Eight alpha decays and six beta decays are necessary before an atom of 2 23892U 92 238 U achieves stability. The final product in the chain has an atomic nu...

Eight alpha decays and six beta decays are necessary before an atom of 2 ${}_{92}^{238}U$ achieves stability. The final product in the chain has an atomic number of

Answer Details

U $\to$ 8(${}_2^{4}He$) + 6(${}_{-1}^{0}e$) + ${}_a^{b}X$

92 = (8 X 2) + (6 X -1) + a

a = 82