Current Electricity

Which of the following is a type of wave that is both mechanical and longitudinal?

Answer Details

A wave that is both mechanical and longitudinal is sound waves.

Sound waves are created by the vibration of an object, such as a speaker, which causes the air particles around it to vibrate. These vibrations then travel through the air in the form of a wave.

Sound waves are classified as mechanical waves because they require a medium, such as air, water, or solid objects, to travel through. Without a medium, sound waves cannot propagate.

Furthermore, sound waves are classified as longitudinal waves because the particles in the medium vibrate parallel to the direction of the wave. This means that as the sound wave travels, the particles in the medium move back and forth in the same direction as the wave itself.

In contrast, water waves and seismic waves are mechanical waves, but they are not longitudinal. Water waves are categorized as transverse waves because the particles in the water move up and down at right angles to the direction of the wave. Seismic waves, which include earthquake waves, can be both transverse and longitudinal, but typically the primary seismic waves are classified as transverse waves.

Lastly, light waves are not mechanical waves but rather electromagnetic waves. They do not require a medium to travel through and can propagate in a vacuum, unlike sound waves.

You are provided with a battery of e.m.f, E, a standard resistor, R, of resistance 2 Ω $\mathrm{\Omega }$, a key, K, an ammeter, A, a jockey, J, a potentiometer, UV, and some connecting wires.

(i) Measure and record the emf, E, of the battery.

(ii) Set up the circuit as shown in the diagram above with the key open.

(iii) Place the jockey at the point, U, of the potentiometer wire. Close the key and record the reading, i, of the ammeter.

(iv) Place the jockey at a point T on the potentiometer wire UV such that d = UT = 30.0 cm.

(v) Close the circuit, read and record the current, I, on the ammeter,

(vi) Evaluate I1 ${}^1$.

(vi) Repeat the experiment for four other values of d = 40.0 cm, 50.0 cm, 60.0 cm and 70.0 cm. In each case, record I and evaluate I1 ${}^1$.

(vii) Tabulate the results

(ix) Plot a graph with d on the vertical axis and I on the horizontal axis stalling both axes from the origin (0,0).

(x) Determine the slope, s, of the graph.

(xi) From the graph determine the value I1 ${}_1$, of I when d = 0. (ci) Given that=s, calculate 8.

(xii) State two precautions taken to ensure accurate results.

(xii) Given that Eδ $\frac{�}{�}$ = s, calculate δ $�$.

(b)(i) Write down the equation that connects the resistance, R, of a wire and the factors on which it depends. State the meaning of each of the symbols.

(ii) An electric fan draws a current of0.75 A in a 240 V circuit. Calculate the cost of using, the fan for 10 hours if the utility rate is $ 0.50 per kWh.

Answer Details

(a) OBSERVATIONS

(i) Value of E correctly read and recorded to at least 1 d.p in volts.

(ii) Value of i correctly read and recorded to at least 1 d.pin amperes.

(iii) Five values of d correctly determined and recorded to at least 1 d.p in cm.

(iv) Five values of I correctly read and recorded to at least 1 d.p in amperes and in trend.
Trend;  As d increases, I decreases

(v) Five values of I1 ${}^1$ correctly evaluated to at least 3 s.f.

(vi) Composite table showing at least d, I, and I−1 ${}^{-1}$.

(ii) P = IV

Power P = 240×0.75100 $\frac{240\times 0.75}{100}$

0.18kw

Energy consumed in 10hr =  0.18 x 10

= 1.8kWh

Cost of energy = 1.8 x 0.5 = $0.9

OR 

Cost of energy = P x cost x time100 $\frac{\text{<br>}}{}$

0.7×240×101000 $\frac{\mathrm{<br>}}{}$

=  $0.9