If the fundamental frequency of a closed pipe organ on a day when the speed of sound is 340ms-1 is 170Hz, then the length of the pipe is

If the fundamental frequency of a closed pipe organ on a day when the speed of sound is 340ms-1 is 170Hz, then the length of the pipe is

Answer Details

$\lambda$ = $\frac{v}{f}$

= $\frac{340}{170}$

= 2m ; for closed pipe

L = $\frac{1}{4}$$\lambda$

= $\frac{1}{4}$ x $\frac{2}{1}$

= 0.5m

= 50cm