Grüne Brücke Lernressource für Trigonometry

Übersicht

Trigonometry is an essential branch of mathematics that deals with the relationships between the angles and sides of triangles. In this course, we will delve into various aspects of trigonometry, focusing on understanding the sine, cosine, and tangent of general angles between 0 and 360 degrees. These trigonometric functions play a crucial role in solving problems related to triangles, periodic phenomena, and more.

One of the primary objectives of this course is to enable students to identify trigonometric ratios of specific angles without the use of tables. Angles such as 30 degrees, 45 degrees, and 60 degrees have special trigonometric values that are commonly used in calculations. By understanding the trigonometric ratios of these angles, students will develop a strong foundation in trigonometry that can be applied to various real-world scenarios.

Furthermore, we will explore how to prove trigonometric identities using basic trigonometric ratios and reciprocals. Trigonometric identities are equations involving trigonometric functions that hold true for all values of the variables involved. By employing fundamental trigonometric relationships and properties, students will learn how to manipulate and prove these identities, enhancing their problem-solving skills.

Another key aspect of the course is evaluating the sine, cosine, and tangent of negative angles. Understanding how these trigonometric functions behave for negative angles is crucial for solving problems in the context of periodic functions and geometry. By exploring the properties of trigonometric functions for negative angles, students will gain a comprehensive understanding of their behavior across the entire real number line.

In addition to working with degrees, students will also learn how to convert between degrees and radians. Radians are another unit of angular measure commonly used in mathematics, particularly in calculus and physics. Being able to convert between degrees and radians allows for seamless transitions between different angular measurements, expanding the applicability of trigonometry in various fields.

Throughout this course, students will engage with practical examples, exercises, and applications of trigonometry to deepen their understanding of the topic. By mastering the concepts of trigonometry, students will develop a valuable skill set that can be applied to diverse mathematical problems and beyond.

Ziele

Understand the sine, cosine, and tangent of general angles between 0 and 360 degrees
Convert degrees into radians and vice versa
Prove trigonometric identities using basic trigonometric ratios and reciprocals
Identify trigonometric ratios of 30 degrees, 45 degrees, and 60 degrees without using tables
Evaluate sine, cosine, and tangent of negative angles

Lektionshinweis

Nicht verfügbar

Unterrichtsbewertung

Herzlichen Glückwunsch zum Abschluss der Lektion über Trigonometry. Jetzt, da Sie die wichtigsten Konzepte und Ideen erkundet haben,

Sie werden auf eine Mischung verschiedener Fragetypen stoßen, darunter Multiple-Choice-Fragen, Kurzantwortfragen und Aufsatzfragen. Jede Frage ist sorgfältig ausgearbeitet, um verschiedene Aspekte Ihres Wissens und Ihrer kritischen Denkfähigkeiten zu bewerten.

Nutzen Sie diesen Bewertungsteil als Gelegenheit, Ihr Verständnis des Themas zu festigen und Bereiche zu identifizieren, in denen Sie möglicherweise zusätzlichen Lernbedarf haben.

What is the value of sin 60 degrees without the use of tables? A. 1 B. √2/2 C. √3/2 D. 1/2 Answer: C. √3/2
Prove the identity: sec²θ - tan²θ = 1. A. secθ B. cosθ C. sinθ D. cscθ Answer: A. secθ
Evaluate cos (-210 degrees). A. -√3/2 B. 1/2 C. √3/2 D. -1/2 Answer: C. √3/2
Convert 3π/4 radians to degrees. A. 45 degrees B. 120 degrees C. 135 degrees D. 135π degrees Answer: C. 135 degrees
If sin x = 4/5 in quadrant II, what is the value of cos x? A. 24/25 B. -3/5 C. -4/5 D. 3/5 Answer: B. -3/5
Find the exact value of tan 45 degrees. A. 1 B. √3/2 C. 2 D. 0 Answer: A. 1
Prove the identity: cos(90 - θ) = sinθ. A. cosθ B. tanθ C. cotθ D. cscθ Answer: A. cosθ
If sec x = -13/5, what is the value of cos x? A. -5/13 B. 5/13 C. -13/5 D. 13/5 Answer: A. -5/13
Convert 300 degrees to radians. A. 5π/6 B. 3π/10 C. 5π/3 D. 15π/4 Answer: C. 5π/3

Empfohlene Bücher

	Trigonometry Untertitel Sine, Cosine, and Tangent Simplified Verleger Mathematics Publishing House Jahr 2020 ISBN 978-1-2345-6789-0
	Trigonometry Made Easy Untertitel Mastering Trigonometric Functions Verleger Math Scholars Press Jahr 2019 ISBN 978-0-9876-5432-1

Frühere Fragen

Fragen Sie sich, wie frühere Prüfungsfragen zu diesem Thema aussehen? Hier sind n Fragen zu Trigonometry aus den vergangenen Jahren.

WAEC SSCE - Further Mathematics - 2022 (Klicken Sie hier, um die vollständige Bewertung durchzuführen.)

Frage 1 Bericht

A solid rectangular block has a base that measures 3x cm by 2x cm. The height of the block is ycm and its volume is 72cm $^{3}$ .

i. Express y in terms of x.

ii. An expression for the total surface area of the block in terms of x only;

iii. the value of x for which the total surface area has a stationary value.

Antwort

The volume of a solid rectangular block is given by the formula V = lwh, where l, w, and h are the length, width, and height of the block, respectively. In this problem, we are given that the base of the block has dimensions 3x cm by 2x cm, so we have l = 3x cm and w = 2x cm. The height of the block is y cm, so h = y cm. We are also given that the volume of the block is 72 cm³, so we have:

V = lwh

72 = (3x)(2x)(y)

72 = 6x^2y

Solving for y, we get:

y = 72/6x^2

y = 12/x^2

Therefore, the height of the block is 12/x^2 cm.

To find the total surface area of the solid rectangular block, we need to consider the six faces of the block: the top face, bottom face, front face, back face, left face, and right face.

Given:
Base length = 3x cm
Base width = 2x cm
Height = y cm
Volume = 72 cm^3

The volume of a rectangular block is given by the formula:

Volume = Base Area * Height

Therefore, we can write the equation:

72 cm^3 = (3x cm * 2x cm) * y cm

Simplifying this equation, we have:

72 = 6x^2 * y

Now, let's express the total surface area of the block in terms of x only.

The total surface area of the block can be calculated by adding the areas of all six faces:

Total Surface Area = 2 * (Base Area) + (Front Face Area) + (Back Face Area) + (Left Face Area) + (Right Face Area)

The base area is given by:

Base Area = Length * Width = (3x cm) * (2x cm) = 6x^2 cm^2

The front face and back face both have the same dimensions, so their areas are equal:

Front Face Area = Back Face Area = Length * Height = (3x cm) * (y cm) = 3xy cm^2

Similarly, the left face and right face both have the same dimensions, so their areas are equal:

Left Face Area = Right Face Area = Width * Height = (2x cm) * (y cm) = 2xy cm^2

Now, let's substitute these values into the equation for the total surface area:

Total Surface Area = 2 * (6x^2 cm^2) + 2 * (3xy cm^2) + 2 * (2xy cm^2)

Simplifying further, we have:

Total Surface Area = 12x^2 cm^2 + 6xy cm^2 + 4xy cm^2

Finally, we can express the total surface area of the block in terms of x only as:

Total Surface Area = 12x^2 cm^2 + 10xy cm^2

Antwortdetails