When excess ethene is shaken with acidified KMnO4 solution, the product obtained is
Answer Details
When excess ethene is shaken with acidified KMnO4 solution, the product obtained is ethane-1,2-diol. This is because acidified KMnO4 solution is a strong oxidizing agent and can oxidize alkenes such as ethene. When ethene is reacted with KMnO4, it undergoes oxidative cleavage where the double bond is broken and two hydroxyl groups are added to the carbons of the double bond. The resulting product is a diol, specifically ethane-1,2-diol.