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Question 1 Report
Question 2 Report
Question 3 Report
θA = 2θB ,
| mA | = | 12 | mB |
H = MCθ
mA
cA
θA
= mB
cB
θB
( 1/2 mB
)CA
(2θB
) = mB
cB
θB
| CA CB | = | 11 |
⇒ 1 : 1
Question 4 Report
l1
= 5m, ΔT = 10c, l2
- l1
= 1mm
l1
= 2.5m, ΔT = 5c, l2
- l1
= ?
| using | α | = | l2 - l1 l1 ΔT |
| 15(10) | = | l2 - l1 2.5(5) |
| l2 | - | l2 | = | 2.5(5)5(10) | = | 14 | = | 0.25mm |
Question 5 Report
The volume of 0.354g of helium at 273°C and 114cm of mercury pressure is 2667cm\(^{3}\). Calculate the volume
m = 0.354g, T1
= 273°C = 273 + 273 = 576K
P1
= 114cmHg, V1
= 2667cm3
at STP
T2
= 273K, P2
= 76cmHg, V2
= ?
| P1 V1 T1 | = | P2 V2 T1 |
| V2 | = | 114 × 2667 × 27376 × 576 | = | 2000.25cm3 |
Question 6 Report
Question 7 Report
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Question 10 Report
Question 11 Report
Question 12 Report
Water and Kerosine are drawn respectively into the two limbs of a Hare's apparatus. The destiny of water is \(1.0\mathrm{g\,cm^{-3}}\) and the density of kerosine is \(0.80\mathrm{g\,cm^{-3}}\). If the height of the water column is 20.0cm, calculate the height of the kerosine column.
Devices with different liquids
d1
h1
= d2
h2
1 × 20 = 0.8 × h
| h | = | 200.8 | = | 25cm |
Question 13 Report
u + v = 40
vu = 3
v = 3u
u + 3u = 40
4u = 40
u = 10cm
v = 3u = 30cm
f = uvu+v=10(30)10+30=30040
= 7.5 cm
Question 14 Report
A well 1km deep is filled with a liquid of density \(950\text{kg/m}^3\) and \(g = 10\text{m/s}^2\), the pressure at the bottom of the well is
Question 15 Report
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Question 18 Report
| v | = | dt | or | v | α | d |
d = x, v = 4m/s
d = 2x, v = ? (girl and image)
| v | = | 2 × 4x | = | 8 | ms |
Question 19 Report
In which of the points labelled A, B, C, D and E on the conductor shown would electric charge tend to concentrate most
Question 20 Report
Question 21 Report
The limiting frictional force between two surfaces depends on
I. the normal reaction between the surfaces
II. the area of surface in contact
III. the relative velocity between the surfaces
IV. the nature of the surfaces
Question 22 Report
The resultant capacitance in the figure above is
For the parallel arrangement = 2 + 4 = 6μf
| For | the | series | arrangement | = | 1CT | = | 12 | + | 13 | + | 16 | + | 14 |
| 1CT | = | 1512 |
| CT | = | 1215 | = | 0.8μf |
Question 23 Report
In a slide wire bridge, the balance is obtained at a point 25cm from one end of wire 1m long. The resistance to be tested is connected to that end and a standard resistance of \(3.6\,\Omega\) is connected to the other end of the wire. Determine the value of the unknown resistance
R3.6=7525=13
3R = 3.6
R = 1.2Ω
Question 24 Report
The earth's gravitational field intensity at its surface is about
\(G = 6.7 \times 10^{-11}\,\mathrm{Nm^2/kg^2}\), mass of the earth is \(6 \times 10^{24}\,\mathrm{kg}\), radius of the earth is \(6.4 \times 10^6\,\mathrm{m}\), g on the earth = \(9.8\mathrm{m/s^2}\)
Question 25 Report
Question 26 Report
Question 27 Report
A coil X is moved quickly away from the end Y of a stationary metal bar and a current then flows in X as shown above.
Then
Question 28 Report
The value of T in the figure above is
Tsin30 + Tsin30 =40
2Tsin30 = 40
Tsin30 = 40/2 = 20
T(12 ) = 20
T = 20 x 2 = 40N
Question 29 Report
Question 30 Report
A metal rod has a length of 100cm at \(200^\circ C\). At what temperature will its length be 99.4cm. If the linear expansivity of the material of the rod is \(2 \times 10^{-5}C^{-1}\)
Question 31 Report
The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
Mr
(90 - 50) = 0.2(100 - 90)
40Mr
= 0.2 × 10
Mr
= 240
= 0.05kg
Question 32 Report
Question 33 Report
The height at which the atmosphere cases to exist is about 80km. If the atmospheric pressure on the ground level is 760mmHg, the pressure at a height of 20km above the ground level is
\((\rho_m = 13.6g/cm^3\ \rho = 0.00013g/cm^3)\)
ρm
hm
= ρa
ha
13.68(760 - p) × 10−3
= 13 × 10−5
(20 × 103
)
| 760 | - | p | = | 13 × 10−5 × 20 × 103 13.68 × 10−3 | = | 19.00 | × | 101 |
760 - p = 190
p = 760 - 190 = 570mmHg
Question 34 Report
The conductivity of gases at low pressure can be termed as
I. hot cathode emission
II. thermo ionic emission
III. cold cathode emission
IV. Field emission
Question 35 Report
When the downward current flows in a straight vertical conductor, the direction of its magnetic field at a point due north of the wire is
At a point due N of the wire, the field is due east, at a point due S of the wire, the field is due west.
Question 36 Report
Question 37 Report
Question 38 Report
Question 39 Report
P = 0.45cm, L = 60cm, Eff = 75/π%
| VR | (Screw | system) | = | 2πrP | = | 2πLP |
| M.A | = | Eff% × VR100 | = | 75π | × | 1100 | × | 2π × 600.45 | = | 75 × 800300 | = | 200 |
Question 40 Report
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