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JAMB UTME - Physics - 1997

Question 1 Report

The electromagnetic waves that are sensitive to temperature changes are

X-rays

Gamma-rays

Ultra-violet rays

Infra-red rays

Answer Details

The electromagnetic waves that are sensitive to temperature changes are the infra-red rays. Infra-red radiation is a type of electromagnetic radiation that is invisible to the human eye but can be felt as heat. All objects with a temperature above absolute zero emit infrared radiation, and the amount of radiation increases as the temperature of the object increases. This property of infra-red radiation makes it useful for detecting temperature changes in a wide range of applications, including thermal imaging cameras, temperature sensors, and heat-seeking missiles.

Read lesson note on Description Property Of Fields (WAEC)

Read lesson note on Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum (WAEC)

Read lesson note on Light Waves (WAEC)

Description Property Of Fields

Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum

Light Waves

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Question 4 Report

The distance xm travelled by a particle in time t seconds is described by the equation x = 10 + 12t2, Find the average speed of the particle between the time interval t = 2s and t = 5s

60 ms-1

72 ms-1

84 ms-1

108 ms-1

Answer Details

speed =

\frac{d x}{d t}

$\frac{d x}{d t}$ = 10 + 12t2

$\frac{d x}{d t}$ = 24t

$\frac{d x}{d t}$ =24 x 3

$\frac{d x}{d t}$ = 72 ms-1

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Question 5 Report

Under constant tension and constant mass per unit length, the note produced by a plucked string is 500Hz when the length of the string is 0.90m. At what length is the frequency 150Hz?

3m

4m

5m

6m

Answer Details

F =

\frac{1}{2 L}

\sqrt{\frac{T}{m}}

F1L1 = F2L2

500 x 0.9 = 150 x L2

therefore, L2 = 3m

Read lesson note on Motion (JAMB)

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Question 8 Report

Three electric cells each of e.m.f 1.5V and internal resistance of 1.0 \(\Omega\) are connected in parallel across an external resistance of \(\frac{2}{3}\Omega\). Calculate the value of the current in the resistor

0.5 A

0.9A

1.5A

4.5A

Answer Details

E.m.f = 1.5

r = $\frac{1 \times 1 \times 1}{(1 \times 1) + (1 \times 1) + (1 \times 1)}$

r = $\frac{1}{3}$ $Ω$

I = $\frac{E . m . f}{r + R}$

I = $\frac{1.5}{\frac{1}{3} + \frac{2}{3}}$

I = 1.5A

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Current Electricity

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Question 10 Report

In a meter bridge experiment, two resistor \(2\Omega\) and \(3\Omega\) occupy the left and right gaps respectively. Find the balance point from the left side of the bridge

20cm

40cm

60cm

80cm

Answer Details

Let the point be x

$\frac{2}{x}$ = $\frac{3}{100 - x}$

making x subject of formula,

2(100 - x) = 3x

200 - 2x = 3x

200 = 3x + 2x

200 = 5x

divide both side by 5

x = 40cm

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Equilibrium Of Forces

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Question 11 Report

The length of mercury thread when it is at 0^oC, 100^oC and at an unknown temperature \( \theta \) is 25mm, 225mm and 175mm respectively. The value of \( \theta \) is

85.0oC

80.0oC

75.0oC

70.0oC

Answer Details

\frac{θ - 0}{100 - 0}

=

\frac{175 - 25}{225 - 25}

$θ$ = 75.0oC

Read lesson note on Measurements And Units (JAMB)

Measurements And Units

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Question 12 Report

A body of mass 2kg moving vertically upwards has its velocity increased uniformly from 10ms-1 to 40ms-1 in 4s. Neglecting air resistance, calculate the upward vertical force acting on the body.[g = 10 ms-1]

15N

20N

35N

45N

Answer Details

F = mg + ma

F = 2 [10 + $\frac{(40 - 10)}{4}$ ]

F = 35 N

Read lesson note on Scalars And Vectors (WAEC)

Scalars And Vectors

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Question 18 Report

The voltage of the domestic electric supply is represented by the equation \(V = 311 \sin 314.2t\). Determine the frequency of the a.c. supply \([\pi = 3.142]\)

50.0Hz

100.0Hz

311.0Hz

314.2Hz

Answer Details

V = 311 sin314.2t compare with,

V = V sin2 $π$ Ft

2 $μ$ F = 314.2

F = $\frac{314.2}{2 \times 3.142}$

F = 50Hz

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Question 23 Report

A planet has mass m1 and is at a distance r, from the sun. A second planet has mass m2 = 10m1 and at a distance of r2 = 2r1 from the sun. Determine the ratio of the gravitational force experienced by the planets.

1 : 5

2 : 5

3 : 5

4 : 5

Answer Details

g =

\frac{G M}{R^{2}}

$\frac{G_{1} M_{1}}{r_{1}^{2}}$ = $\frac{G_{2} M_{2}}{r_{2}^{2}}$

$\frac{G_{1} M_{1}}{r_{1}^{2}}$ = $\frac{G_{2} \times 10 M_{1}}{(2 r_{1})^{2}}$

$\frac{G_{1}}{G_{2}}$ = $\frac{2}{5}$

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Gravitational Field

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Question 24 Report

Two bodies X and Y are projected on the same horizontal plane, with the same initial speed but at angles 30 and 60 respectively to the horizontal. Neglecting air resistance, the ratio of the range of X to that of Y is

1:1

1:2

√3:1

√3

Answer Details

Range =

\frac{U^{2} s i n 2 θ}{g}

$\frac{R_{x}}{R_{y}}$ = $\frac{U_{x}^{2} s i n 60}{U_{y}^{2} s i n 120}$

sin60o = sin120o

$\frac{R_{x}}{R_{y}}$ = $\frac{1}{1}$

hence, = 1:1

Read lesson note on Motion (JAMB)

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Question 25 Report

In the diagram above, which of the angles \( \theta_1 \), \( \theta_2 \), \( \theta_3 \) and \( \theta_4 \) is the angle of deviation of the ray of light passing through the glass prism XYZ?

θ3

θ2

θ_{1}

θ4

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Question 42 Report

An electric water pump rate 1.5 kW, lifts 200kg of water through a vertical height of 6 meters in seconds. What is the efficiency of the pump? [g = 10ms-2, neglecting air resistance]

90.0%

85.0%

80.0%

65.0%

Answer Details

Efficiency = output x 100

= $\frac{\frac{200 \times 10 \times θ}{10}}{1500}$ x $\frac{100}{1}$

= 80%

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Electrical Energy And Power

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Question 45 Report

An object of mass 100g projected vertically upwards from the ground level has a velocity of 20ms-1 at a height of 10m. calculate its initial kinetic energy at the ground level.[g = 10ms-2, neglect air resistance]

10 J

20 J

30 J

50 J

Answer Details

Using, v2 = u2 - 2gx

(20)2 = u21/2 x 10 x 10

u2 = 600(m/s)2

initial K.E = - mu2

= $\frac{1}{2}$ x 600

= 30 J

Read lesson note on Scalars And Vectors (WAEC)

Scalars And Vectors

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