NECO SSCE - General Mathematics - 2008

Given that x² + y² + k = 60 and x = \(\sqrt{10}\) when y = 4 , find the value of k.

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x2 ${}^2$ + y2 ${}^2$ + k = 60

(?10)2 ${}^2$ + (4)2 ${}^2$ + k = 60

k + 10 + 16 = 60

k =  60 - 26

k = 34

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