A particle of weight 120N is placed on a plane inclined at 300 to the horizontal. If the plane has an efficiency of 60% to the floor what is the force requi...

Assessment: JAMB UTME - Physics - 2007 Subject: Physics

Question 1 Report

A particle of weight 120N is placed on a plane inclined at 300 to the horizontal. If the plane has an efficiency of 60% to the floor what is the force required to push the weight uniformly up the plane?

50N

100N

175N

210N

Answer Details

Efficiency =

\frac{W (120 N) I N P U T}{W O R K O U T P U T} \times \frac{100}{1}

And for incline plane

V.R = $\frac{1}{S i n θ} = V . R = \frac{1}{S i n 30} = \frac{1}{0.5} = 2 therefore \frac{60}{120} = \frac{M . A}{2} = M . A = \frac{120}{100} = 1.2 but M.A = \frac{l o a d}{e f f o r t} = \frac{120}{E} therefore \frac{120}{E} = 1.2 = E = \frac{120}{1.2} = 100 N$

Therefore Effort up the plane = 100N

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A particle of weight 120N is placed on a plane inclined at 300 to the horizontal. If the plane has an efficiency of 60% to the floor what is the force requi...

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