WAEC SSCE - Physics - 1997 (Objective)

Question 1 Report

An object of mass 0.40 kg attached to the end of a string is whirled around in a horizontal circle of radius 2.0m with a constant speed of 8$ms^{-1}$. Calculate the angular velocity of the object

0.8rad$s^{-1}$

2 rad$s^{-1}$

4 rad$s^{-1}$ Correct answer

8 rad$s^{-1}$

16 rad$s^{-1}$

Answer Details

The angular velocity of the object can be found using the formula: ω = v/r where ω is the angular velocity, v is the velocity of the object and r is the radius of the circle. In this case, the velocity of the object is given as 8$ms^{-1}$ and the radius of the circle is given as 2.0m. So, ω = 8$ms^{-1}$/2.0m = 4 rad$s^{-1}$ Therefore, the angular velocity of the object is 4 rad$s^{-1}$. Hence, the correct option is (c) 4 rad$s^{-1}$.






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