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JAMB UTME - Physics - 1985

Question 1 Report

Two rays of light from a point below the surface of water are equally inclined to each other at \(60^\circ\) in water. What is the angle between the rays when they emerge into air? (Take the refractive index of water to be \(\frac{4}{3}\))

Answer Details
4 3  =  s i n r 1 s i n 30  and  4 3  =  s i n r 2 s i n 30

r1 = 41.8o and r2 = 41.8o

angle between them = r1 + r2

= 83.6o