A travelling wave moving from left to right has an amplitude of 0.15m, a frequency of 550Hz and a wavelength of 0.01m. The equation describing the wave is

A travelling wave moving from left to right has an amplitude of 0.15m, a frequency of 550Hz and a wavelength of 0.01m. The equation describing the wave is

Answer Details

The equation of a travelling wave is given by: y = A sin (kx - ωt + φ) where A is the amplitude, k is the wave number, ω is the angular frequency, t is time, x is position, and φ is the phase constant. Given the amplitude, frequency, and wavelength of the wave, we can find the wave number and angular frequency using the following equations: k = 2π/λ ω = 2πf Substituting the values, we get: k = 2π/0.01 = 200π ω = 2π × 550 = 1100π The phase constant φ is usually assumed to be zero. Hence, the equation describing the wave is: y = 0.15 sin (200πx - 1100πt) which can be simplified as: y = 0.15 sin 200π(x - 5.5t) Therefore, the correct option is: y = 0.15 sin 200π(x - 5.5t)