WAEC SSCE - General Mathematics - 2019

If 6, P, and 14 are consecutive terms in an Arithmetic Progression (AP), find the value of P.

Detalhes da Resposta

In an arithmetic progression (AP), the difference between any two consecutive terms is constant. So, we can find the common difference (d) between any two consecutive terms in the given AP by subtracting one term from the preceding term. Let's use the second term (P) and the first term (6) to find the common difference: d = P - 6 Now, to check whether 14 is the third term of the AP, we can use the formula for the nth term of an AP: an = a1 + (n-1)d where an = nth term a1 = first term d = common difference If 14 is the third term, then n = 3, so we have: 14 = 6 + (3-1)d 14 = 6 + 2d 2d = 8 d = 4 Now, we can substitute the value of d in the expression we got earlier: d = P - 6 4 = P - 6 P = 10 Therefore, the value of P is 10.

H varies directly as p and inversely as the square of y. If H = 1, p = 8 and y = 2, find H in terms of p and y.

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In the diagram, RT is a tangent to the circle at R, < PQR = 70\(^o\), < QRT = 52\(^o\), < QSR and < PRQ = x.  Calculate the variance of 2, 4, 7, 8 and 9 

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Eric sold his house through an agent who charged 8% commission on the selling price. If Eric received $117,760.00 after the sale, what was the selling price of the house? 

Detalhes da Resposta

The commission charged by the agent is 8% of the selling price. This means that the remaining amount that Eric received after the sale is 92% of the selling price (100% - 8% = 92%). We can set up an equation to solve for the selling price: 92% of selling price = $117,760.00 To solve for the selling price, we can divide both sides by 92% (or multiply by the reciprocal of 92%, which is 100/92): selling price = $117,760.00 ÷ 0.92 Using a calculator, we get: selling price = $128,000.00 Therefore, the selling price of the house was $128,000.00.

In the diagram, PQ is parallel to RS, < QFG = 105\(^o\) and < FEG = 50\(^o\). Find the value of m.

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Find the angle at which an arc of length 22 cm subtends at the centre of a circle of radius 15cm.  [Take \(\pi = \frac{22}{7}\)]

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A rectangular board has a length of 15cm and width x cm. If its sides are doubled, find its new area.

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Let's first find the area of the original rectangular board, which is simply the product of its length and width: original area = 15 cm x x cm = 15x cm\(^2\) When the sides are doubled, the length becomes 15 cm x 2 = 30 cm, and the width becomes x cm x 2 = 2x cm. So, the new area is: new area = 30 cm x 2x cm = 60x cm\(^2\) So, the new area of the rectangular board is 60x cm\(^2\).

Which of these values would make \(\frac{3p^-}{p^{2-}}\) undefined? 

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An arc subtends an angle of 72\(^o\) at the centre of a circle. Find the length of the arc if the radius of the circle is 3.5 cm. [Take \(\pi = \frac{22}{7}\)]

Detalhes da Resposta

To find the length of the arc, we need to use the formula: Length of arc = \(\frac{\text{angle subtended by the arc}}{360^\circ} \times 2\pi r\) Here, the angle subtended by the arc is 72\(^o\) and the radius of the circle is 3.5 cm. We can substitute these values in the formula to get: Length of arc = \(\frac{72^\circ}{360^\circ} \times 2 \times \frac{22}{7} \times 3.5\) cm Simplifying this expression, we get: Length of arc = \(\frac{1}{5} \times \frac{44}{7} \times 3.5\) cm Length of arc = \(\frac{22}{5}\) cm Length of arc = 4.4 cm (approx.) Therefore, the length of the arc is 4.4 cm (option C).

In the diagram, PQ is parallel to RS, < QFG = 105\(^o\) and < FEG = 50\(^o\). Find the value of n

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If (0.25)\(^y\) = 32, find the value of y.

Detalhes da Resposta

We can solve the given equation by taking the logarithm of both sides. Any base of the logarithm can be used, but we will use the common logarithm (base 10). log\((0.25)^y\) = log 32 Using the logarithmic identity log\((a^b)\) = b log\((a)\), we get: y log\((0.25)\) = log 32 Now, we can evaluate log\((0.25)\) using the logarithmic identity log\((a^n)\) = n log\((a)\), as follows: log\((0.25)\) = log\((\frac{1}{4})\) = log\((4^{-1})\) = -log\((4)\) We know that log\((10^x)\) = x, so log\((4)\) = log\((10^{0.602})\) \(\approx\) 0.602 Therefore, y log\((0.25)\) = log 32 y (-log\((4)\)) = log 32 y (-0.602) = log 32 y = \(\frac{\text{log } 32}{-0.602}\) Using a calculator, we get: y \(\approx\) -2.5 Therefore, the value of y is approximately -2.5. Hence, the answer is: y = -\(\frac{5}{2}\).

If T = {prime numbers} and M = {odd numbers} are subsets of \(\mu\)  = {x : 0 < x ≤ 10} and x is an integer, find (T\(^{\prime}\) n M\(^{\prime}\)). 

Detalhes da Resposta

The set T is the set of prime numbers less than or equal to 10, which are {2, 3, 5, 7}. The prime complement (T\(\prime\)) is the set of non-prime numbers less than or equal to 10, which are {1, 4, 6, 8, 10}. The set M is the set of odd numbers less than or equal to 10, which are {1, 3, 5, 7, 9}. The odd complement (M\(\prime\)) is the set of even numbers less than or equal to 10, which are {2, 4, 6, 8, 10}. Finally, the intersection of T\(\prime\) and M\(\prime\) is the set of numbers that are both non-prime and even, which is {4, 6, 8, 10}. So (T\(\prime\) n M\(\prime\)) = {4, 6, 8, 10}.

Factorize completely; (2x + 2y)(x - y) + (2x - 2y)(x + y) 

Detalhes da Resposta

To factorize the given expression, we can use the distributive property of multiplication over addition. This means that we need to multiply each term in the first set of parentheses by each term in the second set of parentheses, and then simplify: (2x + 2y)(x - y) + (2x - 2y)(x + y) = 2x(x - y) + 2y(x - y) + 2x(x + y) - 2y(x + y) (using distributive property) = 2x^2 - 2xy + 2xy + 2y^2 + 2x^2 + 2xy - 2xy - 2y^2 (combining like terms) = 4x^2 - 4y^2 Therefore, the answer is 4(x - y)(x + y). Explanation: We can factorize the given expression by grouping the terms into two sets, each set containing two terms with a common factor. We can then factor out that common factor from each set, and simplify. In this case, we can factor out 2 from the first set of parentheses, and -2 from the second set of parentheses, giving us: 2(x + y)(x - y) - 2(x + y)(x - y) We can then combine the two sets of parentheses, giving us: (2(x + y) - 2(x - y))(x - y) Simplifying the expression inside the parentheses gives us: (2x + 2y - 2x + 2y)(x - y) Which further simplifies to: 4y(x - y) However, this is not the fully factored form, since we can factor out 4 from the expression to get: 4(x - y)(y) So the answer is 4(x - y)(y), which is equivalent to option A.

The following are scores obtained by some students in a test, Find the mode of the distribution  

Detalhes da Resposta

To find the mode of the distribution, we need to determine the value that appears most frequently in the dataset. Looking at the table, we can see that the value "13" appears three times, which is more than any other value. Therefore, the mode of this distribution is 13. Alternatively, we could create a frequency table or a histogram to visualize the distribution and identify the mode more easily.

If 2\(^{a}\) = \(\sqrt{64}\) and \(\frac{b}{a}\) = 3, evaluate a\(^2 + b^{2}\) 

Detalhes da Resposta

First, let's solve for a using the given equation 2\(^{a}\) = \(\sqrt{64}\). We know that \(\sqrt{64}\) is equal to 8, so we can substitute this value in the equation: 2\(^{a}\) = 8 To solve for a, we need to find the exponent that 2 is raised to in order to get 8. This exponent is 3, so a = 3. Next, we need to find the value of b. We are given that \(\frac{b}{a}\) = 3, so we can rearrange this equation to solve for b: b = 3a Substituting the value we found for a, we get: b = 3 x 3 = 9 Finally, we can evaluate a\(^2\) + b\(^2\) using the values we found for a and b: a\(^2\) + b\(^2\) = 3\(^2\) + 9\(^2\) = 9 + 81 = 90 Therefore, the answer is 90.

8, 18, 10,14, 18, 11, 13, 14, 13, 17, 15, 8, 16, and 13

The following are scores obtained by some students in a test. How many students scored above the mean score? 

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The interior angles of a polygon are 3x\(^o\), 2x\(^o\), 4x\(^o\), 3x\(^o\) and 6\(^o\). Find the size of the smallest angle of the polygon.

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If 7 + y = 4 (mod 8), find the least value of y, 10 \(\leq y \leq 30\) 

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In XYZ, |YZ| = 32cm, < YXZ 53\(^o\) and XZY = 90\(^o\). Find, correct to the nearest centimetre, |XZ|

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Express, correct to three significant figures, 0.003597. 

Detalhes da Resposta

To express 0.003597 correct to three significant figures, we need to round off the number to the third digit after the decimal point. The third digit after the decimal point is 7. Since 7 is greater than or equal to 5, we need to round up the second digit after the decimal point. Therefore, the third digit becomes zero. Hence, the rounded value of 0.003597 correct to three significant figures is 0.00360. Therefore, the answer is: 0.00360.

Simplify, correct to three significant figures, (27.63)\(^2\) - (12.37)\(^2\) 

Detalhes da Resposta

We can start by squaring each of the numbers in the expression: (27.63)\(^2\) = 762.9869 (12.37)\(^2\) = 153.4369 Now we can subtract the two squares: 762.9869 - 153.4369 = 609.55 Rounding the result to three significant figures, we get: 609.55 = 610 So (27.63)\(^2\) - (12.37)\(^2\) = 610.

The total surface area of a solid cylinder 165cm\(^2\). Of the base diameter is 7cm, calculate its height. [Take \(\pi = \frac{22}{7}\)]

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In the diagram, RT is a tangent to the circle at R, < PQR = 70\(^o\), < QRT = 52\(^o\), < QSR and < PRQ = x. Find the value of y. 

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If 3p = 4q and 9p = 8q - 12, find the value of pq.

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Evaluate: 2\(\sqrt{28} - 3\sqrt{50} + \sqrt{72}\)  

Detalhes da Resposta

To evaluate the expression 2\(\sqrt{28} - 3\sqrt{50} + \sqrt{72}\), we need to simplify the square roots first. \(\sqrt{28} = 2\sqrt{7}\) \(\sqrt{50} = 5\sqrt{2}\) \(\sqrt{72} = 2\sqrt{18} = 2\sqrt{9}\sqrt{2} = 6\sqrt{2}\) Now that we have simplified the square roots, we can substitute the values back into the expression: 2\(\sqrt{28} - 3\sqrt{50} + \sqrt{72}\) = 2 * 2\(\sqrt{7}\) - 3 * 5\(\sqrt{2}\) + 6\(\sqrt{2}\) = 4\(\sqrt{7}\) - 3 * 5\(\sqrt{2}\) + 6\(\sqrt{2}\) = 4\(\sqrt{7}\) - 15\(\sqrt{2}\) + 6\(\sqrt{2}\) = 4\(\sqrt{7}\) - 9\(\sqrt{2}\) So the expression evaluates to 4\(\sqrt{7}\) - 9\(\sqrt{2}\).

Evaluate: (0.064) - \(\frac{1}{3}\) 

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Solve 4x^{2}\) - 16x + 15 = 0.

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In the diagram, O is the centre of the circle of radius 18cm. If < zxy = 70\(^o\), calculate the length of arc ZY. [Take \(\pi = \frac{22}{7}\)]
 

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The following are scores obtained by some students in a test. Find the median score 
 

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If 23\(_y\) = 1111\(_{\text{two}}\), find the value of y

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Simplify: \(\frac{x^2 - 5x - 14}{x^2 - 9x + 14}\) 

Detalhes da Resposta

To simplify the fraction, we need to find a common denominator for the numerator and denominator. The denominator, \(x^2 - 9x + 14\), can be factored into the product of two binomials: \((x - 7)(x - 2)\). Now, to simplify the numerator, we can factor it as well: \(x^2 - 5x - 14 = (x - 7)(x + 2)\). With this factoring, we can cancel out the common factor of \(x - 7\) in the numerator and denominator, leaving us with the simplified fraction: \(\frac{x^2 - 5x - 14}{x^2 - 9x + 14} = \frac{(x - 7)(x + 2)}{(x - 7)(x - 2)} = \frac{x + 2}{x - 2}\). So the simplified fraction is.

From the top of a vehicle cliff 20m high, a boat at sea can be sighted 75m away and on the same horizontal position as the cliff. Calculate, correct to the nearest degree, the angle of depression of the boat from the top of the cliff. 

Detalhes da Resposta

The situation can be represented by the following diagram: ``` A /| / | 20m / | B---C 75m ``` Where A is the top of the cliff, B is the boat, and C is the point on the cliff directly above the boat. We want to find the angle of depression, which is the angle ACB. We can use trigonometry to find this angle. First, we need to find the length of AC. This is simply the height of the cliff, which is given as 20m. Next, we need to find the length of BC. This is the horizontal distance from the base of the cliff to the boat, which is given as 75m. Now we can use the tangent function to find the angle of depression: tan(ACB) = opposite / adjacent = 20 / 75 Taking the inverse tangent (or arctan) of both sides gives: ACB = arctan(20 / 75) = 15.02 degrees (to two decimal places) Therefore, the angle of depression of the boat from the top of the cliff is approximately 15 degrees (to the nearest degree). So the answer is option D: 15\(^o\).

Solve: \(\frac{y + 1}{2} - \frac{2y - 1}{3}\) = 4

Detalhes da Resposta

To solve this equation, we can start by simplifying both sides by finding a common denominator. \(\frac{y + 1}{2} - \frac{2y - 1}{3} = 4\) Multiplying the first term by 3 and the second term by 2 (the least common multiple of 2 and 3), we get: \(\frac{3(y+1)}{6} - \frac{2(2y-1)}{6} = 4\) Simplifying this gives: \(\frac{3y + 3 - 4y + 2}{6} = 4\) Combining like terms: \(\frac{-y + 5}{6} = 4\) Multiplying both sides by 6: \(-y + 5 = 24\) Subtracting 5 from both sides: \(-y = 19\) Finally, multiplying both sides by -1 to solve for y: \(y = -19\) Therefore, the solution is y = -19.

If m : n = 2 : 1, evaluate \(\frac{3m^2 - 2n^2}{m^2 + mn}\)

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Bala sold an article for #6,900.00 and made a profit of 15%. Calculate his percentage profit if he had sold it for N6,600.00. 

Detalhes da Resposta

If Bala sold an article for #6,900.00 and made a profit of 15%, this means that his cost price for the article was lower than the selling price by 15%. We can calculate his cost price as follows: Cost Price = Selling Price / (1 + Profit%) Cost Price = 6,900 / (1 + 0.15) Cost Price = 6,000 Therefore, Bala's cost price was #6,000.00, and he sold the article for #6,900.00, making a profit of #900.00. Now, we need to calculate the percentage profit he would have made if he sold the article for #6,600.00 instead of #6,900.00. To do this, we can use the following formula: Percentage Profit = (Profit / Cost Price) x 100% Percentage Profit = (6,600 - 6,000) / 6,000 x 100% Percentage Profit = 10% Therefore, if Bala had sold the article for #6,600.00 instead of #6,900.00, he would have made a profit of 10%. The correct option is 10%.

Evaluate: \(\frac{0.42 + 2.5}{0.5 \times 2.95}\), leaving the answer in the standard form.

Detalhes da Resposta

To solve this expression, we need to follow the order of operations which is parentheses, exponents, multiplication and division (from left to right), and addition and subtraction (from left to right). We do not have any parentheses or exponents, so we can proceed to the multiplication and division step. We have: \[\frac{0.42 + 2.5}{0.5 \times 2.95} = \frac{2.92}{1.475}\] Next, we can simplify the fraction by dividing both the numerator and denominator by the greatest common factor which is 0.05. \[\frac{2.92}{1.475} = \frac{292}{147.5}\] Finally, we can express this fraction in standard form by moving the decimal point in the numerator to the left by two places and simultaneously moving the decimal point in the denominator to the left by two places. \[\frac{292}{147.5} = 1.98\] Therefore, the answer is 1.639 x 10\(^1\) in standard form.

The foot of a ladder is 6m from the base of an electric pole. The top of the ladder rest against the pole at a point 8m above the ground. How long is the ladder? 

Detalhes da Resposta

To find the length of the ladder, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. In this case, the ladder is the hypotenuse, and the distance from the foot of the ladder to the pole and the height of the pole where the ladder is resting form the other two sides of the right triangle. So we have: Length of ladder^2 = (distance from foot of ladder to pole)^2 + (height of pole where ladder is resting)^2 Length of ladder^2 = 6^2 + 8^2 Length of ladder^2 = 36 + 64 Length of ladder^2 = 100 Length of ladder = √100 = 10 Therefore, the length of the ladder is 10 meters. Answer option C (10m) is correct.

In the diagram, POS and ROT re straight lines. OPOR is a parallelogram, |OS| = |OT| and

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There are 8 boys and 4 girls in a lift. What is the probability that the first person who steps out of the lift will be a boy? 

Detalhes da Resposta

The probability of an event happening is the number of ways it can happen divided by the total number of outcomes. In this case, there are 8 boys and 4 girls in the lift. If the first person who steps out of the lift is a boy, it means that any one of the 8 boys can be the first person to step out of the lift. Therefore, the number of ways the event can happen is 8. The total number of outcomes is the total number of people who can step out of the lift first. Since there are 12 people in the lift, any one of the 12 people can be the first person to step out of the lift. Therefore, the total number of outcomes is 12. Therefore, the probability that the first person who steps out of the lift will be a boy is: probability = number of ways the event can happen / total number of outcomes probability = 8 / 12 probability = 2 / 3 Hence, the answer is: \(\frac{2}{3}\).

If tan x = \(\frac{3}{4}\), 0 < x < 90\(^o\), evaluate \(\frac{\cos x}{2 sin x}\) 

Detalhes da Resposta

We are given that \(\tan x = \frac{3}{4}\) and \(0 < x < 90^o\). Since \(\tan x = \frac{\sin x}{\cos x}\), we can rewrite the given equation as: \[\frac{\sin x}{\cos x} = \frac{3}{4}\] Multiplying both sides by \(\cos x\) gives us: \[\sin x = \frac{3}{4}\cos x\] Dividing both sides by \(2\sin x\) gives us: \[\frac{\cos x}{2\sin x} = \frac{\frac{4}{3}\sin x}{2\sin x} = \frac{4}{3} \cdot \frac{1}{2} = \frac{2}{3}\] Therefore, the value of \(\frac{\cos x}{2\sin x}\) is \(\frac{2}{3}\). Hence, the answer is: \(\frac{2}{3}\).

A box contains 3 white and 3 blue identical balls. If two balls are picked at random from the box, one after the other with replacement, what is the probability that they are of different colours?

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The pie chart represents fruits on display in a grocery shop. If there are 60 oranges on display, how many apples are there?  
 

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A box contains 5 red, 6 green and 7 yellow pencils of the same size. What is the probability of picking a green pencil at random?

Detalhes da Resposta

There are 5 + 6 + 7 = 18 pencils in the box. Since there are 6 green pencils, the probability of picking a green pencil at random is 6/18, which simplifies to 1/3. Therefore, the answer is \(\frac{1}{3}\).

In the diagram, RT is a tangent to the circle at R, < PQR = 70\(^o\), < QRT = 52\(^o\), < QSR and < PRQ = x. Calculate the value of x.

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The fourth term of an Arithmetic Progression (A.P) is 37 and the first term is -20. Find the common difference.
 

Detalhes da Resposta

In an arithmetic progression (AP), the terms are equally spaced. Let's call the common difference "d". If we have the first term "a" and the nth term "an", we can find the common difference using the formula: d = (an - a) / (n - 1) In this case, the fourth term is 37 and the first term is -20, so we can plug in the values into the formula: d = (37 - (-20)) / (4 - 1) = 57 / 3 = 19 So the common difference is 19.

Simplify: \(\log_{10}\) 6 - 3 log\(_{10}\)  3 + \(\frac{2}{3} \log_{10} 27\)

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If log\(_x\) 2 = 0.3, evaluate log\(_x\) 8.

Detalhes da Resposta

We can use the property of logarithms that states: $$\log_{a}(b^c) = c \log_{a}(b)$$ Using this property, we can rewrite the expression for log\(_x\) 8 as: $$\log_{x}(8) = \log_{x}(2^3) = 3\log_{x}(2)$$ We are given that log\(_x\) 2 = 0.3, so we can substitute this value: $$3\log_{x}(2) = 3(0.3) = 0.9$$ Therefore, the value of log\(_x\) 8 is 0.9. Therefore, option (C) is the correct answer: 0.9.

Evaluate; \(\frac{\log_3 9 - \log_2 8}{\log_3 9}\) 

Detalhes da Resposta

We can use the laws of logarithms to simplify the expression: \(\frac{\log_3 9 - \log_2 8}{\log_3 9} = \frac{\log_3 (3^2) - \log_2 (2^3)}{\log_3 (3^2)}\) Using the laws of logarithms, we can simplify the numerator: \(\frac{\log_3 (3^2) - \log_2 (2^3)}{\log_3 (3^2)} = \frac{2\log_3 3 - 3\log_2 2}{2\log_3 3}\) We know that \(\log_3 3 = 1\) and \(\log_2 2 = 1\), so we can substitute these values: \(\frac{2\log_3 3 - 3\log_2 2}{2\log_3 3} = \frac{2 - 3}{2} = -\frac{1}{2}\) Therefore, the value of the expression is -\(\frac{1}{2}\).

Make b the subject of the relation lb = \(\frac{1}{2}\) (a + b)h

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Find the equation of a straight line passing through the point (1, -5) and having gradient of \(\frac{3}{4}\) 

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A survey of 40 students showed that 23 students study Mathematics, 5 study Mathematics and Physics, 8 study Chemistry and Mathematics, 5 study Physics and Chemistry and 3 study all the three subjects. The number of students who study Physics only is twice the number who study Chemistry only.

(a) Find the number of students who study:

(i) only Physics.

(ii) only one subject

b) What is the probability that a student selected at random studies exactly 2 subjects?
 

Detalhes da Resposta

a. (i) To find the number of students who study only Physics, we need to subtract the number of students who study Mathematics and Physics, and the number of students who study Physics and Chemistry from the total number of students who study Mathematics.

From the information given, 23 students study Mathematics, and 5 study Mathematics and Physics, so 23 - 5 = 18 students study Mathematics only.

The number of students who study Physics only is twice the number who study Chemistry only, so if x is the number of students who study Chemistry only, then 2x is the number of students who study Physics only.

(ii) To find the number of students who study only one subject, we need to add the number of students who study each subject only.

From the information given, 18 students study Mathematics only, x students study Chemistry only, and 2x students study Physics only, so 18 + x + 2x = 18 + 3x students study only one subject.

b. To find the probability that a student selected at random studies exactly 2 subjects, we need to find the number of students who study 2 subjects, and divide that by the total number of students (40).

From the information given, 8 students study Chemistry and Mathematics, and 5 students study Physics and Chemistry, so 8 + 5 = 13 students study 2 subjects.

The probability of selecting a student who studies exactly 2 subjects is 13/40.

(a) Solve the inequality: \(\frac{1 + 4x}{2}\) -\(\frac{5 + 2x}{7}\) < x -2

(b) If x: y = 3: 5, find the value of \(\frac{2x^2 - y^2}{y^2 - x^2}\)

Detalhes da Resposta

(a)

majority of the candidates multiplied through by the L.C.M which is 14 to arrive at

7(1+4x) - 2(5+2x) < 14(x - 2)

and when simplified yielded

10x < -25 x -212 $\frac{1}{2}$

(b)

it was expected that they express

x = 3y5 $\frac{3𝑦}{5}$ or y = 5x3 $\frac{5𝑥}{3}$ 

and thereafter, substitute into the given expression to have 

2x2−y2y2−x2=2x2−(5x3)2(5x3)2−x2=x(2−259)x2(259−1)

=−716

 A woman bought 130 kg of tomatoes for 4452,000.00. She sold half of the tomatoes at a profit of 30%. The rest of the tomatoes began to go bad, she then reduced the selling price per kg by 12%. Calculate:

(a) the new selling price per kg;

(ii) the percentage profit on the entire sales if she threw away 5 kg of bad tomatoes.

Detalhes da Resposta

(a) Let's first find the cost per kilogram of the tomatoes:

Cost per kilogram = Total cost / Total weight
Cost per kilogram = 4452,000.00 / 130 kg
Cost per kilogram = 34,246.15

Now let's find the selling price per kilogram for the first half of the tomatoes, which were sold at a 30% profit:

Profit = Selling price - Cost price
30% of Cost price = 0.3 * 34,246.15 = 10,273.85
Selling price = Cost price + Profit
Selling price = 34,246.15 + 10,273.85 = 44,520.00
Selling price per kilogram = Selling price / (130 kg / 2)
Selling price per kilogram = 44,520.00 / 65 kg
Selling price per kilogram = 684.92

Now let's find the new selling price per kilogram for the remaining tomatoes, which were sold at a 12% discount:

Discount = Selling price before discount - Selling price after discount
12% of Selling price before discount = 0.12 * Selling price before discount
Selling price after discount = Selling price before discount - 0.12 * Selling price before discount
Selling price after discount = 0.88 * Selling price before discount
Selling price per kilogram = Selling price after discount / (130 kg / 2)
Selling price per kilogram = 0.88 * Selling price before discount / (130 kg / 2)
Selling price per kilogram = 0.44 * Selling price before discount / 65
Selling price per kilogram = 0.44 * 684.92 / 65
Selling price per kilogram = 4.63

(ii) If 5 kg of tomatoes were thrown away, then the total weight sold would be 125 kg. Let's calculate the total revenue:

Revenue = Selling price per kilogram * Total weight sold
Revenue = (684.92 * 65 / 2) + (4.63 * 60)
Revenue = 22,303.80

The cost of the tomatoes was 4452,000.00, and since the revenue was less than that, there was a loss. Let's calculate the percentage loss:

Loss = Cost - Revenue
Loss = 4452,000.00 - 22,303.80
Loss = 4429,696.20
Percentage loss = (Loss / Cost) * 100
Percentage loss = (4429,696.20 / 4452,000.00) * 100
Percentage loss = 99.5%

So the percentage profit on the entire sales was -99.5%, which means there was a loss of 99.5%.

(a) Solve the inequality 13x?14(x+2)?3x?113 $\frac{\mathrm{<br>}}{}$

(b) 

In the diagram, ABC is right-angled triangle on a horizontal ground. |AD| is a vertical tower. < BAC = 90o ${}^{?}$, < ACB = 35o ${}^{?}$, < ABD = 52o ${}^{?}$ and |BC| = 66cm.

Detalhes da Resposta

13x−14(x+2)≥3x−113 $\frac{\mathrm{<br>}}{}$

13x−(x+2)12≥3x−43 $\frac{\mathrm{<br>}}{}$

4x−3x−612≥3x−43 $\frac{4𝑥-3𝑥-6}{12}\ge 3𝑥-\frac{4}{3}$

x−612≥3x1−43 $\frac{𝑥-6}{12}\ge \frac{3𝑥}{1}-\frac{4}{3}$

x−612≥9x−43 $\frac{𝑥-6}{12}\ge \frac{9𝑥-4}{3}$ 

3(x - 6) ≥ $\ge$ 12(9x - 4)

3x - 18 ≥ $\ge$ 108x - 48

3x - 108x ≥ $\ge$ -48 + 18

−105x−105≥−30−105 $\frac{-105𝑥}{-105}\ge \frac{-30}{-105}$ 

x ≥1035 $<br>\frac{\mathrm{<br>}}{}$

x 
$\ge$ 27

 27

(b)

(i) 

CB $𝐵$A = 108o ${}^{𝑜}$ - (90o ${}^{𝑜}$ + 35o ${}^{𝑜}$)

= 180o ${}^{𝑜}$ - 125o ${}^{𝑜}$ = 55o

sin35o ${}^{𝑜}$ = |AB|66 $\frac{|𝐴𝐵|}{66}$

|AB| = 66 x sin30o ${}^{𝑜}$ 

|AB| = 37.856m

cos 35o ${}^{𝑜}$ = |AC|66 $\frac{|𝐴𝐶|}{66}$

|AC| = 66 x cos35o ${}^{𝑜}$ 

|AC| = 55.06m

Tan52o ${}^{𝑜}$ = |AD|37.856 $\frac{|𝐴𝐷|}{37.856}$

|AD| = 37.856 x Tan52o ${}^{𝑜}$

= 48.45m the height of the tower to 2d.p

(ii)

Tan AC $𝐶$D = 48.45354.06

=0.8962

AC $𝐶$D = tan−1 ${}^{-1}$0.8962

= 41.867o ${}^{𝑜}$

Angle of elevation of the tower from

C = 35o ${}^{𝑜}$ + 41.867o ${}^{𝑜}$ 

= 76.87o ${}^{𝑜}$ to 2d.p

(a) The curved surface areas of two cones are equal. The base radius of one is 5 cm and its slant height is 12cm. calculate the height of the second cone if its base radius is 6 cm.

(b) Given the matrices A = \(\begin{pmatrix} 2 & 5 \\ -1 & -3 \end{pmatrix}\) and B = \(\begin{pmatrix} 3 & -2 \\ 4 & 1 \end{pmatrix}\), find:

  
(i) BA; 
(ii) the determinant of BA. 

Detalhes da Resposta

a) We can use the formula for the curved surface area of a cone, which is given by πrs, where r is the radius of the base and s is the slant height. Let's assume that the height of the second cone is h. Then we have:

π(5)(12) = π(6)(√(6^2 - h^2))

Simplifying the equation, we get:

60 = 6√(36 - h^2)

10 = √(36 - h^2)

Squaring both sides, we get:

100 = 36 - h^2

h^2 = 64

h = 8

Therefore, the height of the second cone is 8 cm.

b) (i) To find BA, we need to multiply the matrices in the order B x A. The product is given by:

BA = ∡(3 -2) (4 1) x (2 5) (-1 -3) = ∡(8 21) (7 17)

(ii) The determinant of a product of two matrices is equal to the product of their determinants, i.e., |AB| = |A||B|. Therefore, to find the determinant of BA, we can multiply the determinants of B and A. The determinant of a 2x2 matrix is given by the formula ad - bc, where a, b, c, and d are the elements of the matrix. Using this formula, we get:

|BA| = (8)(17) - (21)(7) = -49

Therefore, the determinant of BA is -49.

(a) Given that 110\(_x\) - 40\(_{five}\). find the value of x

(b) Simplify \(\frac{15}{\sqrt{75}} + \(\sqrt{108}\) + \(\sqrt{432}\), leaving the answer in the form a\(\sqrt{b}\), where a and b are positive integers.
 

Detalhes da Resposta

a) To find the value of x, we need to convert the numbers in the expression from different number systems to a common number system, in this case, base 10.

110_x is a number in base x, so to convert it to base 10, we need to evaluate the expression:

110_x = 1 * x² + 1 * x + 0 = x² + x

40_five is a number in base 5, so to convert it to base 10, we need to evaluate the expression:

40_five = 4 * 5¹ + 0 * 5⁰ = 20

So, the expression 110_x - 40_five becomes:

x² + x - 20 = 0

We can solve for x by using the quadratic formula or by factoring the equation.

Using the quadratic formula, we get:

x = (-1 ± √(1² - 4 * 1 * -20)) / (2 * 1)

x = (-1 ± √(1 + 80)) / 2

x = (-1 ± 9) / 2

So, the two solutions are:

x = (8 - 9) / 2 = -0.5

x = (8 + 9) / 2 = 8.5

Since x must be a positive integer, the only possible solution is x = 8.

b) To simplify the expression, we need to simplify each term inside the parenthesis separately.

First, we simplify the fraction:

15 / √75 = 15 / √(3² * 5²) = 15 / (3 * 5) = 15 / 15 = 1

Next, we simplify the square root terms:

√108 = √(2² * 3³) = √(2² * 3² * 3) = 3 * 3 = 9

√432 = √(2⁴ * 3³) = √(2² * 2² * 3³) = 6 * 3 = 18

So, the expression becomes:

1 + 9 + 18 = 28

Therefore, the simplified expression is 28, which is not in the form a√b where a and b are positive integers.

The data shows the marks obtained by students in a biology test

(a) Construct a frequency distribution table  using the class interval 0 - 9, 10 - 19, 19, 20, 29... 

(b) Draw a cumulative frequency curve for the distribution 

(c) Use the graph to estimate the;

(i) median

(ii) Percentage of students who scored at least 66 marks, correct to the nearest whole number.

Detalhes da Resposta

a)

b)

(c)

(i) Mean mark

= 49.9

(ii) Percentage of at least 66 mark

= 1350×100 $\frac{13}{50}\times 100$%

= 26%

The second, fourth and sixth terms of an Arithmetic Progression (AP.) are x - 1, x + 1 and 7 respectively. Find the:

(a) common difference;

(b) first term;

(c) value of x.

 

Detalhes da Resposta

An Arithmetic Progression (AP) is a sequence of numbers where the difference between any two consecutive terms is always the same. If a, b, c are three terms of an AP, then b - a = c - b. This common difference is denoted by d.

In this problem, we are given the second, fourth, and sixth terms of the AP as x - 1, x + 1, and 7 respectively. We can use these terms to find the common difference d and the first term a.

Let's call the first term a. Then, the second term a + d = x - 1, the fourth term a + 3d = x + 1, and the sixth term a + 5d = 7. We can use these equations to find d and a.

From the equation a + d = x - 1, we get d = x - 1 - a.

Substituting this in a + 3d = x + 1, we get a + 3(x - 1 - a) = x + 1
Expanding the brackets, we get a + 3x - 3 - 3a = x + 1
Combining like terms, we get -2a + 3x - 2 = x + 1
Solving for x, we get x = (2a + 2)/2

Substituting this value of x in d = x - 1 - a, we get d = (2a + 2)/2 - 1 - a = (2 - 2a)/2

Finally, substituting this value of d in a + 5d = 7, we get a + 5(2 - 2a)/2 = 7
Expanding the brackets, we get a + 5 - 5a = 7
Combining like terms, we get -4a + 5 = 7
Solving for a, we get a = 2.

So, the common difference d is 2 - 2a = 2 - 2 * 2 = -2, and the first term a is 2.

The value of x can be found from x = (2a + 2)/2 = (2 * 2 + 2)/2 = (4 + 2)/2 = 6/2 = 3.

Hence, the common difference is -2, the first term is 2, and the value of x is 3.

(a) Fred bought a car for $5,600.00 and later sold it at 90% of the cost price. He spent $1,310.00 out of the amount received and invested the rest at 6% per annum simple interest. Calculate the interest earned in 3 years.

(b) Solve the equations 2\(^x\)(4\(^{-7}\)) = 2 and 3\(^{-x}\)(9\(^{2y}\)) = 3 simultaneously.
 

Detalhes da Resposta

a) First, let's calculate the amount Fred received after selling the car. He sold the car for 90% of its cost price, so he received $5,600 * 0.9 = $5,040.00. After spending $1,310.00, he was left with $5,040 - $1,310 = $3,730.00. This is the amount he invested at 6% per annum simple interest.

The formula for simple interest is I = P * R * T, where I is the interest, P is the principal (the amount invested), R is the rate of interest (as a decimal), and T is the time (in years). Plugging in the values, we have I = $3,730 * 0.06 * 3 = $676.20.

So Fred earned $676.20 in interest over a period of 3 years.

b) To solve the equations 2^x(4^-7) = 2 and 3^-x(9^2y) = 3 simultaneously, we need to find the values of x and y that make both equations true.

Starting with the first equation, we can simplify the left-hand side to get 2^x * 4^-7 = 2^x * (1/16) = 2. We can then divide both sides of the equation by 2^x to get (1/16) = 1. Since this is not true, there are no values of x that make this equation true.

Next, let's simplify the second equation to get 3^-x * 9^2y = 3^-x * 81^y = 3. Dividing both sides of the equation by 3^-x gives us 81^y = 3^x. Taking the log base 3 of both sides gives us y = x.

So the only solution for x and y is x = y = 1.

In conclusion, there is only one solution for the system of equations, x = y = 1.

The force of attraction F, between two bodies, varies directly as the product of their masses, \(m_1\) and m\(_2\) and inversely as the square of the distance, d, between them. Given that F = 20N, when m\(_1\) = 25kg, m\(_2\) = 10kg and d = 5m, find:

(I) an expression for F in terms of m\(_1\), m\(_2\) and d;

(ii) the distance, d for F = 30N, m\(_1\) = 7.5kg and m\(_2\) = 4kg

(b) Find the value of x in the diagram

Detalhes da Resposta

(I) To find the expression for F in terms of m₁, m₂, and d:

We can use the formula for direct variation and inverse variation:

F ∝ (m₁ m₂) / d²

where k is a constant of proportionality. To find the value of k, we can use the given values:

20 = k (25 x 10) / (5²)

Simplifying this equation gives:

k = 4

Therefore, the expression for F in terms of m₁, m₂, and d is:

F = 4(m₁ m₂) / d²

(ii) To find the distance, d, for F = 30N, m₁ = 7.5kg, and m₂ = 4kg:

We can use the expression we found in part (i):

30 = 4(7.5 x 4) / d²

Simplifying this equation gives:

d² = (4 x 7.5 x 4) / 30

d² = 4

Taking the square root of both sides gives:

d = 2 meters

Therefore, the distance between the two bodies is 2 meters.

(b) In the diagram:

We can see that there are two right triangles that share a common side, which is x. The two triangles have sides of length 3 and 4, and sides of length 5 and x.

Since these are right triangles, we can use the Pythagorean theorem:

3² + 4² = 5² + x²

Simplifying this equation gives:

9 + 16 = 25 + x²

25 = x²

Taking the square root of both sides gives:

x = 5

Therefore, the value of x in the diagram is 5.

The cost of dinner for a group of tourist is partly constant and partly varies as the number of tourists present. It costs $740.00 when 20 tourists were present and $960.00 when the number of tourists increased by 10. Find the cost of the dinner when only 15 tourists were present.
 

Detalhes da Resposta

Let's call the constant cost of dinner "C". When there were 20 tourists, the total cost was $740.00, so we can write an equation to find the value of C:

C + 20 * (variable cost per tourist) = $740.00

When the number of tourists increased by 10, the total cost became $960.00, so we can write another equation using this information:

C + 30 * (variable cost per tourist) = $960.00

Now we have two equations with two unknowns (C and the variable cost per tourist), so we can use substitution to solve for one of the unknowns.

Subtracting the first equation from the second equation, we get:

10 * (variable cost per tourist) = $960.00 - $740.00 = $220.00

So, the variable cost per tourist is $22.00. Now we can use this value to find the constant cost of dinner, C:

C + 20 * $22.00 = $740.00

C = $740.00 - 20 * $22.00 = $140.00

Finally, we can use the constant cost of dinner and the variable cost per tourist to find the total cost of dinner when there were 15 tourists:

Total cost = C + 15 * (variable cost per tourist) = $140.00 + 15 * $22.00 = $340.00

So, the cost of dinner for 15 tourists was $340.00.

(a)

In the diagram. \(\over{Rs}\) and \(\over{RT}\) are tangent to the circle with centre O, < TUS = 68\(^o\), < SRT = x and < UTO  = y. Find the value of x.

(b) Two tanks A and B are filled to capacity with diesel. Tank A holds 600 litres diesel more than tank B. If 100 litres of diesel was pumped cut of each tank, tank A would then contain 3 times as much as tank B. Find the capacity of each tank.