JAMB UTME - Chemistry - 2013 | Green Bridge CBT

Question 1 Report

In the graph above, the activation energy of the catalyzed reaction is

100KJ

300KJ

250KJ

200KJ

Answer Details

Read lesson note on Chemical Kinetics And Equilibrium System (Nigeria Only) (WAEC)

Chemical Kinetics And Equilibrium System (Nigeria Only)

View Answer

Question 2 Report

An organic compound contains 60% carbon, 13.3% hydrogen and 26.7% oxygen. Calculate the empirical formula
rn(C=12,H =1, O=16)

C 5H 12O

C 3H 8O

C 6H 13O 2

C 4H 9O

Answer Details

To calculate the empirical formula, we need to determine the simplest whole number ratio of atoms in the compound. Given that the compound contains 60% carbon, we can assume that the compound contains 60 grams of carbon in a 100-gram sample of the compound. Similarly, we can assume that the compound contains 13.3 grams of hydrogen and 26.7 grams of oxygen in a 100-gram sample. Next, we need to convert the masses of each element to the number of moles of each element using their respective atomic masses. The atomic masses are: - Carbon (C) = 12 - Hydrogen (H) = 1 - Oxygen (O) = 16 So, the number of moles of each element is: - Carbon (C) = 60g / 12 g/mol = 5 moles - Hydrogen (H) = 13.3g / 1 g/mol = 13.3 moles - Oxygen (O) = 26.7g / 16 g/mol = 1.67 moles The next step is to divide each of the mole values by the smallest mole value to obtain the simplest whole number ratio of atoms. In this case, the smallest mole value is 1.67 moles of oxygen. Dividing by 1.67 gives: - Carbon (C) = 5 / 1.67 = 2.99 ≈ 3 - Hydrogen (H) = 13.3 / 1.67 = 7.95 ≈ 8 - Oxygen (O) = 1.67 / 1.67 = 1 Therefore, the empirical formula of the compound is C3H8O. is the correct formula as it matches the empirical formula determined above.

Read lesson note on Chemistry, Industry And The Environment (WAEC)

Chemistry, Industry And The Environment

View Answer

Question 3 Report

The decarboxylation of ethanoic acid will produce carbon (IV)oxide and

methane

ethane

propane

butane

Answer Details

Read lesson note on Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

View Answer

Question 4 Report

Choose the correct option from the graph above.

3Fe(S) + 4H2O(g) ⇌ Fe3O4(s) + 4H2(g). The equilibrium constant, K, of the reaction above is represented as

Answer Details

Read lesson note on Chemical Equilibria (JAMB)

Chemical Equilibria

View Answer

Question 5 Report

A primary amide is generally represented by the formula

RCOOR

RCONH 2

RCONHR

RCONR 2

Answer Details

A primary amide is generally represented by the formula RCONH2. This means that it is a compound made up of an R group (which can be any alkyl or aryl group) attached to a carbon atom, which is then connected to a nitrogen atom by a double bond, and that nitrogen atom is also bonded to two hydrogen atoms. This arrangement of atoms is characteristic of a primary amide, which is an organic compound that contains the functional group -CONH2. The other options listed are not primary amides. RCOOR is an ester, RCONHR is a secondary amide (with one hydrogen atom replaced by an R group), and RCONR2 is a tertiary amide (with both hydrogen atoms replaced by R groups).

Read lesson note on Periodic Chemistry (Ghana Only) (WAEC)

Periodic Chemistry (Ghana Only)

View Answer

Question 6 Report

The compound above is an

alkanone

alkanoate

alkanal

akanol

Answer Details

Read lesson note on Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

Chemistry Of Carbon Compounds (Nigeria Only)

View Answer

Question 7 Report

Which of the following fraction is used as raw material for the cracking process?

kerosine

lubricating oil

bitumen

diesel oils

Answer Details

The fraction used as raw material for the cracking process is typically a heavier fraction of crude oil, such as lubricating oil or diesel oils. In the cracking process, these heavier fractions are broken down into lighter fractions, such as gasoline and kerosene. The goal of cracking is to produce more valuable, in-demand products from the heavier, less valuable fractions of crude oil.

Read lesson note on Solubility (JAMB)

Solubility

View Answer

Question 8 Report

In an endothermic reaction, if there is a loss in entropy the reaction will

be indeterminate

be spontaneous

not be spontaneous

be at equilibrium

Answer Details

Read lesson note on Energy Changes (JAMB)

Energy Changes

View Answer

Question 9 Report

Which of the following molecules is held together by hydrogen bond?

CH4

HBr

H2SO4

Answer Details

Hydrogen bonds are a type of chemical bond that forms between a hydrogen atom and an electronegative atom, such as nitrogen, oxygen, or fluorine. Out of the given options, only "HF" molecule is held together by hydrogen bonds. In this molecule, the hydrogen atom is bonded to the electronegative fluorine atom through a hydrogen bond. This bond results from the attraction between the positively charged hydrogen atom and the negatively charged fluorine atom. The other molecules listed, "CH4," "HBr," and "H2SO4," do not contain hydrogen bonds as they do not involve the interaction between a hydrogen atom and an electronegative atom.

Read lesson note on Oxidation And Reduction (JAMB)

Oxidation And Reduction

View Answer

Question 10 Report

Aluminium containers are frequently used to transport trioxonitrate (V) acid because aluminium

has a silvery-white appearance

has a low density

does not react with the acid

does not corrode

Answer Details

Aluminium containers are used to transport trioxonitrate (V) acid because aluminium does not react with the acid and does not corrode, which makes it a safe material for containing the acid. This is important because if the container were to react with the acid or corrode, it could cause leaks or spills, which would be dangerous. Additionally, aluminium has a low density and is lightweight, which makes it easy to transport and handle.

Read lesson note on Metals And Their Compounds (JAMB)

Metals And Their Compounds

View Answer

Question 11 Report

The coloured nature of transition metal ions are associated with their partially filled

f- orbital

s- orbital

p-orbital

d-orbital

Answer Details

The colored nature of transition metal ions is associated with their partially filled d-orbital. When an electron in a transition metal ion absorbs a certain amount of energy, it gets excited and jumps to a higher energy level. When this electron falls back down to its original energy level, it emits a certain amount of energy in the form of light. This emitted light has a characteristic color that is determined by the energy difference between the excited and ground states of the electron. The d-orbitals in transition metal ions are partially filled with electrons, and these electrons can easily move between different energy levels. When light is absorbed by a transition metal ion, the electrons in the partially filled d-orbitals can get excited to higher energy levels. When these electrons fall back down to lower energy levels, they emit light with a specific wavelength and color that corresponds to the energy difference between the excited and ground states of the electron. Therefore, the color of transition metal ions is directly related to the presence of partially filled d-orbitals, which allow electrons to absorb and emit light in a way that produces characteristic colors.

Read lesson note on Atomic Structure And Bonding (JAMB)

Atomic Structure And Bonding

View Answer

Question 12 Report

Which of the gases is employed as an anaesthesia?

N 2O

NO2

NH3

Answer Details

The gas that is commonly used as an anaesthetic is Nitrous Oxide (N2O). Nitrous oxide is a colorless, non-flammable gas with a slightly sweet taste and odor. It is also known as laughing gas due to its euphoric and pain-relieving effects. Nitrous oxide works by decreasing the sensation of pain and inducing a state of relaxation and sedation. It is commonly used in dental procedures, minor surgeries, and obstetrics. Nitrous oxide is preferred over other anaesthetic gases because it is fast-acting, has a rapid onset and offset of action, and is easily administered. It is also a relatively safe gas to use as an anaesthetic, with a low risk of side effects or complications. In summary, Nitrous Oxide is the gas that is commonly used as an anaesthetic due to its fast-acting, safe, and easily administered properties.

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)

Kinetic Theory Of Matter And Gas Laws

View Answer

Question 13 Report

From the diagram above, an ideal can be represented by

Answer Details

Read lesson note on Metals And Their Compounds (JAMB)

Read lesson note on Structure Of The Atom (WAEC)

Read lesson note on States Of Matter (WAEC)

Read lesson note on Non-metals And Their Compounds (JAMB)

Metals And Their Compounds

Structure Of The Atom

States Of Matter

Non-metals And Their Compounds

View Answer

Question 14 Report

The presence of an impurity in substance will cause the melting point to

be zero

reduce

increase

be stable

Answer Details

The presence of an impurity in a substance will reduce its melting point. The melting point of a pure substance is a fixed temperature at which the solid and liquid phases coexist in equilibrium. However, when an impurity is added to the substance, the impurity molecules become incorporated into the crystal lattice of the substance. This incorporation of impurity molecules disrupts the regular arrangement of the substance's molecules, making it more difficult for the substance to maintain its crystal structure as the temperature increases. As a result, the melting point of the substance is lowered, and it melts at a lower temperature than the pure substance. This is why impurities are often added to substances like ice on roads to reduce their melting point and make them melt more quickly.

Read lesson note on Separation Of Mixtures And Purification Of Chemical Substances (JAMB)

Separation Of Mixtures And Purification Of Chemical Substances

View Answer

Question 15 Report

The bond formed between two elements with electron configurations 1s2 2s2 2p6 3s2 and 1s2 2s2 2p4 is

metallic

covalent

dative

ionic

Answer Details

Read lesson note on Atomic Structure And Bonding (JAMB)

Atomic Structure And Bonding

View Answer

Question 16 Report

$\mathrm{2SO}_{2(g)} + \mathrm{O}_{2(g)} \rightarrow \mathrm{2SO}_{3(g)}$

$\Delta H = -395.7\ \mathrm{kJ\,mol^{-1}}$

In the reaction above, the concentration of $\mathrm{2SO}_{3(g)}$ can be in creased by

decreasing the pressure

decreasing the temperature

the addition of catalyst

increasing the temperature

Answer Details

Read lesson note on Chemical Kinetics And Equilibrium System (Nigeria Only) (WAEC)

Chemical Kinetics And Equilibrium System (Nigeria Only)

View Answer

Question 17 Report

The IUPAC nomenclature for the compound above is

4-methylpent-1-ene

3-methylpent-2-ene

2-methylpent-1ene

2-methylpent-4-ene

Answer Details

Read lesson note on Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

Chemistry Of Carbon Compounds (Nigeria Only)

View Answer

Question 18 Report

2H2O (l) + 2F2(g) → 4HF(aq) + O2(g).

In the reaction above, the substance that is being reduced is

O2(g)

H2O(l)

F2(g)

HF(aq)

Answer Details

The substance that is being reduced in the reaction is F2(g). Reduction is a chemical reaction in which electrons are gained by a species, leading to an increase in its oxidation state. In the reaction above, F2(g) is gaining electrons and its oxidation state is decreasing, which indicates that it is being reduced. On the other hand, oxidation is a chemical reaction in which electrons are lost by a species, leading to a decrease in its oxidation state. In the reaction, O2(g) is losing electrons and its oxidation state is increasing, which indicates that it is being oxidized.

Read lesson note on Oxidation And Reduction (JAMB)

Oxidation And Reduction

View Answer

Question 19 Report

10.0 dm3 of water was added to 2.0 mol dm-3 of 2.5dm3 solution of HCl. What is the concentration of the final solution in mol dm-3?

0.4

8.0

2.0

0.5

Answer Details

C1V1 = C2V2

C2 = $\frac{C_{1} V_{1}}{V_{2}}$

= $\frac{2.0 \times 2.5}{12.5}$

= 0.4mol/dm-3

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)

Kinetic Theory Of Matter And Gas Laws

View Answer

Question 20 Report

In an electrochemical cell, polarization is caused by

chlorine

oxygen

tetaoxsulphate (Vl) acid

hydrogen

Answer Details

Read lesson note on Electrolysis (JAMB)

Electrolysis

View Answer

Question 21 Report

$ \mathrm{Zn(s) + CuSO_4(aq) \rightarrow ZnSO_4(aq) + Cu(s)} $

In the reaction above, the oxidizing agent is

CuSO4(aq)

ZnSO4(aq)

Cu(s)

Zn(s)

Answer Details

In the given reaction, Zn (s) + CuSO4 (aq) → ZnSO4 (aq) + Cu (s), zinc (Zn) is oxidized to form Zn2+ ions and copper ions (Cu2+) are reduced to form solid copper (Cu). Therefore, the oxidizing agent in this reaction is CuSO4 (aq), which causes the oxidation of Zn by accepting electrons from it. The reducing agent, on the other hand, is Zn (s), which causes the reduction of Cu2+ ions to form solid copper (Cu).

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)

Kinetic Theory Of Matter And Gas Laws

View Answer

Question 22 Report

The radioisotope used in industrial radiography for the rapid checking of faults in welds and casting is

carbon-14

phosphorus-32

cobalt-60

iodine-131

Answer Details

The radioisotope used in industrial radiography for the rapid checking of faults in welds and casting is cobalt-60. Cobalt-60 is a radioactive isotope that emits gamma rays, which are high-energy electromagnetic radiation. These gamma rays can penetrate through solid materials such as metal and concrete, allowing technicians to see the internal structure of the material without having to physically cut it open. This makes it ideal for checking faults in welds and castings, as it can quickly reveal any cracks or voids that might otherwise be difficult to detect. Once the radiography is done, the cobalt-60 source is removed and the material is safe to handle. The use of cobalt-60 in industrial radiography is a well-established and widely used technique that has been safely and effectively used for many decades.

Read lesson note on Organic Compounds (JAMB)

Organic Compounds

View Answer

Question 23 Report

The shape of the carbon (lV) oxide molecule is

pyramidal

linear

angular

tetrahedral

Answer Details

The shape of the carbon dioxide (CO2) molecule is linear. This is because the molecule consists of two oxygen atoms bonded to a central carbon atom in a straight line. The bond angles in CO2 are all 180 degrees, resulting in a linear shape. This shape is determined by the electron geometry and molecular geometry of the molecule, which are both linear.

Read lesson note on Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

Chemistry Of Carbon Compounds (Nigeria Only)

View Answer

Question 24 Report

Sulphur (IV)oxide is a strong reducing agent in the presence of water due to the formation of

hydroxide ion

sulpgur (Vl)oxide

hydrogen sulhide

trioxosulphate (IV) salt

Answer Details

Read lesson note on Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

View Answer

Question 25 Report

In a water body, too much sewage leads to

a decrease in the temperature of the water which cause in death of aquatic animals

an increase in the number of aquatic animals in the water

an increase in the bacterial population which reduces the level of oxygen in the water

a decrease in the bacterial population which increases the level of oxygen in the water

Answer Details

When there is too much sewage in a water body, it can lead to an increase in the bacterial population. This is because sewage contains organic matter and nutrients that can provide food for bacteria to grow. However, as the bacteria grow, they use up oxygen from the water. If there is too much bacteria, it can lead to a decrease in the level of oxygen in the water. This is called "eutrophication." A decrease in oxygen levels in water can be harmful for aquatic animals. Many fish and other aquatic creatures need a certain level of oxygen to survive, and if there's not enough, they can become sick or die. This can also have a ripple effect throughout the ecosystem, as the loss of certain species can affect the food chain and balance of the environment.

Read lesson note on Environmental Pollution (JAMB)

Environmental Pollution

View Answer

Question 26 Report

The rate of diffusion of a gas Y is twice that of Z If the relative molecular mass of Y is 64 and the two gases diffuse under the same conditions, find the relative molecular mass of Z

Answer Details

\sqrt{y}

= 2x

\sqrt{Z}

= x

\frac{r z}{r y}

\sqrt{\frac{m y}{m z}}

$\frac{2 x}{x}$ = $\sqrt{\frac{64}{m z}}$
$\frac{4}{1}$ = $\frac{64}{m z}$

mz = $\frac{64}{4}$
mz = 16

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)

Kinetic Theory Of Matter And Gas Laws

View Answer

Question 27 Report

A metal that forms soluble trioxosulphate (IV) ion is

barium

potassium

manganese

aluminium

Answer Details

The soluble trioxosulphate (IV) ion is also known as the sulphate (IV) ion or the sulphite ion, SO32-. This ion is formed when sulphur dioxide gas (SO2) dissolves in water, and reacts with oxygen in the air. Out of the given metals, only one metal can form a soluble trioxosulphate (IV) ion, and that is potassium. Potassium sulphite (K2SO3) is a soluble salt that can dissociate into potassium ions (K+) and sulphite ions (SO32-) in water. Barium can form a sulphite ion, but it is not soluble in water. Manganese can form a sulphate ion, but not a sulphite ion. Aluminium can also form a sulphate ion, but it cannot form a sulphite ion. Therefore, the metal that forms a soluble trioxosulphate (IV) ion is potassium.

Read lesson note on Acids, Bases And Salts (Ghana Only) (WAEC)

Acids, Bases And Salts (Ghana Only)

View Answer

Question 28 Report

2- methylbutan- 2ol is an example of a

dihydric alkanol

tertiary alkanol

secondary alkanol

primary alkanol

Answer Details

2-methylbutan-2-ol is an example of a tertiary alkanol. An alkanol is a type of organic compound that contains a hydroxyl (-OH) group attached to a carbon atom in an alkane chain. In this case, the -OH group is attached to a tertiary carbon atom, which means that the carbon is bonded to three other carbon atoms. Tertiary alkanols have the hydroxyl group attached to a tertiary carbon atom, while primary and secondary alkanols have the hydroxyl group attached to a primary or secondary carbon atom, respectively.

Read lesson note on Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

Chemistry Of Carbon Compounds (Nigeria Only)

View Answer

Question 29 Report

The reaction between ammonia and ethyl ethanoate produces

propanol and ethanamide

propanol and propanamide

ethanol and propanamide

ethanol and ethanamide

Answer Details

The reaction between ammonia and ethyl ethanoate produces ethanol and ethanamide. When ammonia reacts with ethyl ethanoate, it undergoes a reaction called a nucleophilic substitution reaction. In this reaction, the nitrogen atom of the ammonia molecule acts as a nucleophile, or a molecule with a strong tendency to donate electrons, and attacks the carbon atom of the ethyl ethanoate molecule, which is bonded to the carbonyl group. This results in the formation of ethanol and ethanamide.

Read lesson note on Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

Chemistry Of Carbon Compounds (Nigeria Only)

View Answer

Question 30 Report

How many unpaired electron are in the p-orbitals of a fluorine atom?

Answer Details

Read lesson note on Atomic Structure And Bonding (JAMB)

Atomic Structure And Bonding

View Answer

Question 31 Report

Copper is displaced from the solution of its salts by most metals because it

is a transition element

is at the bottom of the activity series

is very reactive

has completely filled 3d-orbitals

Answer Details

Copper is displaced from the solution of its salts by most metals because it is at the bottom of the activity series. The activity series is a list of metals arranged in order of their decreasing chemical reactivity. Metals at the top of the activity series are highly reactive and can displace metals below them from their solutions. Copper, on the other hand, is at the bottom of the activity series and is less reactive than most other metals, so it can be displaced by them from its salts. Therefore, when a more reactive metal is added to a solution containing copper ions, the more reactive metal will displace copper ions from the solution, forming its own ions and causing copper to precipitate out of the solution as a solid.

Read lesson note on Chemical Combination (JAMB)

Chemical Combination

View Answer

Question 32 Report

In the laboratory preparation of ammonia, the flask is placed in a slanting position so as to

prevent condensed water from breaking the reaction flask

enable the proper mixing of the reactions in the flask

enhance the speed of the reaction

prevent formation of precipitate

Answer Details

Read lesson note on Oxidation And Reduction (JAMB)

Oxidation And Reduction

View Answer

Question 33 Report

An insoluble salt can be prepared by

the reaction of trioxocarbonate (V) with an acid

double decomposition

the action of dilute acid on an insoluble base

the reaction of metals with an acid

Answer Details

Read lesson note on Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

View Answer

Question 34 Report

Steam changes the colour of anhydrous cobalt (ll) chloride from

white to red

blue to white

blue to pink

white to blue

Answer Details

Read lesson note on Periodic Chemistry (Ghana Only) (WAEC)

Periodic Chemistry (Ghana Only)

View Answer

Question 35 Report

Which of the following compounds is a neutral oxide?

Carbon (IV) oxide

Sulphur (Vl) oixide

Sulphur (IV) oxide

Carbon (ll) oxide

Answer Details

Read lesson note on Acids, Bases And Salts (JAMB)

Acids, Bases And Salts

View Answer

Question 36 Report

Calculate the volume in cm3 of oxygen evolved as s.t.p. when a current of 5 A is passed through acidified water for 193s

{F = 96500 Cmol-1, Molar volume of a gas at s.t.p. = 22.4 dm3}

224.000 dm3

0.056 dm3

0.224 dm3

56.000 dm3

Answer Details

The volume of oxygen evolved can be calculated using the formula: Volume of gas = (Current × Time × Molar volume of gas at s.t.p.) / (2 × Faraday constant) where current is in amperes, time is in seconds, the molar volume of gas at s.t.p. is 22.4 dm³/mol, and the Faraday constant is 96500 C/mol. Plugging in the given values, we get: Volume of gas = (5 A × 193 s × 22.4 dm³/mol) / (2 × 96500 C/mol) = 0.056 dm³ Therefore, the volume of oxygen evolved is 0.056 dm³ or 56 cm³. So, the correct answer is option (B) 0.056 dm³.

Read lesson note on Kinetic Theory Of Matter And Gas Laws (JAMB)

Kinetic Theory Of Matter And Gas Laws

View Answer

Question 37 Report

The solvent used for removing grease stain is

turpentine

ammonia solution

ethanol

solution of borax in water

Answer Details

Read lesson note on Solubility Of Substances (Ghana Only) (WAEC)

Solubility Of Substances (Ghana Only)

View Answer

Question 38 Report

The radioactive emission with the least ionization power is

α−particles

X-rays

γ - r a y s

β−rays

Answer Details

The radioactive emission with the least ionization power is gamma (γ) radiation. Gamma radiation is a type of electromagnetic radiation that has the highest frequency and shortest wavelength among all types of radiation. While it is highly penetrating and can cause damage to biological tissues, it has the least ionization power because it carries no electric charge and does not interact strongly with matter. This means that gamma radiation can easily pass through materials without being deflected or slowed down, and it takes a lot of energy to ionize atoms or molecules through gamma radiation. In comparison, alpha and beta radiation are particles that carry an electric charge and interact more strongly with matter, making them more ionizing than gamma radiation.

Read lesson note on Structure Of The Atom (WAEC)

Read lesson note on Periodic Chemistry (Nigeria Only) (WAEC)

Structure Of The Atom

Periodic Chemistry (Nigeria Only)

View Answer

Question 39 Report

What volume of carbon (ll) oxide is produced by reacting excess carbon with 10 dm3 of oxygen?

5 dm 3

20 dm 3

15 dm 3

10 dm 3

Answer Details

The volume of carbon dioxide produced by reacting excess carbon with 10 dm^3 of oxygen can be calculated using the balanced chemical equation for the reaction. The balanced chemical equation for the reaction between carbon and oxygen to form carbon dioxide is: C + O2 → CO2 From this equation, it can be seen that one molecule of carbon reacts with one molecule of oxygen to form one molecule of carbon dioxide. So, if we have 10 dm^3 of oxygen, we would need 10 dm^3 of carbon to react with it. The volume of carbon dioxide produced would be equal to the volume of the reactants, which in this case is 10 dm^3 + 10 dm^3 = 20 dm^3. Therefore, the answer is 20 dm^3 of carbon dioxide would be produced.

Read lesson note on Stoichiometry And Chemical Reactions (WAEC)

Stoichiometry And Chemical Reactions

View Answer

Question 40 Report

Which of the following substances is not a salt?

Aluminium oxide

Sodium hydrogentrioxosulphate (V)

Sodium trioxocarbonate (V)

Zinc chloride

Answer Details

The substance that is not a salt among the options given is Aluminium oxide. A salt is a type of chemical compound that is formed when an acid reacts with a base. It is typically made up of a metal cation and a non-metal anion. Sodium hydrogentrioxosulphate (V), sodium trioxocarbonate (V), and zinc chloride are all examples of salts. Aluminium oxide, on the other hand, is not formed from the reaction of an acid and a base. It is an oxide of the metal aluminium and is therefore not a salt. In summary, of the substances listed, Aluminium oxide is not a salt, while sodium hydrogentrioxosulphate (V), sodium trioxocarbonate (V), and zinc chloride are all examples of salts.

Read lesson note on Acids, Bases And Salts (Ghana Only) (WAEC)

Acids, Bases And Salts (Ghana Only)

View Answer

Question 41 Report

the minimum amount of energy required for a reaction to take place is

lattice energy

ionization energy

activation energy

kinetic energy

Answer Details

The minimum amount of energy required for a reaction to take place is called the activation energy. Activation energy is the energy required to initiate a chemical reaction by breaking the bonds in the reactant molecules. It is the energy barrier that must be overcome for the reaction to occur. Once the activation energy is surpassed, the reaction will proceed on its own without the need for additional energy input. The activation energy is often provided in the form of heat or light. Lattice energy refers to the energy released when ions combine to form a crystal lattice structure. Ionization energy is the energy required to remove an electron from an atom or ion. Kinetic energy is the energy of motion. None of these terms are directly related to the minimum amount of energy required for a reaction to take place.

Read lesson note on Rates Of Chemical Reaction (JAMB)

Rates Of Chemical Reaction

View Answer

Question 42 Report

If 24.4 g of lead (ll) trioxonitrate (V) were dissolved in 42 g of distilled water at 20oC; calculate the solubility of the solute in gdm-3.

581.000.

0.581

5.810

58.100

Answer Details

To calculate the solubility of lead (II) trioxonitrate (V) in water, we need to use the formula: Solubility (g/dm³) = (mass of solute ÷ volume of solvent) First, let's convert the temperature to Kelvin (K) using the formula K = °C + 273.15: 20°C + 273.15 = 293.15 K Next, we need to calculate the volume of water that the lead (II) trioxonitrate (V) was dissolved in. We can assume that the density of water is 1 g/cm³, so: Volume of water = mass of water ÷ density of water Volume of water = 42 g ÷ 1 g/cm³ Volume of water = 42 cm³ Now, we can calculate the solubility of lead (II) trioxonitrate (V) in water: Solubility (g/dm³) = (mass of solute ÷ volume of solvent) Solubility (g/dm³) = 24.4 g ÷ (42 cm³ ÷ 1000) Solubility (g/dm³) = 581 g/dm³ Therefore, the solubility of lead (II) trioxonitrate (V) in water is 581 g/dm³. The correct option is the one that reads "581.000".

Read lesson note on Solubility Of Substances (Ghana Only) (WAEC)

Solubility Of Substances (Ghana Only)

View Answer

Question 43 Report

The constituent of air that acts as a diluent is

nitrogen

carbon (IV) oxide

noble gases

oxygen

Answer Details

The constituent of air that acts as a diluent is nitrogen. Diluent refers to a substance that is added to a gas or liquid to reduce its concentration. In the case of air, nitrogen is the most abundant gas and makes up about 78% of the air we breathe. The other gases present in air such as oxygen, carbon dioxide, and noble gases make up the remaining 22%. Nitrogen, being an inert gas, does not react with other elements, which makes it an ideal diluent in air. It helps to lower the concentration of reactive gases, making it easier for us to breathe and for combustion reactions to occur safely.

Read lesson note on Air (JAMB)

Air

View Answer

Question 44 Report

An example of a hygroscopic substance is

CuO (S).

MgCL2(S).

CaCL2(S).

NaOH(S).

Answer Details

Read lesson note on Solubility (JAMB)

Solubility

View Answer

Question 45 Report

Three drops of a 1.0 mol dm-3 solution of HCl was added to 20 cm3 of a solution of pH6.4. The pH of the resulting solution will be

close to that of pure water

less than 6.4

greater than 6.4

unaltered

Answer Details

The addition of HCl (hydrochloric acid) to a solution of pH 6.4 will result in a decrease in pH. Hydrochloric acid is a strong acid and will release hydrogen ions (H+) into the solution, thereby lowering the pH. The exact pH will depend on the concentration of HCl added, but it will be less than 6.4.

Read lesson note on Periodic Chemistry (Ghana Only) (WAEC)

Periodic Chemistry (Ghana Only)

View Answer

Question 46 Report

Use the following option above to answer this question. Which of the following compounds in solution will turn red litmus paper blue?

Answer Details

Read lesson note on Acids, Bases And Salts (Ghana Only) (WAEC)

Acids, Bases And Salts (Ghana Only)

View Answer

Question 47 Report

Use the above option to answer this question. The dehydration of ammonium salt of alkanoic acids produces a compound with the general formula

Answer Details

Read lesson note on Chemistry Of Carbon Compounds (Nigeria Only) (WAEC)

Chemistry Of Carbon Compounds (Nigeria Only)

View Answer






Press & Hold to Drag Around
Click Here to Close