of d into equation (1), we get: a_1 + 3(3) = 13 a_1 = 4 So, the first term of the A.P is 4 and the common difference is 3. Now we can use the formula again to find the 21st term of the A.P: a_21 = a_1 + (21 - 1)d Substituting the values we found earlier, we get: a_21 = 4 + (20)(3) = 64 Therefore, the 21st term of the A.P is 64, and the correct answer is option (C).
Vraag 25 Verslag
Find the value of ∣∣ ∣∣032178054∣∣ ∣∣
Antwoorddetails
0∣∣∣7854∣∣∣−3∣∣∣1804∣∣∣+2∣∣∣1705∣∣∣
= 0(28 - 40) - 3(4 - 0) + 2(5 - 0)
= 0(-12) - 3(4) + 2(5)
= 0 - 12 + 10
= -2
Vraag 26 Verslag
What is the common ratio of the G.P. (√10+√5)+(√10+2√5)+...
?
Antwoorddetails
Common ratio r of the G.P is
r=Tn+1Tn=T2T1
r=√10+2√5√10+√5
r=√10+2√5√10+√5×√10−√5√10−√5
=(√10)(√10)+(√10)(−√5)+(2√5)(√10)+(2√5)(−√5)(√10)2−(√5)2
10−√50+2√50−1010−5
√505
√25×25
5√25
√2
Vraag 27 Verslag
From the Venn diagram above, the shaded parts represent
Antwoorddetails
The Venn diagram above represents three sets: P, Q, and R. The shaded parts represent the elements that are in both P and Q (the intersection of P and Q), and the elements that are in both P and R (the intersection of P and R). Therefore, the shaded parts represent the set (P∩Q) and the set (P∩R). Option (A) (P∩Q)∪(P∩R) is the correct answer.
Vraag 28 Verslag
Evaluate Log28 + Log216 - Log24
Vraag 29 Verslag
A binary operation * is defined by x * y = xy. If x * 2 = 12 - x, find the possible values of x
Antwoorddetails
x * y = xy
x * 2 = 12 - x
Thus by comparison,
x = x, y = 2
But x * y = x * 2
xy = 12 - x
x2 = 12 - x
x2 + x - 12 = 0
x2 + 4x - 3x - 12 = 0
x(x + 4) - 3(x + 4) = 0
(x - 3)(x + 4) = 0
x - 3 = 0 or x + 4 = 0
So x = 3 or x = -4
Vraag 30 Verslag
y varies directly as w2. When y = 8, w = 2. Find y when w = 3
Antwoorddetails
The given statement "y varies directly as w^2" can be written as an equation: y = k w^2 where k is a constant of proportionality. We are also given that when y = 8, w = 2. We can use this information to solve for k: 8 = k (2^2) 8 = 4k k = 2 Now that we know the value of k, we can use the equation to find y when w = 3: y = 2 (3^2) y = 18 Therefore, when w = 3, y is equal to 18. In other words, the problem is asking us to find the value of y when the value of w is changed from 2 to 3, given that y varies directly with w^2. We can use the equation y = k w^2 and the given information to solve for the constant of proportionality k. Once we have found k, we can use the equation to find y when w = 3.
Vraag 31 Verslag
Numbers123456Frequency182220161014
The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?
Antwoorddetails
Let E demote the event of obtaining at least a 4
Then n(E) = 16 + 10 + 14 = 40
Hence, prob (E) = n(E)n(S)
=40100
=25
Vraag 32 Verslag
Find the median of 5,9,1,10,3,8,9,2,4,5,5,5,7,3 and 6
Antwoorddetails
To find the median of a set of numbers, we need to arrange the numbers in order from smallest to largest and then find the middle number. Arranging the given numbers in order from smallest to largest, we get: 1, 2, 3, 3, 4, 5, 5, 5, 5, 6, 7, 8, 9, 9, 10 There are 15 numbers in this set, so the median will be the average of the two middle numbers: the 7th and 8th numbers. The 7th number is 5, and the 8th number is also 5, so the median of this set of numbers is: (median) = (5 + 5) / 2 = 10 / 2 = 5 So the median of the given set of numbers is 5. Looking at the given answer options, we see that the answer is (B) 5.
Vraag 33 Verslag
The mean of 2 - 4, 4 + t, 3 - 2t and t - 1 is
Antwoorddetails
Mean x = ∑xn
= [(2 - t) + (4 + t) + (3 - 2t) + (2 + t) + (t - 1) ÷
] 5
= [11 - 1 + 3t - 3t] ÷
5
= 10 ÷
5
= 2
Vraag 34 Verslag
If log7.5 = 0.8751, evaluate 2 log75 + log750
Antwoorddetails
If log 7.5 = 0.8751
Then 2log75 + log750
= 2(1.8751) + 2.8751
= 3.7502 + 2.8751
= 6.6253
Vraag 35 Verslag
A woman bought a grinder for ₦60,000. She sold it at a loss of 15%. How much did she sell it?
Antwoorddetails
The woman bought the grinder for ₦60,000 and sold it at a loss of 15%. This means that she sold it for 100% - 15% = 85% of its original price. To find out how much she sold it for, we can calculate 85% of ₦60,000: 85% of ₦60,000 = 0.85 x ₦60,000 = ₦51,000 Therefore, the woman sold the grinder for ₦51,000. The answer is option C.
Vraag 36 Verslag
Find y, if (5−62−7)(52)=(7−11)
Antwoorddetails
(5−62−7)(52)=(7−11)
By matrices multiplication;
5x - 6y = 7 ........(1)
2x - 7y = -11 ......(2)
2 x (1): 10x - 12y = 14 .......(3)
5 x (2): 10x - 35y = -55 ......(4)
(3) - (4): 23y = 69
y = 69/23 = 3
Vraag 37 Verslag
What is the solution of x-5/x+3<-1?
Vraag 38 Verslag
P varies directly as Q and inversely as R. When Q = 36 and R = 16, P = 27. Find the relation between P, Q and R.
Antwoorddetails
P∝QR
P=KQR
When Q = 36, R = 16, P = 27
Then substitute into the equation
27=K3616
K=27×1636
K=12
So the equation connecting P, Q and R is
P=12QR
Vraag 39 Verslag
How many sides has a regular polygon whose interior angle is 135o
Antwoorddetails
The formula to find the interior angle of a regular polygon is: Interior angle = (n - 2) × 180° / n Where "n" is the number of sides of the polygon. We are given that the interior angle of the regular polygon is 135°, so we can substitute this value into the formula and solve for "n": 135 = (n - 2) × 180° / n Multiplying both sides by "n": 135n = (n - 2) × 180° Distributing on the right-hand side: 135n = 180n - 360° Subtracting 135n from both sides: 0 = 45n - 360° Adding 360° to both sides: 360° = 45n Dividing both sides by 45: 8 = n So the regular polygon has 8 sides. Looking at the given answer options, we see that the answer is (D) 8.
Vraag 40 Verslag
If P = {1,2,3,4,5} and P ∪ Q = {1,2,3,4,5,6,7}, list the elements in Q
Vraag 41 Verslag
If y = cos 3x, find δyδx
Antwoorddetails
To find the derivative of y = cos 3x, we need to use the chain rule of differentiation. The chain rule states that if y = f(g(x)), then the derivative of y with respect to x is given by the product of the derivative of f with respect to g multiplied by the derivative of g with respect to x. In other words, δy/δx = δf/δg * δg/δx. Using the chain rule, we have: δy/δx = δ(cos 3x)/δ(3x) * δ(3x)/δx The derivative of cos 3x with respect to 3x can be found using the chain rule again: δ(cos 3x)/δ(3x) = -sin(3x) The derivative of 3x with respect to x is simply 3. Substituting these values in the original equation, we get: δy/δx = -sin(3x) * 3 Simplifying, we have: δy/δx = -3 sin(3x) Therefore, the correct option is -3 sin 3x. In summary, the derivative of y = cos 3x is -3 sin 3x, which is obtained using the chain rule of differentiation.
Vraag 42 Verslag
Find the minimum value of y = x2 - 2x - 3
Antwoorddetails
To find the minimum value of the function y = x^2 - 2x - 3, we can start by completing the square. First, let's add and subtract the value (-2/2)^2 = 1 to the expression inside the parentheses: y = x^2 - 2x + 1 - 1 - 3 Next, we can group the first three terms and write them as a perfect square: y = (x - 1)^2 - 4 Now we can see that the minimum value of the function occurs when (x - 1)^2 is zero, which happens when x = 1. Therefore, the minimum value of the function is y = -4, which occurs when x = 1. So the answer is -4, and we can explain it by completing the square to find the vertex of the parabolic function. The vertex of the parabola y = x^2 - 2x - 3 is (1, -4), and the minimum value of the function occurs at this point.
Vraag 43 Verslag
In the figure above, what is the equation of the line that passes the y-axis at (0,5) and passes the x-axis at (5,0)?
Antwoorddetails
The equation of the line is given by y = x + 5. To understand why, let's consider the two points the line passes through: (0,5) and (5,0). The first point (0,5) means that when x = 0, y = 5. The second point (5,0) means that when y = 0, x = 5. Using these two points, we can write an equation for the line that passes through them. The slope of the line is the difference in y values divided by the difference in x values, or (5 - 0) / (0 - 5) = -1. So the equation of the line is y = -x + b, where b is the y-intercept, or the point where the line crosses the y-axis. To find b, we use the first point (0,5), plug in x = 0, and solve for b: 5 = -0 + b, so b = 5. Putting it all together, the equation of the line is y = -x + 5.
Vraag 44 Verslag
Factorize 2y2 - 15xy + 18x2
Antwoorddetails
The expression 2y^2 - 15xy + 18x^2 can be factored as (2y - 3x)(y - 6x). To factor this expression, we look for two binomials that multiply to the given expression and have a common factor. In this case, (2y - 3x) and (y - 6x) are two binomials that multiply to 2y^2 - 15xy + 18x^2 and have a common factor of y - 6x. So, the factorization of 2y^2 - 15xy + 18x^2 is (2y - 3x)(y - 6x).
Vraag 45 Verslag
Evaluate ∫(2x+3)12δx
Antwoorddetails
∫(2x+3)12δx
let u = 2x + 3, δyδx=2
δx=δu2
Now ∫(2x+3)12δx=∫u12.δx2
=12∫u12δu
=12u32×23+k
=13u32+k
=13(2x+3)32+k
Vraag 46 Verslag
Evaluate ∫sin2xdx
Antwoorddetails
The value of the integral of sin(2x)dx is -(1/2)cos(2x) + k, where k is an arbitrary constant of integration. The integral of sin(2x) can be found using substitution or by recognizing that sin(2x) is the derivative of -(1/2)cos(2x). The constant of integration k is added to account for the fact that there are infinitely many functions that have the same derivative as sin(2x). The constant can take any value and is introduced to reflect the inherent uncertainty in finding an antiderivative.
Vraag 47 Verslag
Find the standard deviation of 5, 4, 3, 2, 1
Antwoorddetails
To find the standard deviation of the numbers 5, 4, 3, 2, and 1, we need to follow these simple steps: Step 1: Calculate the mean (average) of the given numbers. - Add the numbers together: 5 + 4 + 3 + 2 + 1 = 15. - Divide the sum by the total number of values: 15 ÷ 5 = 3. Therefore, the mean of the numbers is 3. Step 2: Calculate the variance of the given numbers. - Subtract the mean from each number: 5 - 3 = 2, 4 - 3 = 1, 3 - 3 = 0, 2 - 3 = -1, 1 - 3 = -2. - Square each of the differences: 2^2 = 4, 1^2 = 1, 0^2 = 0, (-1)^2 = 1, (-2)^2 = 4. - Add up the squared differences: 4 + 1 + 0 + 1 + 4 = 10. - Divide the sum by the total number of values: 10 ÷ 5 = 2. Therefore, the variance of the numbers is 2. Step 3: Calculate the standard deviation of the given numbers. - Take the square root of the variance: √2 = 1.41421356. Therefore, the standard deviation of the numbers 5, 4, 3, 2, and 1 is approximately 1.41421356.
Vraag 48 Verslag
ind the value of k if y - 1 is a factor of y3 + 4y2 + ky - 6
Antwoorddetails
if y - 1 is a factor of y3 + 4y2 + ky - 6, then
f(1) = (1)3 + 4(1)2 + k(1) - 6 = 0 (factor theorem)
1 + 4 + k - 6 = 0
5 - 6 + k = 0
-1 + k = 0
k = 1
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