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Question 1 Report
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The diagram given, represents the graph of stress against strain for an elastic wire. The point Q on the graph is the
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Question 15 Report
The diagram given illustrates a force-distance graph for the motion of a wooden block. Determine the work done on the block when moved through a distance of 5m.
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Question 16 Report
In a p-type semiconductor, the?
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A ball is dropped from the top of a tower. Due to air resistance,it reaches terminal velocity. Which of the following statement(s) about its motion is/are correct? i. The acceleration of the ball is zero. ii. The net force on the ball is zero. iii. The velocity of the ball increases.
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Question 20 Report
Two magnets are used to magnetize a soft iron bar PQ as illustrated in the diagram given. The correct polarity at P and Q respectively
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Question 22 Report
An aluminium rod of length 1.8m at 10°C is heated to proceed produce a difference in length of 0.007m. Calculate the temperature to which it is heated. (Linear expansivity of aluminium = 2.3 x 10\(^{-5}\)K\(^{-1}\)
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Question 26 Report
X-rays and infrared rays are both electromagnetic. Which common property do the waves have? Both waves
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Question 33 Report
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The resistance of a conductor is given by the formula:
R = ρL/A
where R is resistance, ρ (rho) is resistivity, L is the length of the conductor, and A is the cross-sectional area of the conductor.
We are given the resistance of the cable (R = 21 Ω), its diameter (d = 4 x 10-3 m), and its resistivity (ρ = 3.0 x 10-8 Ωm). We can use the diameter to find the cross-sectional area of the cable, using the formula:
A = πd2/4
Substituting the given values:
A = π x (4 x 10-3)2/4 = 1.26 x 10-5 m2
Now we can rearrange the formula for resistance to solve for the length of the cable (L):
L = RA/ρ
Substituting the given values:
L = 21 x 1.26 x 10-5 / 3.0 x 10-8
Simplifying the expression, we get:
L = 8.82 x 103 m
Therefore, the length of the cable is 8.82 x 103 m.
So the correct answer is) 8.8 x 103 m.
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Question 36 Report
A plank is placed along the path on which a wheel barrow containing sand is pushed at a construction site to prevent it from sticking as illustrated in the diagram given. The large area of the plank prevents the wheel barrow from getting stuck by
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Question 40 Report
The diagram given illustrates the waveform of a note produced by vibrations in an air column of length L. If the speed of sound in air is V, derive an expression for the frequency of the notes
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Question 42 Report
A uniform metre rule is balanced on a fulcrum placed at the 35cm mark by suspending a mass of 120g at the 10cm mark. Calculate the mass of the metre rule.
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In the given radioactive decay equation, beta decay occurs when a neutron in the nucleus of Hg-198 is converted into a proton, causing the atomic number to increase by one and the atomic mass to remain the same. In beta decay, a high-energy electron is emitted from the nucleus.
The equation for beta decay is:
n → p + e- + anti-νe
where n represents a neutron, p represents a proton, e- represents an electron, and anti-νe represents an antineutrino.
Therefore, in the given decay equation, one beta particle (electron) will be emitted as a neutron is converted to a proton.
Hence, the answer is 1.
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