WAEC SSCE - Chemistry - 2013
Tambaya 1 Rahoto
Which of the following bond types is responsible for the high boiling point of water?
Bayanin Amsa
The bond responsible for the high boiling point of water is the hydrogen bond. A hydrogen bond is a type of dipole-dipole interaction that occurs when a hydrogen atom bonded to an electronegative atom (such as oxygen or nitrogen) in one molecule is attracted to an electronegative atom in another molecule. In water, the hydrogen atoms of one water molecule are attracted to the oxygen atom of another water molecule through hydrogen bonds, creating a network of intermolecular attractions. These hydrogen bonds require a large amount of energy to break, resulting in a high boiling point for water compared to similar-sized molecules with only London dispersion or dipole-dipole interactions.
Tambaya 3 Rahoto
Consider the redox reaction as represented by the following equation: 12(aq) + 2S2O32-(aq) → 21-(aq) + S4O62-(aq). Which of the species in the equation is reduced?
Bayanin Amsa
Tambaya 4 Rahoto
Which of the following statements about nuclear reaction is correct? The reaction
Bayanin Amsa
The statement that is correct about nuclear reactions is "takes place inside the nucleus." A nuclear reaction involves changes in the nucleus of an atom, where protons and/or neutrons can be added or removed. This process can result in the formation of a new element or the release of energy in the form of radiation. These reactions can occur spontaneously or be induced by high-energy particles such as neutrons or protons. Unlike chemical reactions, nuclear reactions are not affected by temperature or pressure and involve only particles within the nucleus, such as protons and neutrons, but not electrons.
Tambaya 5 Rahoto
The pressure exerted by a gas is a function of the
Bayanin Amsa
The pressure exerted by a gas is a function of the frequency of collision between gaseous molecules. When gas molecules move, they collide with one another and with the walls of their container. These collisions create a force that is distributed over the area of the container, which is the pressure of the gas. The more often these collisions occur, the higher the pressure of the gas. Therefore, the pressure of a gas is directly proportional to the frequency of collision between its molecules. The total volume of the gas, the speed of the gaseous molecules, and the mass of each gaseous molecule can affect the frequency of collision between gaseous molecules, but they are not the primary factors that determine the pressure of the gas.
Tambaya 6 Rahoto
Which of the following organic compounds would decolourize bromie water?
Bayanin Amsa
Tambaya 7 Rahoto
Which of the following compounds crystallizes without water of crystallization?
Bayanin Amsa
The compound that crystallizes without water of crystallization is sodium chloride (NaCl). When a compound crystallizes, it can trap water molecules within the crystal lattice, forming a hydrated compound. These water molecules are called water of crystallization. However, NaCl is an ionic compound that does not have water of crystallization. This is because ionic compounds do not have a defined molecular structure that can incorporate water molecules. NaCl is formed by the ionic bond between sodium and chloride ions. Therefore, when it crystallizes, it does not include any water molecules in the crystal structure. On the other hand, the other compounds listed have a defined molecular structure that can incorporate water molecules in the crystal lattice, forming hydrated compounds. For example, magnesium sulfate (MgSO4) can crystallize with 7 water molecules in the lattice, forming MgSO4·7H2O. Sodium carbonate (Na2CO3) can crystallize with 10 water molecules, forming Na2CO3·10H2O. Iron(II) sulfate (FeSO4) can crystallize with 7 water molecules, forming FeSO4·7H2O.
Tambaya 8 Rahoto
Consider the reaction represented by the equation: N2O4(g) ⇌ 2NO2(g) ; ∆H = + x kJmol-1
What happens when the temperature is reduced at equilibrium?
Tambaya 9 Rahoto
Consider the reaction represented by the following equation: C\(_2\)H\(_2\) + yH\(_2\) → C\(_2\)H\(_6\). The value of y in the reaction is
Bayanin Amsa
In the given reaction, C\(_2\)H\(_2\) and H\(_2\) react to form C\(_2\)H\(_6\). The molecular formula of C\(_2\)H\(_2\) is C\(_2\)H\(_2\) and that of H\(_2\) is H\(_2\). The molecular formula of C\(_2\)H\(_6\) is C\(_2\)H\(_6\). Therefore, we can write the balanced chemical equation as: C\(_2\)H\(_2\) + 2H\(_2\) → C\(_2\)H\(_6\) We can see that for every one mole of C\(_2\)H\(_2\) used in the reaction, two moles of H\(_2\) are required. Therefore, the value of y in the equation is 2. So, the correct option is (C) 2.
Tambaya 10 Rahoto
Rare gases are stable because they
Bayanin Amsa
Rare gases, also known as noble gases, are stable because they have a complete outermost shell of electrons. In other words, they have octet structures, meaning they have eight electrons in their outermost energy level, with the exception of helium, which has two electrons in its outermost energy level. This full outer shell makes them highly unreactive, since they have no need to gain or lose electrons to achieve a more stable configuration. Therefore, rare gases do not readily form chemical bonds with other elements, making them very stable.
Tambaya 11 Rahoto
The separation of petroleum fractions depends on the differences in their
Bayanin Amsa
The separation of petroleum fractions depends on the differences in their boiling points. Petroleum is a mixture of hydrocarbons with different boiling points, ranging from gases to heavy liquids. In order to separate these different components, petroleum is heated to vaporize the liquid, and then the vapor is cooled to condense the different fractions. The fractions are then collected at different points in the cooling process, based on their boiling points. This process of separation is known as fractional distillation, and it is the most common method for separating petroleum fractions. The boiling point of each fraction depends on the length of the hydrocarbon chain and the degree of branching or saturation, which determine the strength of the intermolecular forces and the thermal stability of the molecules. Therefore, the boiling points of the fractions increase with increasing molecular weight and decreasing volatility.
Tambaya 12 Rahoto
Bronze is a mixture of
Bayanin Amsa
Bronze is an alloy that is primarily composed of copper (Cu) with the addition of other metals to give it specific properties. The exact composition of bronze can vary depending on its intended use, but typically it contains a mixture of copper with one or more additional metals. Out of the given options, only one contains copper as a component, and that is "Cu and X," where X represents the other metal. - Cu and Mg: This mixture is not bronze because magnesium (Mg) is not typically added to copper to create bronze. - Cu and Sn: This mixture is commonly referred to as tin bronze and is often used for making musical instruments, statues, and other decorative objects. - Cu and Zn: This mixture is commonly referred to as brass and is often used for making musical instruments, door knobs, and other household items. - Cu and Pb: This mixture is not commonly used to make bronze, but it can be used to create other alloys such as leaded bronze. Therefore, the correct answer is "Cu and Sn," meaning that bronze is a mixture of copper and tin.
Tambaya 13 Rahoto
Which of the following variables is a measure of the average kinetic energy of the molecule of a gas?
Bayanin Amsa
The variable that is a measure of the average kinetic energy of the molecules of a gas is temperature. Temperature is a measure of the average kinetic energy of the particles in a substance, including gas molecules. The higher the temperature, the higher the kinetic energy of the gas molecules, and the faster they move. Therefore, temperature is a crucial variable to consider when dealing with gases, as it affects their behavior, such as their pressure and volume.
Tambaya 14 Rahoto
Which of the following statements about thermoplastic material is correct? They
Bayanin Amsa
Thermoplastic materials soften and melt on heating. This means that they can be heated, molded into different shapes, and cooled to form a solid. Unlike thermosetting plastics, which harden irreversibly on heating and cannot be remolded, thermoplastics can be remolded multiple times without any change in their chemical structure. Therefore, the correct statement about thermoplastic materials is that they soften and melt on heating.
Tambaya 15 Rahoto
Which of the following halogens is liquid at room temperature?
Bayanin Amsa
The halogen that is liquid at room temperature is Bromine. Bromine is a reddish-brown liquid with a boiling point of 58.8°C, which is lower than room temperature (typically around 20-25°C). This means that bromine is in its liquid state at room temperature. In contrast, fluorine and chlorine are gases at room temperature, while iodine is a solid. Bromine is the only halogen that is a liquid at room temperature.
Tambaya 16 Rahoto
Which of the following reactions is common to all hydrocarbones?
Bayanin Amsa
The common reaction to all hydrocarbons is combustion. Combustion is a chemical reaction between hydrocarbons and oxygen, which results in the production of carbon dioxide and water. This reaction is common to all hydrocarbons regardless of their structure, functional group, or size. Therefore, the correct answer is combustion.
Tambaya 17 Rahoto
Which of the following gases are arranged in increasing order of diffusion rate? [H = 1 .0; C = 12; N = 14; O = 16; S = 32]
Bayanin Amsa
The rate of diffusion is inversely proportional to the molar mass of the gas, which means that the lighter the gas, the faster it will diffuse. Therefore, to arrange the given gases in increasing order of diffusion rate, we need to arrange them in decreasing order of their molar mass. Let's calculate the molar mass of each gas: - SO2: 32 + 2(16) = 64 - O2: 2(16) = 32 - NH3: 14 + 3(1) = 17 - H2: 2(1) = 2 - H2S: 2 + 32 = 34 - NH2: 14 + 2(1) = 16 - CO2: 12 + 2(16) = 44 - N2O: 2(14) + 16 = 44 - NO2: 14 + 2(16) = 46 - CO2: 12 + 2(16) = 44 Now, let's arrange the gases in decreasing order of their molar mass: - H2, NH3, O2, SO2 - NH2, H2S, O2, SO2 - CO2, N2O, O2, SO2 - CO2, N2, NO2, NH3 Therefore, the correct answer is the first option: SO2 < O2 < NH3 < H2.
Tambaya 18 Rahoto
The major product formed by the reaction between ethanoic acid and aqueous sodium hydroxide is
Bayanin Amsa
The major product formed by the reaction between ethanoic acid and aqueous sodium hydroxide is sodium ethanoate, which is a salt. When ethanoic acid reacts with aqueous sodium hydroxide, the acid-base neutralization reaction occurs, and the products are sodium ethanoate (the salt) and water. Sodium hydroxide is a strong base, and ethanoic acid is a weak acid, so the reaction favors the formation of the salt. The reaction can be represented by the following chemical equation: CH\(_3\)COOH + NaOH → CH\(_3\)COONa + H\(_2\)O Therefore, the major product of the reaction is sodium ethanoate, and the other product is water.
Tambaya 19 Rahoto
The percentage by mass of calcium in Ca(OCI)2 is [Ca = 40.0; CI = 35.5; O = 16.0]
Bayanin Amsa
To calculate the percentage by mass of calcium in Ca(OCl)2, we need to first find the molar mass of the compound, which is the sum of the atomic masses of its elements. Molar mass of Ca(OCl)2 = (1 × atomic mass of Ca) + (2 × atomic mass of O) + (2 × atomic mass of Cl) = (1 × 40.0) + (2 × 16.0) + (2 × 35.5) = 142.0 g/mol Next, we need to find the mass of calcium in one mole of Ca(OCl)2. Mass of calcium = (1 × atomic mass of Ca) = 40.0 g/mol Finally, we can calculate the percentage by mass of calcium in Ca(OCl)2 by dividing the mass of calcium by the molar mass of the compound and multiplying by 100. Percentage by mass of calcium in Ca(OCl)2 = (mass of calcium / molar mass of Ca(OCl)2) × 100 = (40.0 / 142.0) × 100 = 28.2% (rounded to one decimal place) Therefore, the correct answer is (A) 28.0%.
Tambaya 20 Rahoto
The molecule which has a linear shape is
Bayanin Amsa
The molecule which has a linear shape is CO2. CO2 has a linear shape because it consists of two identical oxygen atoms bonded to a central carbon atom by double bonds. The carbon atom is located in the center of the molecule and the oxygen atoms are arranged symmetrically on either side. This symmetrical arrangement of atoms results in a linear shape for the molecule.
Tambaya 21 Rahoto
Which of the following phenomenna lead to decrease in volume of a liquid in an open container?
Bayanin Amsa
Evaporation leads to decrease in volume of a liquid in an open container. This is because during evaporation, the molecules at the surface of the liquid gain enough kinetic energy to overcome the intermolecular forces of attraction and escape into the atmosphere as vapour. As a result, the total number of molecules in the liquid decreases and the volume of the liquid decreases as well. This process continues until the rate of evaporation equals the rate of condensation, at which point the liquid reaches equilibrium with the surrounding atmosphere.
Tambaya 22 Rahoto
A hydrocarbon compound contains 92.3% carbon Determine its empirical formula [H = 1.00; C = 12.0]
Bayanin Amsa
To determine the empirical formula of a hydrocarbon compound, we need to know the percentage composition of each element in the compound. In this case, we are given that the compound contains 92.3% carbon, which means that the remaining percentage (100 - 92.3 = 7.7%) must be hydrogen. To calculate the empirical formula, we need to convert the percentages to mole ratios. Assuming a 100 g sample of the compound, we have 92.3 g of carbon and 7.7 g of hydrogen. The next step is to convert the masses of each element to moles. We use the molar masses of carbon and hydrogen (12.0 g/mol and 1.00 g/mol, respectively) to calculate the number of moles of each element: - Moles of carbon = 92.3 g / 12.0 g/mol = 7.69 mol - Moles of hydrogen = 7.7 g / 1.00 g/mol = 7.7 mol To get the simplest whole-number ratio of carbon to hydrogen, we divide each number of moles by the smallest number of moles (7.69 mol in this case): - Carbon: 7.69 mol / 7.69 mol = 1.00 - Hydrogen: 7.7 mol / 7.69 mol = 1.00 Therefore, the empirical formula of the hydrocarbon compound is CH, which corresponds to.
Tambaya 23 Rahoto
The element with electron configuration 1s\(^2\) 2s\(^2\) 2p\(^6\) 3s\(^2\) 3p\(^1\) belongs to
Bayanin Amsa
The electron configuration of an element indicates the distribution of its electrons among the energy levels and orbitals. In this case, the element has 2 electrons in the 1s orbital, 2 electrons in the 2s orbital, 6 electrons in the 2p orbital, 2 electrons in the 3s orbital, and 1 electron in the 3p orbital. Based on this configuration, we can determine that the element belongs to the p-block of the periodic table, specifically to period 3 and group 3, which contains the elements Boron (B), Aluminum (Al), Gallium (Ga), Indium (In), and Thallium (Tl).
Tambaya 24 Rahoto
Which of the following elements is diatomic?
Bayanin Amsa
The term "diatomic" refers to an element that can exist as a molecule composed of two atoms. Out of the options given, only oxygen is diatomic, existing as O2. Sodium exists as a single atom (Na), iron as a solid metal, and neon as a noble gas with single atoms. Therefore, the correct answer is Oxygen.
Tambaya 25 Rahoto
The gas law which describes the relationship between volume and temperature is
Bayanin Amsa
The gas law which describes the relationship between volume and temperature is Charles' law. According to Charles' law, the volume of a gas is directly proportional to its temperature (in Kelvin) at constant pressure and amount of gas. As the temperature of a gas increases, its volume also increases proportionally, and as the temperature decreases, the volume also decreases proportionally. This law is commonly expressed as V/T = constant or V1/T1 = V2/T2, where V is the volume, T is the temperature, and the subscripts 1 and 2 refer to two different conditions.
Tambaya 26 Rahoto
An atom of an element X gains two electrons. The symbol of the ion formed is
Bayanin Amsa
When an atom gains electrons, it becomes negatively charged, because electrons have a negative charge. The number of electrons gained is equal to the difference between the number of protons and the number of electrons. In this case, the atom of element X gains two electrons, so its charge will be -2. The symbol for an ion with a charge of -2 is X 2-. Therefore, the correct answer is.
Tambaya 28 Rahoto
How many isomers has C 3H 6CI 2?
Bayanin Amsa
The number of isomers that C3H6Cl2 can have depends on the possible arrangements of the atoms in the molecule. First, let's consider the number of possible structural isomers that can be formed. Structural isomers are molecules with the same molecular formula but with different arrangements of their atoms. For C3H6Cl2, there are two possible structural isomers: 1,1-dichloropropane and 2,2-dichloropropane. Next, we can consider the possibility of stereoisomers, which are molecules with the same molecular formula and the same structural arrangement of atoms, but with different orientations of atoms in space. However, in C3H6Cl2, there are no chiral centers (carbon atoms with four different substituents), so there are no possible stereoisomers. Therefore, the total number of isomers for C3H6Cl2 is 2
Tambaya 29 Rahoto
The aqueous solution which has pH > 7 is
Bayanin Amsa
The aqueous solution which has pH > 7 is Na\(_2\)CO\(_3(aq)\). pH is a measure of the acidity or basicity of an aqueous solution. A pH of 7 indicates neutrality, while a pH greater than 7 indicates basicity or alkalinity. The pH of a solution is determined by the concentration of hydrogen ions (H\(^+\)) in the solution. In the case of Na\(_2\)CO\(_3(aq)\), it is a basic compound because it has a carbonate ion, which can react with water to form hydroxide ions (OH\(^-\)). The hydroxide ions increase the concentration of hydroxide ions in the solution, which makes the solution basic. The chemical reaction that occurs when Na\(_2\)CO\(_3(aq)\) dissolves in water is: Na\(_2\)CO\(_3(aq)\) + H\(_2\)O → 2Na\(^+\) + CO\(_3^{2-}\) + 2OH\(^-\) The presence of hydroxide ions in the solution makes it basic, and the higher the concentration of hydroxide ions, the higher the pH of the solution. Therefore, Na\(_2\)CO\(_3(aq)\) is the aqueous solution which has pH > 7.
Tambaya 30 Rahoto
Which of the following cells produce electrical energy from chemical reactions?
l. Lead-acid battery ll. Dry cell III. Deniell cell IV Electrolytic cell
Bayanin Amsa
The cells that produce electrical energy from chemical reactions are called electrochemical cells. In an electrochemical cell, a chemical reaction takes place, and the energy released by the reaction is converted into electrical energy. Out of the given options, the lead-acid battery, dry cell, and Daniell cell are all electrochemical cells that produce electrical energy from chemical reactions. The electrolytic cell, on the other hand, is used to drive a non-spontaneous chemical reaction using electrical energy. Therefore, the correct answer is (B) l, ll, and III only.
Tambaya 31 Rahoto
Which of the following acids would readily react with CaCO3 to liberate CO2?
Tambaya 33 Rahoto
Which of the following statements about fine chemical is correct? It
Bayanin Amsa
The correct statement about fine chemical is: it is produced in relatively small amounts. Fine chemicals are complex, pure chemicals produced in smaller quantities than bulk chemicals. They are used as building blocks in the manufacture of various chemical products such as pharmaceuticals, agrochemicals, flavors and fragrances, and specialized materials. Their production involves precise and sophisticated processes that ensure a high degree of purity and quality. Therefore, the other options are incorrect, as fine chemicals are not necessarily injurious to health, they have a high degree of purity, and they may or may not be stored for a long time, depending on their properties and intended use.
Tambaya 34 Rahoto
In which of the following series are the atoms arranged in order of increasing ionization energy?
Bayanin Amsa
Tambaya 35 Rahoto
The volume of 0.25 moldm-3 solution of KOH that would yield 6.5g of of solid KOH on evaporation is (K = 39.0; o = 16.0; H = 1.00)
Bayanin Amsa
The molar mass of KOH (potassium hydroxide) is K + O + H = 39.0 + 16.0 + 1.00 = 56.0 g/mol. To find the amount of KOH needed to yield 6.5g, we divide 6.5 by the molar mass of KOH: 6.5g / 56.0 g/mol = 0.116 mol Since the concentration of KOH is given as 0.25 moldm-3, we can use the formula: concentration (mol/dm3) = amount of substance (mol) / volume (dm3) to find the volume of the solution required: 0.25 mol/dm3 = 0.116 mol / volume (dm3) Solving for volume, we get: volume (dm3) = 0.116 mol / 0.25 mol/dm3 = 0.464 dm3 = 464.30 cm3 Therefore, the answer is 464.30 cm3.
Tambaya 36 Rahoto
Which of the following raw materials is used in a plastic industry?
Bayanin Amsa
Ethene is the raw material used in the plastic industry. Ethene is a colorless gas with a sweet smell and is a type of hydrocarbon that is produced from crude oil and natural gas. It is used as a feedstock in the production of many chemicals, including polyethylene, which is the most widely used plastic in the world. The polymerization of ethene produces polyethylene, which can be molded into various shapes and forms to produce plastic products. Methane is also a hydrocarbon, but it is not commonly used as a raw material in the plastic industry. Calcium and hydrogen are not hydrocarbons and are not used as raw materials in plastic production.
Tambaya 37 Rahoto
The formula of the compound formed between a trivalent metal, M and a divalent non-metal, Y is
Bayanin Amsa
Tambaya 38 Rahoto
Which of the following arrangements represents the correct order of electronic energy level?
Tambaya 39 Rahoto
Which of the following materials is classified as a non-biodegradable pollutant?
Bayanin Amsa
The material classified as a non-biodegradable pollutant is plastic. Plastic does not decompose naturally and takes hundreds of years to break down into smaller fragments, which can persist in the environment and cause harm to wildlife and ecosystems. On the other hand, animal hide, paper, and wood are biodegradable materials that can be broken down naturally by microorganisms in the environment.
Tambaya 40 Rahoto
The main function of limestone in the blast furnace is to
Bayanin Amsa
The main function of limestone in the blast furnace is to remove impurities. When heated, limestone decomposes to form calcium oxide (CaO), which reacts with the impurities (mainly silica and alumina) to form slag. The slag, being less dense than molten iron, floats on top of it and can be easily removed. This process is known as fluxing, and it helps to purify the molten iron. In addition, the limestone also helps to regulate the temperature in the furnace and provides the necessary basicity for the chemical reactions to occur. Therefore, the correct option is: "remove impurity".
Tambaya 41 Rahoto
When heat is absorbed during a chemical reaction, the reaction is said to be
Bayanin Amsa
When heat is absorbed during a chemical reaction, the reaction is said to be endothermic. Endothermic reactions are those that absorb energy from their surroundings in the form of heat, resulting in a decrease in temperature of the surroundings. In an endothermic reaction, the reactants have lower energy than the products, and the difference in energy is absorbed from the surroundings as heat. Examples of endothermic reactions include the process of melting ice, the reaction between baking soda and vinegar, and the reaction between ammonium nitrate and water.
Tambaya 42 Rahoto
In metallic solid, the forces of attraction is between the mobile valence electrons and the
Bayanin Amsa
The question is asking us to identify the particle that the mobile valence electrons in a metallic solid are attracted to. In a metallic solid, the valence electrons are not tightly bound to any particular atom, but rather are free to move throughout the entire solid. These electrons form a "sea" of negatively charged particles that is dispersed throughout the solid. The positive charges in a metallic solid are located in the nuclei of the atoms that make up the solid. Since opposite charges attract each other, the mobile valence electrons are attracted to these positively charged nuclei. Therefore, the correct answer is: "positively charged nuclei".
Tambaya 43 Rahoto
Noble gas molecules are held together by
Bayanin Amsa
Noble gas molecules are held together by van der Waals forces. These forces are weak attractive forces that exist between atoms or molecules due to temporary fluctuations in electron density. In noble gas molecules, the van der Waals forces are the result of the temporary dipoles that form due to the random motion of the electrons in the atoms. These temporary dipoles induce similar dipoles in nearby atoms, leading to weak attractive forces that hold the atoms together in a solid or a liquid state.
Tambaya 44 Rahoto
In the periodic table, alkaline earth metals can be found in group
Bayanin Amsa
Alkaline earth metals can be found in group II of the periodic table. Group II is also known as the alkaline earth metals group, which consists of beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra). These elements are called alkaline earth metals because their oxides and hydroxides are alkaline in nature, and they form basic solutions when dissolved in water.
Tambaya 45 Rahoto
In the periodic table all elements within the same group have the same
Bayanin Amsa
In the periodic table, all elements within the same group have the same number of valence electrons. The periodic table is a systematic arrangement of elements based on their atomic structure. Elements in the same group have the same number of valence electrons, which are the electrons in the outermost energy level of the atom that are involved in chemical reactions. The number of valence electrons determines the chemical properties of an element and its ability to bond with other elements to form compounds. For example, the elements in Group 1 (also called the alkali metals), such as lithium, sodium, and potassium, all have one valence electron. This makes them highly reactive and gives them similar chemical properties. Similarly, the elements in Group 7 (also called the halogens), such as fluorine, chlorine, and bromine, all have seven valence electrons, which also gives them similar chemical properties. In contrast, elements in the same period have the same number of energy levels or shells, but they do not have the same number of valence electrons. For example, oxygen and neon are in the same period, but oxygen has six valence electrons while neon has eight. Therefore, it can be concluded that all elements within the same group have the same number of valence electrons.
Tambaya 46 Rahoto
Which of the following instruments is used in detecting the presence of radiation?
Bayanin Amsa
The instrument used in detecting the presence of radiation is the Geiger-Muller counter. Radiation refers to the emission of energy in the form of particles or waves. This can include gamma rays, beta particles, and alpha particles, among others. The Geiger-Muller counter is a device that is used to detect and measure ionizing radiation, such as alpha and beta particles, gamma rays, and X-rays. The Geiger-Muller counter works by using a gas-filled tube that contains a wire electrode. When ionizing radiation enters the tube, it ionizes the gas atoms, which then cause a cascade of electrons to move toward the wire electrode. This generates a pulse of electrical current that is detected and counted by the device. The number of pulses detected per unit time is proportional to the intensity of the radiation present. Out of the given options, the only instrument used in detecting the presence of radiation is the Geiger-Muller counter. - Cathode ray tube: This instrument is used to generate and manipulate a focused beam of electrons in a vacuum. It is commonly used in televisions and computer monitors. - Mass spectrometer: This instrument is used to determine the mass of individual atoms and molecules in a sample by ionizing them and separating them based on their mass-to-charge ratio. It is commonly used in chemistry and physics research. - X-ray tube: This instrument is used to generate X-rays by accelerating electrons and colliding them with a metal target. X-rays are commonly used in medical imaging. Therefore, the correct answer is the Geiger-Muller counter.
Tambaya 47 Rahoto
The following factors affect the solubility of a solid in a given solvent except
Bayanin Amsa
The solubility of a solid in a given solvent refers to the maximum amount of the solid that can be dissolved in a specific amount of the solvent at a given temperature and pressure. The factors that affect the solubility of a solid in a given solvent are the nature of the solute, nature of the solvent, pressure, and temperature. - Nature of solute: The chemical and physical properties of the solute, such as its molecular size, polarity, and shape, can affect its solubility in a given solvent. For example, a polar solute is more likely to dissolve in a polar solvent, while a nonpolar solute is more likely to dissolve in a nonpolar solvent. - Nature of solvent: The chemical and physical properties of the solvent, such as its polarity and boiling point, can affect its solubility with a specific solute. - Pressure: The solubility of a gas in a liquid is directly proportional to the pressure applied to the system. This is known as Henry's Law. However, the solubility of solids in liquids is not significantly affected by pressure changes. - Temperature: The solubility of most solids in liquids increases as the temperature increases, because higher temperatures increase the kinetic energy of both the solvent molecules and the solute particles. However, for some solutes, such as calcium sulfate, the solubility decreases as the temperature increases. Therefore, the factor that does not affect the solubility of a solid in a given solvent is pressure, as it only significantly affects the solubility of gases in liquids, not solids in liquids.
Tambaya 48 Rahoto
(a)(i) What is the common name given to the group VII elements?
(ii) Name the hydrides of the first two elements in group VII.
(iii) State three chemical properties of group VII elements.
(b) Copy and complete the following table:
| Particles | Number of Neutrons |
Number of electrons |
Number of prontons |
Mass Number |
| W\(^{2+}\) | 12 | 24 | ||
| X\(^{2+}\) | 8 | 16 | ||
| Y | 13 | 27 | ||
| Z | 12 | 11 |
(c)(i) Define each of the followinc processes: I. nuclear fission; II. nuclear fusion.
(ii) Give one use of each process in (c)(i).
(d)(i) List three types of radiation that are produced during radioactivity.
(ii) Arrange the radiations listed in
(d)(i) in order of increasing: I. penetrating power; II. ionizing power.
None
Bayanin Amsa
None
Tambaya 49 Rahoto
TEST OF PRACTICAL KNOWLEDGE QUESTION
Burette readings (initials and final) must be given to two decimal places. Volume of pipette used must also be recorded but no account experimental procedure is required. Al calculations must be done in your answer book. A solution containing 0.05moldm\(^3\) H\(_2\)SO\(_4\). B is a solution containing 1.4g per 250cm\(^3\) .XOH
(a) Put A into the burette and titrate it against 20.0cm\(^3\) or 25.0cm\(^3\) portions of B using methyl orange indicator. Repeat the titration to obtain consistent titres. Tabulate your results and calculate the average volume of A used. The equation for the reaction involved in the titration is; H\(_2\)SO\(_{4(aq)}\) + 2XOH\(_{(aq)}\) \(\to\) X\(_2\)SO\(_{4(aq)}\) + 2H\(_2\)O\(_{(l)}\)
(b) From your results and the information provided above, calculate the;
(i) concentration of B in moldm\(^{-3}\)
(ii) molar mass XOH
(iii) relative atomic mass of X. [H = 1.00; O = 16.0 S =32.0]
Bayanin Amsa
None
Tambaya 50 Rahoto
TEST OF PRACTICAL KNOWLEDGE QUESTION
Credit will be given for strict adherence to the instructions, for observations precisely recorded, and for accurate inferences. AIl tests. observations and inferences must be clearly entered in your answer book, in ink, at the time they are made.
C is a double salt. Carry out the following exercises on C. Record your observations and identify any gas(es) evolved. State the conclusion drawn from the result of each test.
a) Put all of C into a test tube. Add about 5cm\(^3\) of distilled water, stir and test with litmus paper. Divide the Solution into two portions
(b) To the first portion, add sodium hydroxide solution in drops and then in excess. Heat the resulting mixture and keep it for minutes.
(c) To the second portion, add few drops of Bacl\(_{2(aq)}\) followed by excess dilute hydrochloric acid
Tambaya 51 Rahoto
(a)(i) Define the term standard electrode potential.
(ii) State three factors that affect the discharge of ions during electrolysis.
(iii) State two functions of a salt bridge in an electrochemical cell.
(b) Describe briefly what happens when a solution of copper (II) tetraoxosulphate (VI) is electrolyzed using copper electrodes.
c) Calculate the mass of copper deposited at the cathode when a current of 0.2A is passed through a solution of copper (II) tetraoxosulphate (VI) for 35 minutes using copper electrodes. [H = 1.00, O = 16.0, S = 32.0, Cu = 64.0, IF = 96,500C]
(d)(i) State three characteristics of a catalyst.
ii) Name one manufacturing process in which each of the following metals is used as catalyst: I. iron; II. nickel; Ill. platinum.
c-NA
Tambaya 52 Rahoto
(a)(i) Define the term hygroscopic.
(ii) Give two difference: between a physical change and a chemical change.
(iii) Using the kinetic theory of gases, explain briefly the Charles' law.
(b)(i) Arrange the following compounds in order of increasing boiling points: CS\(_2\); CO\(_2\); NaH. Give reasons for your answer.
(ii) Write a balanced chemical equation to illustrate the reaction of chlorine gas with cold dilute sodium hydroxide.
(c) In a certain reaction, 15.0 g of impure magnesium sample reacted with excess hydrochloric acid liberating 8.6 dm\(^2\) of hydrogen gas at s.t.p.
(i) Write a balanced equation for the reaction.
(ii) Calculate the: I. mass of pure magnesium in the sample; I. percentage purity of the magnesium sample; III. number of ions produced in the reaction. [Mg = 24.0; volume at s.t.p. 22.4 dm\(^{-3}\), Avagadro's constant = 6.02 x 10\(^{23}\)mol\(^{-1}\)]
Tambaya 53 Rahoto
(a)(i) List two characteristics of homologous series.
(ii) Consider the compound represented by the following formula: CH\(_3\)(CH\(_2\))\(_2\)CH\(_3\). I. Which homologous series does the compound belong? II. Write the structures of three possible isomers of the coumpound. III Name the three possible isomers in (a)(ii)II.
(b) Write the structure of the major product formed in each of the following reactions: (i) ethanol with excess acidified potassium tetraoxomanganate (VII);
(ii) excess ethane with chlorine in the presence of sunlight;
(iii) ethanol with propanoic acid in the presence of few drops of concentrated tetraoxosulphate(VI) acid.
(c) Name the major product in each reaction in (b).
(d) Consider the following organic compounds:
(i) Give the IUPAC name of each compound.
(ii) State a chemical test for the functional group in each compound.
(e) An organic compound with relative molecular mass 136 contains 70.57% carbon, 5.90% hydrogen and 23.53% oxygen. Determine its: (i) empopirical formula; (ii) molecular formula. [H= 1.00, C= 12.0, H = 16.0]
