A conductor of length 1m moves with a velocity of 50ms-1 at an angle of 30o to the direction of a uniform magnetic field of flux density 1.5Wbm-2. What is t...

A conductor of length 1m moves with a velocity of 50ms-1 at an angle of 30o to the direction of a uniform magnetic field of flux density 1.5Wbm-2. What is the e.m.f induced in the conductor?

Answer Details

The electromotive force (e.m.f) induced in a conductor moving in a magnetic field can be calculated using Faraday's law of electromagnetic induction, which states that the e.m.f induced in a conductor is equal to the rate of change of the magnetic flux through the conductor. The magnetic flux can be calculated as the product of the magnetic field strength and the area of the conductor that is perpendicular to the magnetic field. In this case, the magnetic field strength is given as 1.5 Wb/m^2, the length of the conductor is 1m, and the angle between the velocity of the conductor and the direction of the magnetic field is 30 degrees. The area of the conductor that is perpendicular to the magnetic field can be calculated as the product of the length of the conductor and the component of its velocity that is perpendicular to the magnetic field. The component of velocity that is perpendicular to the magnetic field can be calculated as the product of the velocity and the sine of the angle between the velocity and the magnetic field direction. Thus, the e.m.f induced in the conductor can be calculated as follows: e.m.f = rate of change of magnetic flux = magnetic field strength * area of conductor perpendicular to magnetic field = 1.5 Wb/m^2 * (1m) * (50 m/s * sin(30 degrees)) = 37.5V Therefore, the e.m.f induced in the conductor is 37.5V.