JAMB UTME - Physics - 2014

Calculate the escape velocity of a satellite launched from the earth's surface if the radius of the earth is 6.4x106m

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Escape velocity is the minimum velocity required by an object to escape the gravitational pull of a planet or a star. To calculate the escape velocity from Earth's surface, we can use the formula: v = sqrt(2GM/R) where v is the escape velocity, G is the universal gravitational constant, M is the mass of the Earth, and R is the radius of the Earth. Plugging in the values, we get: v = sqrt(2 x 6.67 x 10^-11 x 5.97 x 10^24 / 6.4 x 10^6) v = sqrt(2 x 9.82 x 10^7) v = sqrt(1.96 x 10^8) v = 1.4 x 10^4 m/s Converting this into kilometers per second, we get: v = 14 km/s Therefore, the correct option is "11.3kms^-1".

The maximum power transfer occur in a cell when the external resistance is

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When we talk about a cell, it has some internal resistance, which is the resistance that opposes the flow of current within the cell. The external resistance is the resistance outside the cell that allows the flow of current. The power transfer from a cell to the external circuit is at its maximum when the external resistance is equal to the internal resistance of the cell. This is because the maximum power transfer theorem states that the maximum power will be transferred from a source to a load when the resistance of the load is equal to the internal resistance of the source. When the external resistance is equal to the internal resistance, the maximum current flows through the circuit, resulting in maximum power transfer. If the external resistance is less than the internal resistance, then the current would be too high, leading to internal heating and reduced power transfer. If the external resistance is greater than the internal resistance, then the current would be too low, leading to reduced power transfer. Therefore, the correct answer to the question is: "The same as the internal resistance of the cell."

A glass bottle of initial volume 2 x 104 cm3 is heated from 20oC to 50oC. If the linear expansivity of glass is 9 x 106K-1, the volume of the bottle at 50oC is

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The correct answer is 20013.5cm3. When a solid or liquid is heated, it usually expands in volume. This expansion can be quantified using the coefficient of linear or volumetric expansion. In this problem, we are given the linear expansivity of glass, which tells us how much the length of a glass object changes for each degree of temperature change. To solve this problem, we can use the formula: ΔV = V₀αΔT where: ΔV is the change in volume V₀ is the initial volume α is the coefficient of linear expansion ΔT is the change in temperature Substituting the given values, we get: ΔV = (2 x 10^4 cm^3)(9 x 10^-6 K^-1)(50°C - 20°C) ΔV = 6 cm^3 The final volume of the bottle is: V = V₀ + ΔV = 2 x 10^4 cm^3 + 6 cm^3 = 20006 cm^3 However, we need to remember that the answer is given to one decimal place, so we round our answer to the nearest tenth: V ≈ 20013.5 cm^3 Therefore, the volume of the bottle at 50°C is 20013.5 cm^3.

The melting point of a substance is equivalent to its

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The sentence is stating that there is a relationship between the melting point of a substance and some other property that is not specified in the given sentence. The sentence is asking to complete this relationship. The correct option that completes this relationship is "Solidification Temperature". The melting point of a substance is the temperature at which it transitions from a solid state to a liquid state. Similarly, the solidification temperature of a substance is the temperature at which it transitions from a liquid state to a solid state. These two temperatures are the same for a given substance, which means that the melting point of a substance is equivalent to its solidification temperature. Therefore, the correct completion of the sentence would be: "The melting point of a substance is equivalent to its Solidification Temperature." The other options provided in the question do not complete this relationship and are therefore incorrect.

In a compound microscope, the objective and the eye piece focal lengths are

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In a common emitter configuration, the output voltage is through the

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A boy receives the echo of his clap reflected by a nearby hill 0.8s later. How far is he from the hill?

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Time for echo both ways = 0.8
Therefore time for echo in 1 way = 0.8/2 = 0.4

Distance = Speed x time

Distance = 340 x 0.4

Distance = 136m

The temperature at which the water vapour present in the air is just sufficient to saturate air is

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The temperature at which the water vapor present in the air is just sufficient to saturate the air is called the dew point. When the air is saturated with water vapor, it can no longer hold any more water vapor, and the excess water vapor condenses into tiny droplets, which form dew on surfaces such as grass, leaves, and windows. The dew point varies depending on the amount of moisture in the air. Higher humidity levels in the air will lead to a higher dew point, while lower humidity levels will lead to a lower dew point. In summary, the dew point is the temperature at which the air becomes saturated with water vapor, and any additional water vapor will condense into dew.

An object is placed 10m from a pinhole camera of length 25cm. Calculate the linear magnification.

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$\text{Linear Magnification}=\frac{\text{Length of Camera}}{\text{Distance of the Object}}$

$\text{Linear Magnification}=\frac{25}{1000}$

$\text{Linear Magnification}=2.5\times {10}^{-2}$

An object of mass 20kg is released from a height of 10m above the ground level. The kinetic energy of the object just before it hits the ground is

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The kinetic energy of the object just before it hits the ground is 2000J. We can use the principle of conservation of energy to solve this problem. When the object is released from a height of 10m above the ground level, it has gravitational potential energy which is given by: PE = mgh where: m is the mass of the object g is the acceleration due to gravity h is the height of the object above the ground level Substituting the given values, we get: PE = (20 kg)(9.8 m/s^2)(10 m) = 1960 J As the object falls towards the ground, its potential energy is converted into kinetic energy. At the point just before it hits the ground, all of its potential energy will have been converted into kinetic energy. The kinetic energy is given by: KE = 1/2 mv^2 where: m is the mass of the object v is the velocity of the object To find the velocity of the object just before it hits the ground, we can use the principle of conservation of energy again. The total energy of the system (object + Earth) is conserved, so the potential energy at the top of the fall is equal to the sum of the kinetic and potential energies just before impact. Therefore, we can write: PE at the top = KE just before impact + PE just before impact We know that the PE at the top is equal to 1960 J, and the PE just before impact is zero (since the object is at ground level). Therefore: 1960 J = 1/2 (20 kg) v^2 Solving for v, we get: v = √(2(1960 J)/(20 kg)) = 20 m/s Substituting the value of v into the equation for kinetic energy, we get: KE = 1/2 (20 kg) (20 m/s)^2 = 2000 J Therefore, the kinetic energy of the object just before it hits the ground is 2000 J.

PHCN measures its electrical energy in

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The PHCN, or Power Holding Company of Nigeria, measures its electrical energy in kilowatt-hours (KWh). This is a unit of energy that is commonly used to measure the amount of electricity that is consumed or generated over a period of time. A kilowatt-hour is equivalent to the amount of energy consumed or generated by a one kilowatt power source in one hour. So, by measuring the electrical energy in kilowatt-hours, PHCN can keep track of how much electricity is being used by its customers and bill them accordingly.

A car accelerates uniformly from rest at 3ms-2. its velocity after traveling a distance of 24m is

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V2 = U2 x 2ax
V2 = 0 x 2(3)(24)
V2 = 144
V = $\sqrt{144}$
V = 12ms-1

What is the equivalent of 20K in Celsius scale?

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273 + 20 = 293

Heat transfer by convection in a liquid is due to the

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The quantity of heat needed to raise the temperature of a body by 1K is the body's

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When ${}_{82}^{210}Pb$ decays to ${}_{80}^{206}Pb$

, it emits        

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When 21082Pb decays to 20680Pb, it emits one alpha particle. This is because alpha decay involves the emission of an alpha particle, which is a helium nucleus consisting of two protons and two neutrons. During alpha decay, the atomic nucleus of the parent atom loses two protons and two neutrons, resulting in a new atom with a mass number that is four units less and an atomic number that is two units less than the parent atom. In this case, 21082Pb has a mass number of 210 and an atomic number of 82, while 20680Pb has a mass number of 206 and an atomic number of 80. Therefore, during the decay process, 21082Pb emits an alpha particle, which reduces the mass number by four to 206 and the atomic number by two to 80, resulting in the formation of 20680Pb.

A machine whose efficiency is 75% is used to lift a load of 1000N. Calculate the effort put in to the machine if it has a Velocity ratio of 4.

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$\frac{MA}{VR}\times \frac{100}{1}=efficiency$

$\frac{L}{E}\frac{1}{VR}\times \frac{100}{1}=75$

$\frac{1000}{E}\frac{1}{4}\times \frac{100}{1}=75$

$E=\frac{250\times 100}{75}$

E = 333.3N

The distance between two successive crests of a wave is 15cm and the velocity 300ms-1. Calculate the frequency.

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The formula to calculate frequency is: frequency = velocity / wavelength where wavelength is the distance between two successive crests of a wave. In this problem, the wavelength is given as 15cm or 0.15m, and the velocity is given as 300ms^-1. Substituting these values in the formula, we get: frequency = 300 / 0.15 = 2000 Hz Therefore, the frequency of the wave is 2.0x10^3 Hz. Answer: 2.0x103Hz

A circuit has a resistance of 200?. The resistance of the circuit can be reduced to 120? when

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When resistors are connected in series, their total resistance is equal to the sum of their individual resistances. Therefore, adding an 80Ω resistor in series with the 200Ω circuit will result in a total resistance of 280Ω. On the other hand, when resistors are connected in parallel, their total resistance is given by the formula: 1/R_total = 1/R1 + 1/R2 + 1/R3 + ... Therefore, adding a 300Ω resistor in parallel with the 200Ω circuit will result in a total resistance of: 1/R_total = 1/200 + 1/300 = 5/600 R_total = 600/5 = 120Ω Therefore, the correct option is "a 300Ω resistor is connected to it in parallel", which will reduce the resistance of the circuit from 200Ω to 120Ω.

The energy in the nucleus of atoms produce heat which can be used to generate

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An object of weight 80kg on earth is taken to a planet where acceleration due to gravity is one-third of its value on earth. The weight of the object on the planet is

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The focal length of a concave mirror is 2.0cm. If an object is placed 8.0cm from it, the image is at

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$\frac{1}{U}+\frac{1}{V}=\frac{1}{f}$

$\frac{1}{8}+\frac{1}{V}=\frac{1}{2}$

$V=\frac{8}{3}$

$V=2.7cm$

What charge is stored in a 0.1F capacitor when a 10V supply is connected across it?

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A capacitor is an electronic component that stores electrical charge. The amount of charge stored by a capacitor depends on its capacitance and the voltage applied across it. In this case, a 0.1F capacitor is connected to a 10V supply. The capacitance of the capacitor is 0.1F, which means it can store 0.1 coulombs of charge per volt. So, the amount of charge stored by the capacitor can be calculated by multiplying the capacitance by the voltage applied across it: Charge stored = capacitance x voltage = 0.1F x 10V = 1 coulomb Therefore, the answer is 1C. The capacitor will store 1 coulomb of charge when a 10V supply is connected across it.

Which gas produces a pink coloured light in a discharge tube?

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What is the least possible error encountered when taking measurement with a meter rule?

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The least possible error encountered when taking measurements with a meter rule depends on the precision of the instrument being used. A typical meter rule has divisions of 1 mm, which means that the smallest distance that can be measured is 1 mm. However, with careful estimation, it may be possible to estimate the position of the edge of an object to within half a division, or 0.5 mm. Therefore, the least possible error encountered when taking measurements with a meter rule is 0.5 mm. Hence, the correct option is 0.5mm.

When an atom undergoes a beta decay, the atomic number of the nucleus

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When an atom undergoes a beta decay, the atomic number of the nucleus increases by one. This is because in beta decay, a neutron in the nucleus decays into a proton, an electron, and an antineutrino. The proton remains in the nucleus and increases the atomic number, while the electron and antineutrino are emitted from the nucleus. So, the number of protons in the nucleus increases by one, which means the atomic number increases by one.

Calculate the mass of the copper deposited during electrolysis when a current of 4A passes through a copper salt for 2 hours. [Ece of Copper z=3.3x10-7kgC-1]

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Mass = ZIT kg
Mass = 3.3 x 10-7 x 4 x 2 x 60 x 60 kg
Mass = 9.5 x 10-3kg

When a telescope is in normal use, the final image is at

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Which type of motion do the wheels of a moving car undergo?

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The wheels of a moving car undergo both translational and rotational motion. Translational motion refers to the motion of an object in a straight line, such as the forward motion of the car. Rotational motion refers to the spinning of the wheel around its axis, which is necessary for the car to move forward. Together, these two motions allow the wheels to propel the car forward.

The magnitude of the angle of dip at the equator is

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The angle of dip, also known as the magnetic inclination, is the angle between the horizontal plane and the total magnetic field vector at a particular location on Earth. At the equator, the angle of dip is zero degrees because the magnetic field lines run parallel to the Earth's surface at this location. This means that there is no component of the magnetic field vector that points vertically downwards, so the angle of dip is zero. Therefore, the correct answer is option B: 0 Deg.

I Electrical potential, II Torque, III Kinetic Energy, IV Momentum. Which of the quantities listed are vectors?

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Vectors are physical quantities that have both magnitude and direction. Scalars, on the other hand, are quantities that have only magnitude and no direction. Of the four quantities listed, torque and momentum are vectors, while electrical potential and kinetic energy are scalars. Torque is a measure of the force that causes an object to rotate around an axis or pivot point. It has both magnitude and direction, as it depends on the position and orientation of the object and the direction of the applied force. Momentum is a measure of an object's motion, and it has both magnitude and direction, as it depends on the object's mass and velocity. Electrical potential is a scalar quantity that represents the amount of energy required to move an electric charge from one point to another in an electric field. It has only magnitude and no direction. Kinetic energy is also a scalar quantity that represents the energy an object possesses due to its motion. It is determined by the mass and speed of the object and has only magnitude. Therefore, the correct answer is (A) II and IV, as torque and momentum are the only vector quantities listed.

If a metal wire 4m long and cross-sectional area 0.8 mm2 has a resistance of 60, find the resistivity of the wire

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The resistivity of a material is a measure of how much it resists the flow of electrical current through it. It is given by the formula: ρ = RA/L where ρ is the resistivity, R is the resistance, A is the cross-sectional area of the wire, and L is the length of the wire. In this problem, we are given the length, cross-sectional area, and resistance of the wire. So we can rearrange the formula to solve for the resistivity: ρ = RA/L = (R x A)/L Substituting the given values, we get: ρ = (60 Ω x π x (0.8 mm)^2) / (4 m) Simplifying this expression, we get: ρ = 1.2 x 10^-6 Ω m Therefore, the resistivity of the wire is 1.2 x 10^-6 Ω m. So the correct option is: - 1.2x10^-6

The small droplets of water that form on the grass in the early hours of the morning is

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The small droplets of water that form on the grass in the early hours of the morning is called "dew". Dew is formed when the ground and the air close to the ground cool down at night, causing water vapor in the air to condense into tiny droplets on surfaces like grass, leaves, and flowers. The droplets are most visible at dawn, before the sun has had a chance to evaporate them. Dew is important for plants because it provides moisture for them to absorb through their leaves and roots.

One of the conditions necessary for an object to be in equilibrium when acted upon by a number of parallel forces is that the vector sum of the forces is

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A quantity which requires magnitude and direction to be specified is

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The quantity which requires magnitude and direction to be specified is displacement. Displacement refers to the distance between an object's initial position and its final position. It is a vector quantity because it has both magnitude (the distance between the initial and final position) and direction (the direction from the initial position to the final position). For example, if a car travels 10 kilometers north and then 5 kilometers east, its displacement would be the straight-line distance from its starting point to its ending point, which would be the square root of (10^2 + 5^2) = 11.18 kilometers, at an angle of approximately 26.6 degrees north of east. In contrast, distance, temperature, and mass are scalar quantities that only require magnitude to be specified, not direction. Distance refers to the total amount of space covered by an object, temperature is the degree of hotness or coldness of a body, and mass refers to the amount of matter in an object.

A wheel and an axle is used to raise a load whose weight is 800N when an effort of 250N is applied. If the radii of the wheel and axle are 800mm and 200mm respectively, the efficiency of the machine is

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VR = 800/200 = 4
$Efficiency=\frac{MA}{VR}\times \frac{100}{1}$

$Efficiency=\frac{L}{E}\times \frac{1}{VR}\times \frac{100}{1}$

$Efficiency=\frac{800}{250}\times \frac{1}{4}\times \frac{100}{1}$

= 78.74%
= 80%

What is the best method of demagnetizing a steel bar magnet?

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Demagnetization is the process of removing the magnetic field from a magnet. This can be done in various ways, but the best method of demagnetizing a steel bar magnet is by using the solenoid method. The solenoid method involves using a coil of wire called a solenoid. When an alternating current is passed through the solenoid, it creates a changing magnetic field. By placing the steel bar magnet inside the solenoid and gradually reducing the current, the magnetic field of the magnet is gradually reduced until it becomes demagnetized. This method is considered the best because it is a controlled and gradual process that does not damage the magnet. Hammering or rough handling the magnet can cause physical damage to it, and heating it can actually make the magnet stronger due to the alignment of the magnetic domains within the magnet. Therefore, if you need to demagnetize a steel bar magnet, the best method is to use the solenoid method.

What type of reaction is represented by the equation ${}_1^{2}X{+}_1^{2}X{\to }_2^{3}Y{+}_0^{1}n+Energy$

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When a negatively charged rod is brought near the cap of a charged gold leaf electroscope which has positive charges, the leaf

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When a negatively charged rod is brought near the cap of a charged gold leaf electroscope which has positive charges, the electrons in the gold leaf are repelled by the negatively charged rod. As a result, the electrons move away from the cap of the electroscope, and this causes the gold leaf to become negatively charged. The negatively charged gold leaf is then attracted to the positively charged cap of the electroscope, causing the gold leaf to collapse towards the cap. Therefore, the correct option is "collapses". If the negatively charged rod is removed, the electrons in the gold leaf return to their original positions and the gold leaf returns to its original state. However, if the negatively charged rod is brought close to the electroscope again, the same process will repeat, and the gold leaf will collapse towards the cap again. Therefore, the option "collapses and diverges again" is also correct, but it is not the immediate response to the presence of the negatively charged rod. In summary, when a negatively charged rod is brought near the cap of a charged gold leaf electroscope which has positive charges, the gold leaf collapses towards the cap due to the repulsion of electrons in the gold leaf.

What happens when three coplanar non-parallel forces are in equilibrium?

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Conditions for non-parallel coplanar forces

A force of 500N1 is applied to a steel wire of cross-sectional area 0.2m2, The tensile stress is

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$Stress=\frac{Force}{Area}$

$Stress=\frac{500}{0.2}=2500$

= 2.5 x 103Nm-3

The equation PaVbTc= constant reduces to Charles Law if

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if a=0, b=1 and c=-1 then
P0V1T-1 = V/T (Charles Law)