JAMB UTME - Chemistry - 2008
Question 1 Report
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800 * 300 = 650 * V2
V2 = (800 * 300)/650 = 369.23 cm3
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Question 7 Report
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pH = -log(H+) Or 14 - pOH
pOH = -log(0.001)
pOH = 3
pH = 14 - 3 = 11
Question 8 Report
The IUPAC nomenclature for the structure above is
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Question 10 Report
2Na(s) + 2H2O(l) → 2NaOH(aq) + H2(g)
From the equation above, calculate the mass of sodium hydroxide produced by 2.3g of sodium.
[H = 1, O = 16, Na = 23]
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Relative molecular mass of NaOH = 23 + 16 + 1 = 40smol-1
2 * 23g of sodium react with water to produce
2 * 40g of NaOH
∴ 2.3g of sodium will react with water to produce
(2.3 * 40 * 2)/(23 * 2) = 4.00g
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Question 16 Report
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CAVA = NA/NB = (0.05 * 32)/(CB * 25)
∴ CB = (0.05 * 32)/25 = 0.064 mol dm-3
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Question 24 Report
The atom of an element X is represented as \( {}^{y}_{z}X \). The basic chemical properties of X depend on the value of
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Question 27 Report
Use the diagram to answer this question.
The gas that can be used to demonstrate the experiment is
Question 28 Report
Use the diagram to answer this question.
The colour of the fountain water is
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Question 36 Report
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O.N of H + O.N of C + 2* O.N of oxygen of
H = 0
1 + X + 2X - 2 + 1 = 0
2 + X -4 = 0
X = 4 - 2 = +2
Question 38 Report
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mole = 92.3/12 7.7/1
7.1/7.1 7.1/7.1
empirical formula = CH
(CH)n = 26
(12 + 1)n = 26
(13)n = 26
n = 26/13 = 2
molecular formula = C2H2
Question 39 Report
Choose the correct option from the structure above
Question 40 Report
16.8 g of sodium hydrogen trioxocarbonate (IV) is completely decomposed by heat. Calculate the volume of carbon(IV) oxide given off s.t.p
[Na 23, C = 12, O = 16, H = 1, Molar volume of a gas at s.t.p = 22.4 dm3]
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Relative molecular mass of NaHCO3 = 23 +1 + 12 + 16 * 3 = 84smol-1
2 * 84g of NaHCO3 will be liberated 22.4dm3 or CO2 at s.t.p
16.8g of NaHCO3 will libertae (16.8 * 22.4)/(2 * 84) = 2.24 dm3
Question 41 Report
\( {}^{11}_{11}\mathrm{Na}^{+1}_{0}\mathrm{n} \xrightarrow[11]{24} \mathrm{Na} \)
The reaction above is an example of
Question 42 Report
117.0g of sodium chloride was dissolved in the solubility in 1.0dm3 of distilled water at 25oC. Determine the solubility in mol dm-3 of sodium chloride at that temperature
[Na = 23, Cl = 35.5]
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No. of mole of NaCl = 117/55.5 = 2.1 mol
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Question 47 Report
If a given quantity of electricity liberates 0.65g of Zn2+, what amount of Hg2+ would be liberated by the same quantity of current?
[Zn = 65, Hg = 201]
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Question 48 Report
NH3(g) + HCl(s) → NH4Cl(s)
The entropy change in the system above is
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Question 49 Report
