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JAMB UTME - Physics - 2013

Question 1 Report

If a pump is capable of lifting 5000kg of water through a vertical height of 60m in 15 min, the power of the pump is
Answer Details
The power of the pump can be calculated using the formula: Power = (Work done)/time where Work done = force x distance In this case, the force is the weight of the water (5000 kg) and the distance is the height to which it is lifted (60 m). We can calculate the work done as: Work done = force x distance = 5000 kg x 9.81 m/s^2 x 60 m (using the acceleration due to gravity, g = 9.81 m/s^2) = 2,943,000 J (joules) The time taken is 15 minutes, which is equivalent to 900 seconds. Therefore, the power of the pump can be calculated as: Power = Work done / time = 2,943,000 J / 900 s = 3270 J/s This answer is not listed among the options. However, we can convert J/s to the more commonly used unit of power, watts (W), by dividing by 1 watt = 1 J/s. Therefore, the power of the pump is: Power = 3270 J/s = 3270 W This answer is not exactly the same as any of the options listed, but it is closest to which is 3.3 x 10^3 J/s or 3,300 W.
Read lesson note on Work, Energy And Power (WAEC)
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